Say how many items are the same in 2 arrays? - php

Question

Is there a way within PHP and MySQL to be able to compare 2 different array (list) variables and say how many items are the same
For example,
$array1 = "hello, bye, google, laptop, yes";
$array2 = "google, bye, windows, no, phone";
Then an echo statement would say how many items are the same. In this example, it would be 2 and this would be echoed.
This is different to most array questions because of the way my site is set up using commas which can make it quite complicated

Answer 1

Try array_intersect() function in php
<?php
$array1 = array("a" => "green", "red", "blue");
$array2 = array("b" => "green", "yellow", "red");
$result = array_intersect($array1, $array2);
print_r(count($result));
?>
You can count elements in the output array using count() function,
doc link

Answer 2

$array_new1 = explode(',',$array1);
$array_new2 = explode(',',$array2);
$array_1 = array_map('trim', $array_new1);
$array_2 = array_map('trim', $array_new2);
$data =array();
foreach($array_2 as $value){
if(in_array($value,$array_1)){
$data[] = $value;
}
}
echo count($data);

Answer 3

First you have to convert your string to array with trim. Then use
array_intersect to get common values.
$array1 = "hello, bye, google, laptop, yes";
$array2 = "google, bye, windows, no, phone";
$array_new1 = array_map('trim', explode(',', $array1));
$array_new2 =array_map('trim', explode(',', $array2));
$common = array_intersect($array_new1, $array_new2);
print_r($common);
echo count($common);