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$date ="2018-02-15";
$next_month = date('$date', strtotime('+1 month');
echo "$next_month";
I want the output as "2018-03-15";
But this code not working.
You can use strtotime
$date ="2018-02-15";
$time = strtotime($date);
$next_month = date("Y-m-d", strtotime("+1 month", $time));
echo $next_month;
The result will be:
2018-03-15
Doc: strtotime
use this:
$date ="2018-04-22";
$next_month = date('Y-m-d', strtotime($date.' +1 month'));
echo "$next_month";
I need to get the first day of the week (Monday), 8 weeks back from today, where 8 is a variable.
What's the best way to do that in PHP?
You can do this way
echo date("l M-d-Y", strtotime('monday this week'));
echo date("l M-d-Y", strtotime('sunday this week'));
echo date("l M-d-Y", strtotime('monday last week'));
echo date("l M-d-Y", strtotime('sunday last week'));
echo date("l M-d-Y", strtotime('monday next week'));
echo date("l M-d-Y", strtotime('sunday next week'));
You can also search monthwise
echo date("l M-d-Y", strtotime('first day of this month'));
echo date("l M-d-Y", strtotime('last day of this month'));
echo date("l M-d-Y", strtotime('first day of last month'));
echo date("l M-d-Y", strtotime('last day of last month'));
echo date("l M-d-Y", strtotime('first day of next month'));
echo date("l M-d-Y", strtotime('last day of next month'));
$weeks = 8;
// Timestamp for $weeks weeks ago
$time = strtotime("$weeks weeks ago");
// Day of the week for $time (1 - Mon, ...)
$week_day = date('N', $time);
// Number of days from Monday
$diff = $week_day - 1;
// The date of the Monday $weeks weeks ago
echo date('j', $time - ($diff * 24 * 3600));
It's not really complicated actually, all you got to do is play a little bit with datetimes ;
<?php
$dt = new Datetime(sprintf('%d weeks ago', 8)); // replace 8 with variable, your value, whatever
$day = $dt->format('w');
$dt->modify(sprintf('%d days go', ($day - 1) % 7));
your $dt should then have the value you seek
You can make some math with dates in PHP like:
$now = date('F d, Y H:i');
$newdate = date('F d, Y H:i', strtotime($now.' - 8 weeks'));
echo $newdate;
In this case it will output a current date minus 8 weeks.
Also to count which day is today you can use:
$dw = date( "w", strtotime($newdate));
Where $dw will be 0 (for Sunday) through 6 (for Saturday) more informations can be found: PHP: date
Solution
In your case it would look as follows:
<?php
$weeks = 8;
$now = date('F d, Y H:i:s');
$newdate = date('F d, Y H:i:s', strtotime($now.' - '.$weeks.' weeks'));
$new_date_day = date( "w", strtotime($newdate));
$minus = $new_date_day - 1;
if ($minus < 0) { //check if sunday
$plus = $minus * -1;
$newdate = date('F d, Y H:i:s', strtotime($newdate.' + '.$plus.' days'));
} else {
$newdate = date('F d, Y H:i:s', strtotime($newdate.' - '.$minus.' days'));
}
echo $newdate;
?>
Of course you can echo what ever style of date you want. F.ex. F d, Y H:i:s will output November 28, 2016 06:18:03.
How to find get week duration or week range from monday to friday for the given date in php.
for example i have date
$date = "2013-02-24";
Now i want range of date from monday to friday for the month
Just Try Out this answer.
$date = "2013-02-24";
$week = date('W', strtotime($date));
$year = date('o', strtotime($date));
echo "first day of week". $from = date("Y-m-d", strtotime("{$year}-W{$week}-1"));
echo "end day of week". $to = date("Y-m-d", strtotime("{$year}-W{$week}-5"));
function week_range($date) {
$ts = strtotime($date);
$start = (date('w', $ts) == 0) ? $ts : strtotime('last monday', $ts);
return array(date('Y-m-d', $start),
date('Y-m-d', strtotime('next friday', $start)));
}
And call it like this:
list($start_date, $end_date) = week_range('2009-05-10');
how to get the previous 3 months in php ex(If i say DEC.. It should display the previous 3 months i.e., OCT NOV DEC)
You can use the strtotime function like this:
echo date('M', strtotime('-3 month'));
So you specify previous dates with minus sign.
echo date('M', strtotime('0 month'));
echo date('M', strtotime('-1 month'));
echo date('M', strtotime('-2 month'));
echo date('M', strtotime('-3 month'));
Results:
Dec
Nov
Oct
Sep
You can do the same if you are using a loop like this:
for ($i = -3; $i <= 0; $i++){
echo date('M', strtotime("$i month"));
}
Results:
Sep
Oct
Nov
Dec
Check out the documentation too see many other friendly date and time keywords strtotime supports:
http://php.net/manual/en/function.strtotime.php
Voted answer is almost correct.
Correct solution is:
for ($i = -3; $i <= 0; $i++){
echo date('M', strtotime("$i month", strtotime(date("Y-m-15"))));
}
Explain: strtotime default implementation is:
date ( string $format [, int $timestamp = time() ] ) : string
As you can see there is timestamp with default value of: time().
Last say today is 31th March.
Because there is no 31th Feb
echo date('M', strtotime("-1 month"));
will return March
On the other hand:
echo date('M', strtotime("+1 month"));
will return May (April will be skipped).
