What I have
$array1 = [1,1,1];
$array2 = [1,1];
What I'm doing:
array_diff( $array1, $array2 );
What I expected:
array(1) { 1 }
What I got
array(0) { }
How do I subtract two arrays to get every discrepancy?
Edit:
My example was incomplete, sorry.
If we also have values like this:
$array1 = [1,1,2,1];
$array2 = [1,1,1,2];
I would expect
[1,1,2,1] - [1,1,1,2] = []
array_diff_assoc() is the right way to go here. But to get your expected result you just have to sort the array first with usort() where I compare the values with strcasecmp().
So this should work for you:
<?php
$array1 = [1,1,2,1];
$array2 = [1,1,1,2];
function caseCmpSort($a, $b){
return strcasecmp($a, $b);
}
usort($array1, "caseCmpSort");
usort($array2, "caseCmpSort");
$result = array_diff_assoc($array1, $array2);
print_r($result);
?>
output:
Array ( )
use array_diff_assoc
$array1 = [1,1,1];
$array2 = [1,1];
print_r(array_diff_assoc( $array1, $array2)); // outputs Array ([2] => 1)
try it here http://sandbox.onlinephpfunctions.com/code/43394cc048f8c9660219e4fa30386b53ce4adedb
So you should check array key differences too. Have you tried array_diff_assoc()?
http://php.net/manual/en/function.array-diff-assoc.php
From manual:
Returns an array containing all the entries from array1 that are not present in any of the other arrays.
So, it is working as expected. I am not sure what exactly You want to achieve. You cloud try, it should give You expected result in this example.
$a = [1,1,1];
$b = [1,1];
print_r(array_diff_assoc($a,$b));
Edit: Well, simple sort should solve issue from Your comment. Nothe, that this will remove information of original indexes of elements.
$a = [1,1,2,1];
$b = [1,1,1,2,1];
sort($a);
sort($b);
print_r(array_diff_assoc($a,$b));
<?php
$n = array(1,1,1);
$m = array(1,1);
$r = array_diff_assoc($n,$m);
var_dump($r);
?>
Related
I have two array inputs like this :
$array1 = [1,2,3,4,6];
$array2 = [1,3];
$output = array_merge(array_diff($array1,$array2),array_diff($array2,$array1));
Now I want to check array1 with array 2 and eliminate 1 and 3 in $array1
and the output I am expecting is
$output = [2,4,6];
but in this method I get some bugs, when array2 have single value e.g.: $array2 = [1]; , $array1 = [1,2,3,4,6]; the output should be $output = [2,3,4,6];. But I am getting $array1 all values [1,2,3,4,6];
Simple :)
(Just un-complicate your code and you don't need anything new for that)
<?php
$array1 = array(1,2,3,4,6);
$array2 = array(1,3);
$result = array_diff($array1, $array2);
print_r($result);
?>
Demo
In Your style it can even be a one liner :P
<?php print_r(array_diff(array(1,2,3,4,6), array(1,3))); ?>
$arr1 = array('potato'=>1,'tomato'=>2,'apple'=>5,'banana'=>10);
$arr2 = array('orange'=>20,'tomato'=>3,'apple'=>5,'banana'=>20);
I need function that would return array('tomato','banana'), consider that it omits keys that don't exist in one or the other array. Apple has the same value in both arrays, so it should be omitted - returned should be only keys whose values differ and are set
This should work (demo):
$arr1 = array('potato'=>1,'tomato'=>2,'apple'=>5,'banana'=>10);
$arr2 = array('orange'=>20,'tomato'=>3,'apple'=>5,'banana'=>20);
$result = array_keys(array_diff(array_intersect_key($arr1, $arr2), $arr2));
print_r($result);
Output:
Array
(
[0] => tomato
[1] => banana
)
Reference:
array_intersect_key — Computes the intersection of arrays using keys for comparison
array_diff — Computes the difference of arrays
array_keys — Return all the keys or a subset of the keys of an array
$array3 = array();
foreach(array_intersect_key($array1, $array2) as $key => $v){
if($array1[$key] != $array2[$key]) $array3[] = $key;
}
<?php
/**
* Returns an array which contains keys which are in both $array1
* and $array2, and which have different values.
*/
function getKeysWhichMatchAndHaveDifferentValues($array1, $array2)
{
$arrIntersected = array_intersect_key($array1, $array2);
foreach($arrIntersected as $key => $value)
{
if($array2[$key] == $value) {
unset($arrIntersected[$key]);
}
}
return array_keys($arrIntersected);
}
$arr1 = array('potato'=>1,'tomato'=>2,'apple'=>5,'banana'=>10);
$arr2 = array('orange'=>20,'tomato'=>3,'apple'=>5,'banana'=>20);
$final = getKeysWhichMatchAndHaveDifferentValues($arr1, $arr2);
echo '<pre>' . print_r($final) . '</pre>';
?>
I would do simple loop.
