How to order by higher id sql - php

Question

I have rows in MYSQL.
They are basically articles and rumours based on user input. In my query, i would like the table created to have the later results ranked higher. How would that Order By Query work?
$query = "SELECT * FROM rumours";
$query.= "ORDER BY"
$query = mysql_query($query) or die('MySQL Query Error: ' . mysql_error( $connect ));
while ($row = mysql_fetch_assoc($query)) {
$id = $row['id'];
$band = $row['band'];
$title = $row['Title'];
$description = $row['description'];
echo "<table border='1'>";
echo "<tr>";
echo "<td> $title </td>";
echo "</tr>";
echo "<tr>";
echo "<td class = 'td1'> $description </td>";
echo "</tr>";
echo "</table>";
}

Answer 1

Few things regarding your snippet.
Use a column list and avoid selecting *
mysql_ functions are being deprecated. You should use either mysqli_ or PDO functions.
You can save yourself time by calling your columns directly, rather than reassigning them variables.
When you are asking for the older records to display first, what is the criteria for this? Does a higher id mean the record is newer? I've assumed this in my answer.
Here's an improved version of your code using mysqli_:
$link = mysqli_connect("localhost", "user", "pass", "db");
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$q = "SELECT id, band, Title, description FROM rumours ORDER BY id DESC";
$result = mysqli_query($link, $q);
while($row = mysqli_fetch_array($result, MYSQLI_BOTH)) {
echo "<table border='1'>";
echo "<tr>";
echo "<td>" . $row[id] . "</td>";
echo "</tr>";
echo "<tr>";
echo "<td class = 'td1'>" . $row[description] . "</td>";
echo "</tr>";
echo "</table>";
}
mysqli_free_result($result);