prepare different mysqli statement [duplicate] - php

Question

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Can I mix MySQL APIs in PHP?
(4 answers)
Closed 2 years ago.
I get lost when I need to prepare multiple statements. I have problems with prepared statement and connection..
I have a function and I pass to it the connection to the database ($con variable). Inside this function i prepare more statement but i have an error, the server replied with:
mysql_error() expects parameter 1 to be resource, object given in select.php on line 1086
This is the page where i call the function and pass the connection variable:
include('include/connect.php');
echo show_volanti($con);
This is the connection file that I included above:
$con = mysqli_connect($host,$user,$password,$db);
if (!$con) {
die('Connection Error (' . mysqli_connect_errno() . ') '
. mysqli_connect_error()); }
if(!mysqli_set_charset($con, "utf8mb4")) {
printf("Error loading character set utf8: %s\n", mysqli_error($con));
exit(); }
and this is the function:
function show_volanti($data){
$con = $data; // PASSO CONNESSIONE
$con2 = ''; // SECONDA CONNESSIONE
$id = 1; // 1 VOLANTE
$visibile = 1; // VARIABILE DI VISIBILITA'
$rows1 = array(); // PREPARO ARRAY 1 PER ID ARTICOLI VOLANTE
$rows2 = array(); // PREPARO ARRAY 2 PER ARTICOLI VOLANTE
$rows3 = array(); // PREPARO ARRAY PER GALLERIA IMMAGINI ARTICOLI
$stmt1 = ''; // PREPARO GLI STATEMENT
$stmt2 = ''; // PREPARO GLI STATEMENT
$stmt3 = ''; // PREPARO GLI STATEMENT
$g = ''; // RIFERIMENTO ASSOCIAZIONE GALLERY VIEWER
$id_articoli = array(); // IMMAGAZZINO ID ARTICOLI DA RECUPERARE NELLA GALLERIA
$con2 = mysqli_stmt_init($con); // INIZIALIZZO LA CONNESSIONE
$stmt1 = mysqli_stmt_prepare($con2,'SELECT
articoli.id
FROM articoli
WHERE articoli.genere1 = ?
AND articoli.visibile = ?')
or die(mysql_error($con2));// QUERY INSERIMENTO DATI
mysqli_stmt_bind_param($stmt1,'ii',$id,$visibile); // LEGO I PARAMETRI
mysqli_stmt_execute($stmt1); // ESEGUO LA QUERY
mysqli_stmt_bind_result($stmt1,$rows1['id']);
while(mysqli_stmt_fetch($stmt1)){
$id_articoli = $rows1['id'];
}
// CREO RIFERIMENTO PER GALLERIA NEL VIEWER
$g .= "g";
$g .= $id_articoli;
$stmt2 = mysqli_stmt_prepare($con2,'SELECT
articoli.id,
articoli.titolo,
articoli.descrizione
FROM articoli
WHERE articoli.genere1 = ?
AND articoli.visibile = ? ')
or die(mysqli_error($con2)); // QUERY INSERIMENTO DATI
mysqli_stmt_bind_param($stmt2,'ii',$id,$visibile); // LEGO I PARAMETRI
mysqli_stmt_execute($stmt2); // ESEGUO LA QUERY
mysqli_stmt_bind_result($stmt2,$rows2['id'],$rows2['titolo'],$rows2['descrizione']);
// PREPARO QUERY PER LA GALLERIA
$stmt3 = mysqli_stmt_prepare($con2,'SELECT
galleria.id,
galleria.foto
FROM galleria
WHERE galleria.rif_id = ?
AND articoli.visibile = ? ')
or die(mysqli_error($con2)); // QUERY INSERIMENTO DATI
mysqli_stmt_bind_param($stmt3,'ii',$id_articoli,$visibile); // LEGO I PARAMETRI
mysqli_stmt_execute($stmt3); // ESEGUO LA QUERY
mysqli_stmt_bind_result($stmt3,$rows3['id'],$rows3['foto']);
$html = "";
$html .= "<div class='container'>";
$html .= " <div class='row'>";
$html .= " <div class='col-sm-12'>";
$html .= " <div class='panel panel-default'>";
$html .= " <div class='panel-body'>";
while (mysqli_stmt_fetch($stmt2)){
$html .= " <div class='col'>";
$html .= " <div class='panel panel-default'>";
$html .= " <div class='panel-heading'>$rows2[titolo]</div>";
$html .= " <div class='panel-body'>";
$html .= " <div class='row'>";
$html .= " <div class='class_p'>$rows2[descrizione]</div>";
$html .= " <div> <!-- end first row -->";
$html .= " <div class='class_container clearfix'>";
while(mysqli_stmt_fetch($stmt3)){
$html .= " <div class='thumbnail col-sm-2'>";
$html .= " <div class='class_img'>";
$html .= " <a href='$rows3[foto]' data-toggle='lightbox' data-gallery='$g' >";
$html .= " <img src='$rows3[foto]' class='img-responsive' class='img-fluid'>";
$html .= " </a>";
$html .= " </div> <!-- end class_img -->";
$html .= " </div> <!-- end thumbnail col-sm-2- -->";
}
$html .= " </div> <!-- end class_container -->";
$html .= " </div> <!-- end panel body -->";
$html .= " </div> <!-- end panel panel-default -->";
$html .= " </div> <!-- end col -->";
}
$html .= " </div> <!-- end panel-body -->";
$html .= " </div> <!-- end panel panel-default -->";
$html .= " </div> <!-- end col-sm-12 -->";
$html .= " </div> <!-- end row -->";
mysqli_close($con2); // CHIUDO CONNESSIONE
return $html;
}

Answer 1

This results in the error:
$stmt1 = mysqli_stmt_prepare($con2,'SELECT
articoli.id,
FROM articoli
WHERE articoli.genere1 = ?
AND articoli.visibile = ?')
or die(mysql_error($con2));// QUERY INSERIMENTO DATI
Change mysql_error to mysqli_error and your problem should be fixed.
Note: Using or die() is a bad way to handle an error.