Of course if you will need to compare large arrays, the native PHP functions could help a lot. Still can't answer right now what would be the most optimal way to do this.
You could do this using array_intersect and array_keys.
$arr3 = array_intersect(array_keys($arr1), array_keys($arr2));
I have 2 arrays, the value will be loaded from database, below is an example:
$arr1 = array(1,2,3);
$arr2 = array(1,2,3,4,5,6,7);
What I want to do is to check if all the values in $arr1 exist in $arr2. The above example should be a TRUE while:
$arr3 = array(1,2,4,5,6,7);
comparing $arr1 with $arr3 will return a FALSE.
Normally I use in_array because I only need to check single value into an array. But in this case, in_array cannot be used. I'd like to see if there is a simple way to do the checking with a minimum looping.
UPDATE for clarification.
First array will be a set that contains unique values. Second array can contain duplicated values. They are both guaranteed an array before processing.
Use array_diff():
$arr1 = array(1,2,3);
$arr2 = array(1,2,3,4,5,6,7);
$arr3 = array_diff($arr1, $arr2);
if (count($arr3) == 0) {
// all of $arr1 is in $arr2
}
You can use array_intersect or array_diff:
$arr1 = array(1,2,3);
$arr2 = array(1,2,3,4,5,6,7);
if ( $arr1 == array_intersect($arr1, $arr2) ) {
// All elements of arr1 are in arr2
}
However, if you don't need to use the result of the intersection (which seems to be your case), it is more space and time efficient to use array_diff:
$arr1 = array(1,2,3);
$arr2 = array(1,2,3,4,5,6,7);
$diff = array_diff($arr1, $arr2);
if ( empty($diff) ) {
// All elements of arr1 are in arr2
}
You can try use the array_diff() function to find the difference between the two arrays, this might help you. I think to clarify you mean, all the values in the first array must be in the second array, but not the other way around.
In my particular case I needed to check if a pair of ids was processed before or not. So simple array_diff() did not work for me.
Instead I generated keys from ids sorted alphabetically and used them with in_array:
<?php
$pairs = array();
// ...
$pair = array($currentId, $id);
sort($pair);
$pair = implode('-', $pair);
if (in_array($pair, $pairs)) {
continue;
}
$pairs[$pair] = $pair;
This is probably not an optimum solution at all but I just needed it for a dirty script to be executed once.
Here's the situations:
I have 2 arrays, eg:
$a=array('a','b','c','d');
$b=array('1','b','c','e');
I want to produce 2 arrays with result:
$c=array('a','d');//only element appeared on $a
$d=array('1','e');//only element appeared on $b
Do you have a clever solution?
$c = array_diff($a, $b);
$d = array_diff($b, $a);
Sorry, my bad. It turn out a was giving the wrong array in my test.
simple array_diff solved the problem:
$c = array_diff($a, $b);
$d = array_diff($b, $a);
Try using the array_diff() function:
array_diff(array1,array2,array3...)
eg:
<?php
$a1=array(0=>"Cat",1=>"Dog",2=>"Horse");
$a2=array(3=>"Horse",4=>"Dog",5=>"Fish");
print_r(array_diff($a1,$a2));
?>
Output:
Array ( [0] => Cat )
Source: http://www.w3schools.com/PHP/func_array_diff.asp
How else might you compare two arrays ($A and $B )and reduce matching elements out of the first to prep for the next loop over the array $A?
$A = array(1,2,3,4,5,6,7,8);
$B = array(1,2,3,4);
$C = array_intersect($A,$B); //equals (1,2,3,4)
$A = array_diff($A,$B); //equals (5,6,7,8)
Is this the simplest way or is there a way to use another function that I haven't thought of? My goal is to have an array that I can loop over, pulling out groups of related content (I have defined those relationships elsewhere) until the array returns false.
You've got it. Just use array_diff or array_intersect. Doesn't get much easier than that.
Edit:
For example:
$arr_1 = array_diff($arr_1, $arr_2);
$arr_2 = array_diff($arr_2, $arr_1);
Source
Dear easy and clean way
$clean1 = array_diff($array1, $array2);
$clean2 = array_diff($array2, $array1);
$final_output = array_merge($clean1, $clean2);
See also array_unique. If you concatenate the two arrays, it will then yank all duplicates.
Hey, even better solution: array _ uintersect.
This let's you compare the arrays as per array_intersect but then it lets you compare the data with a callback function.
Try to this
$a = array(0=>'a',1=>'x',2=>'c',3=>'y',4=>'w');
$b = array(1=>'a',6=>'b',2=>'y',3=>'z');
$c = array_intersect($a, $b);
$result = array_diff($a, $c);
print_r($result);