PHP: How to get Sunday and Saturday given a date input? - php

Question

How can I get the Sunday and Saturday of the week given a specific date?
For example:
input: Monday, September 28, 2009
output should be:
Sunday, September 27, 2009 12:00 AM - Saturday, October 3, 2009 11:59 PM
I am thinking of using the date, strtotime, mktime and time php functions.
If you have a usable function then it is also fine with me.
Thanks in advance :)
Cheers,
Mark

Answer 1

You use strtotime() and date():
<?php
$s = 'Monday, September 28, 2009';
$time = strtotime($s);
$start = strtotime('last sunday, 12pm', $time);
$end = strtotime('next saturday, 11:59am', $time);
$format = 'l, F j, Y g:i A';
$start_day = date($format, $start);
$end_day = date($format, $end);
header('Content-Type: text/plain');
echo "Input: $s\nOutput: $start_day - $end_day";
?>
outputs:
Input: Monday, September 28, 2009
Output: Sunday, September 27, 2009 12:00 PM - Saturday, October 3, 2009 11:59 AM

Answer 2

<?php
date_default_timezone_set('Europe/London');
$datetime = new DateTime("2009-09-23 12:00:00");
// Saturday
$datetime->setISODate(2009, $datetime->format("W"), 6);
print "Saturday:" . $datetime->format(DATE_ATOM) . "\n";
// Sunday
$datetime->setISODate(2009, $datetime->format("W"), 0);
print "Sunday: " . $datetime->format(DATE_ATOM) . "\n";
?>

Answer 3

take a look at strtotime
i.e.
strtotime('next sunday', strtotime($your_date_string));

Answer 4

echo date("Y-m-d H:i:s", strtotime("last sunday", time()));
echo date("Y-m-d H:i:s", strtotime("next saturday", time()));

Answer 5

the issue with the 'correct' answer is, what if the supplied date is Sunday? Then it will give you the previous Sunday, instead of the current Sunday. Same issue with Saturday.
$s = 'Monday, September 28, 2009';
$time = strtotime($s);
if(date('D', $time) == "Sun"){
$start = strtotime(' 12pm', $time);
}
else {
$start = strtotime('last sunday, 12pm', $time);
}
if(date('D', $time) == "Sat"){
$start = strtotime(' 12pm', $time);
}
else {
$start = strtotime('next saturday, 12pm', $time);
}
$format = 'l, F j, Y g:i A';
$start_day = date($format, $start);
$end_day = date($format, $end);
header('Content-Type: text/plain');
echo "Input: $s\nOutput: $start_day - $end_day";

Answer 6

strtotime
$input = strtotime("Monday, September 28, 2009");
$nextSunday = strtotime("next Sunday",$input);

Answer 7

<?php
$date = strtotime('Monday, September 28, 2009 - 1 day');
$initialString = date('l, F d, Y g:i A', $date);
$end = date('l, F d, Y g:i A', strtotime( 'next saturday 11:59 pm', $date));
echo $initialString . ' - ' . $end;
output:
Sunday, September 27, 2009 12:00 AM - Saturday, October 03, 2009 11:59 PM

Answer 8

This is what your looking for. It is what I use.
$beginningOfWeek = date('Y-m-d H:i:s', strtotime('last Sunday'));
$endOfWeek = date('Y-m-d H:i:s', strtotime('+6 day', strtotime('last Sunday')) );

Answer 9

You may find my Date Time Helper much handy in this case , it can finish in 3 Lines
http://normandqq.github.io/Date-Time-Helper/
$date = '2013-08-11';
$monday = Model_DTHpr::getMondayByDate($date);
$sunday = Model_DTHpr::adjustDays("add",$monday,6);
Out Put:
2013-08-05 //Monday
2013-08-11 //Sunday

Answer 10

Get Sunday Php Code:
echo "Today Is : " . date("d-m-Y");
$dw = date( "w");
$dw = 7-$dw;
echo "\nNext Sunday Is" .date('d-m-Y', strtotime("+$dw days"));