Because of that issue we have to setup timestamp value which is a safe date.
Every date between 1-28 is safe because every month have got that date. In my example I had choose 15th day of month.
$month = date('M');
$year = date('Y');
$no_of_mnths = date('n',strtotime("-2 months"));
$remaining_months = (12 - $no_of_mnths)."\r\n";
$tot = $remaining_months+1;
for($j=0;$j<$tot;$j++){
echo date('M',strtotime(''.$no_of_mnths.' months'))
$no_of_mnths++;
}
This may help you`
<?php
$date = explode("-", "2016-08-31");
if($date[2]== "01"){$days = "-0 days";}else{$days = "-1 days";}
$time = strtotime($days, mktime(0, 0, 0, $date[1], $date[2], $date[0]));
$MTD = date('Y-m-01', strtotime('0 month'));
$M1 = date('Y-m-01', strtotime('-1 month'));
$M2 = date('Y-m-01', strtotime('-2 month'));
$M3 = date('Y-m-01', strtotime('-3 month'));
$rng = array();
$rng[$MTD] = strftime("%B, %Y", strtotime(" ", $time));
$rng[$M1] = strftime("%B, %Y", strtotime("first day of previous month", $time));
$rng[$M2] = strftime("%B, %Y", strtotime("-2 months", $time));
$rng[$M3] = strftime("%B, %Y", strtotime("-3 months", $time));
?>
Here $MTD ,$M1,$M2,$M3 will give date in the form of "dd-mm-yyyy" and $rng[$MTD], $rng[$M1],$rng[$M2],$rng[$M3] give date in the form of"Name of Month,year" => (i.e August,2016)
How can I get the Sunday and Saturday of the week given a specific date?
For example:
input: Monday, September 28, 2009
output should be:
Sunday, September 27, 2009 12:00 AM - Saturday, October 3, 2009 11:59 PM
I am thinking of using the date, strtotime, mktime and time php functions.
If you have a usable function then it is also fine with me.
Thanks in advance :)
Cheers,
Mark
You use strtotime() and date():
<?php
$s = 'Monday, September 28, 2009';
$time = strtotime($s);
$start = strtotime('last sunday, 12pm', $time);
$end = strtotime('next saturday, 11:59am', $time);
$format = 'l, F j, Y g:i A';
$start_day = date($format, $start);
$end_day = date($format, $end);
header('Content-Type: text/plain');
echo "Input: $s\nOutput: $start_day - $end_day";
?>
outputs:
Input: Monday, September 28, 2009
Output: Sunday, September 27, 2009 12:00 PM - Saturday, October 3, 2009 11:59 AM
<?php
date_default_timezone_set('Europe/London');
$datetime = new DateTime("2009-09-23 12:00:00");
// Saturday
$datetime->setISODate(2009, $datetime->format("W"), 6);
print "Saturday:" . $datetime->format(DATE_ATOM) . "\n";
// Sunday
$datetime->setISODate(2009, $datetime->format("W"), 0);
print "Sunday: " . $datetime->format(DATE_ATOM) . "\n";
?>
take a look at strtotime
i.e.
strtotime('next sunday', strtotime($your_date_string));
echo date("Y-m-d H:i:s", strtotime("last sunday", time()));
echo date("Y-m-d H:i:s", strtotime("next saturday", time()));
the issue with the 'correct' answer is, what if the supplied date is Sunday? Then it will give you the previous Sunday, instead of the current Sunday. Same issue with Saturday.
$s = 'Monday, September 28, 2009';
$time = strtotime($s);
if(date('D', $time) == "Sun"){
$start = strtotime(' 12pm', $time);
}
else {
$start = strtotime('last sunday, 12pm', $time);
}
if(date('D', $time) == "Sat"){
$start = strtotime(' 12pm', $time);
}
else {
$start = strtotime('next saturday, 12pm', $time);
}
$format = 'l, F j, Y g:i A';
$start_day = date($format, $start);
$end_day = date($format, $end);
header('Content-Type: text/plain');
echo "Input: $s\nOutput: $start_day - $end_day";
strtotime
$input = strtotime("Monday, September 28, 2009");
$nextSunday = strtotime("next Sunday",$input);
<?php
$date = strtotime('Monday, September 28, 2009 - 1 day');
$initialString = date('l, F d, Y g:i A', $date);
$end = date('l, F d, Y g:i A', strtotime( 'next saturday 11:59 pm', $date));
echo $initialString . ' - ' . $end;
output:
Sunday, September 27, 2009 12:00 AM - Saturday, October 03, 2009 11:59 PM
This is what your looking for. It is what I use.
$beginningOfWeek = date('Y-m-d H:i:s', strtotime('last Sunday'));
$endOfWeek = date('Y-m-d H:i:s', strtotime('+6 day', strtotime('last Sunday')) );
You may find my Date Time Helper much handy in this case , it can finish in 3 Lines
http://normandqq.github.io/Date-Time-Helper/
$date = '2013-08-11';
$monday = Model_DTHpr::getMondayByDate($date);
$sunday = Model_DTHpr::adjustDays("add",$monday,6);
Out Put:
2013-08-05 //Monday
2013-08-11 //Sunday
Get Sunday Php Code:
echo "Today Is : " . date("d-m-Y");
$dw = date( "w");
$dw = 7-$dw;
echo "\nNext Sunday Is" .date('d-m-Y', strtotime("+$dw days"));