Issue on output's return value - php

Question

Currently I am using a file with css and all.I have a problem as i am using php output between many html tags. The menu consist of the hard coded pages which is included with the php require_once. However, i also want to add in some pages from my database.
The Problem: The menu only shows 1 page name from my database when i have 2. It is displaying the 2nd page's name i have made. However clicking on it, it calls up the content from the 1st page.
The page name from my database is added using php output after the <ul id="menu-toc">
The page's content from my database is added at the bottom of the "The Page" section.
update: I've changed the placing of the while loop before the to after the
Pattern of css
<div class="bb-item" id="abscess">
<div class="content">
<div class="scroller">
Content
</div>
</div>
</div>
The Page
function find_condition() {
global $connection;
$query = "SELECT * ";
$query .= "FROM pages ";
$query .= "WHERE visible = 1 ";
$query .= "AND subject_id = 2 ";
$query .= "ORDER BY position ASC";
$page_set = mysqli_query($connection, $query);
confirm_query($page_set);
return $page_set;
}
$two = find_condition();
while($page = mysqli_fetch_assoc($two)) {
$pagearray = $page['menu_name'];
?>
<ul id="menu-toc" class="menu-toc">
<li class="menu-toc-current">
ABSCESS</li>
<li>APTHOUS ULCER</li>
<li>BAD BREATH</li>
<?php
$output = "<li>";
$output .= "<a href=\"";
$output .= $pagearray;
$output .= "\">";
$output .= $pagearray;
$output .= "</a></li>";
}
echo $output;
?>
</ul>
</div>
<div class="bb-custom-wrapper">
<div id="bb-bookblock" class="bb-bookblock">
<?php require_once("abscess.php"); ?>
<?php require_once("apthousulcer.php"); ?>
<?php require_once("bad breath.php"); ?>
<?php
$two= find_condition();
while($page = mysqli_fetch_assoc($two)) {
$pagearray = $page['menu_name'];
$content = $page['content'];
$output .= "<div class=\"bb-item\" id=\"";
$output .= $pagearray;
$output .= "\">";
$output .= "<div class=\"content\">";
$output .= "<div class=\"scroller\">";
$output .= "<h2>";
$output .= $pagearray;
$output .= "</h2>";
$output .= $content;
$output .= "</div>";
$output .= "</div>";
$output .= "</div>";
}
echo $output;
?>

Answer 1

You're starting a new <ul> each time through the while loop. You should just do that once, before the loop. You're also reinitializing $output each time through the loop, but not printing it in the loop. So you're just printing the last assignment of output after the loop is done.
$two = find_condition();
?>
<ul id="menu-toc" class="menu-toc">
<li class="menu-toc-current">
ABSCESS</li>
<li>APTHOUS ULCER</li>
<li>BAD BREATH</li>
<?php
while($page = mysqli_fetch_assoc($two)) {
$pagearray = $page['menu_name'];
?>
<?php
$output = "<li>";
$output .= "<a href=\"";
$output .= $pagearray;
$output .= "\">";
$output .= $pagearray;
$output .= "</a></li>";
echo $output;
}
?>