Hi just need to solve this php issue
What I need is to get only specific part of the text that I get from remote server. So remote server gives me this kind of content
......":"http://xxxxxxxx.com?source=yyyyy&service=zzzzz&token=47baiufbweiwrwrqwr21","...........
And I need to get back only this part: token=47baiufbweiwrwrqwr21
thank for help
Use parse_url() and preg_match()
$url = 'http://xxxxxxxx.com?source=yyyyy&service=zzzzz&token=47baiufbweiwrwrqwr21';
$query = parse_url($url, PHP_URL_QUERY);
preg_match('/token=([a-z0-9]+)/i', $query, $token);
echo $token[1];
parse_url() returns the Components of an URL.
You want to have a specific Query-Parameter, so you use the PHP_URL_QUERY-Component. After this you extract the token with a Regular Expression that searches for the Parameter-Name "token" followed by a "=". Then you catch all characters you want (a-z and 0-9). You set the i-Delimiter for a caseinsensitive Search. $token[1] returns the Match within the Subpattern (Brackets).
And if you get the URL from a File you can read it into a String using file_get_contents().
You can use substr and stripos
This will make sure you get the correct part even if the variables are in a different order and is not case sensitive.
https://3v4l.org/q35f0
$url = 'http://xxxxxxxx.com?source=yyyyy&token=47baiufbweiwrwrqwr21&service=zzzzz';
$pos = stripos($url, "token");
$pos2 = stripos($url, "&", $pos);
If($pos2 > 0){
Echo substr($url, $pos, $pos2-$pos);
}Else{
Echo substr($url, $pos);
}
Edit sorry my phone autocorrected my stripos to strpos. Funny how my phone is starting to learn php.
Related
This may be a dupe, but I cannot seem to find a thread which matches this issue. I want to remove all chars from a string after a given sub-string - but the chars and the number of chars after the sub-string is unknown. Most solutions I have found seem to only work for removing the given sub-string itself or a fixed length after a given sub-string.
I have
$str = preg_replace('(.gif*)','.gif$',$str);
Which locates 'blahblah.gif?12345' ok, but I cannot seem to remove the chars after the sub-string '.gif'. I read that $ denotes EOS so I thought this would work, but apparently not. I also tried
'.gif$/'
and simply
'.gif'
It can be done without regex:
echo substr('blahblah.gif?12345', strpos('blahblah.gif?12345', '.gif') + 4);
// returns ?12345 this is the length of the substring ^
So the code is:
$str = 'original string';
$match = 'matching string';
$output = substr($str, strpos($str, $match) + strlen($match));
Ok, now I'm not sure if you want to keep the first or the second part of the string. Anyway, here's the code for keeping the first part:
echo substr('blahblah.gif?12345', 0, strpos('blahblah.gif?12345', '.gif') + 4);
// returns blahblah.gif ^ this is the key
And the full code:
$str = 'original string';
$match = 'matching string';
$output = substr($str, 0, strpos($str, $match) + strlen($match));
See the both examples work here: http://ideone.com/Ge30rY
Assuming (from OP's comment) that you are working with actual URLs as your source string, I believe that the best course of action here would be to use PHP's built-in functionality for working with and parsing URLs. You do this by using the parse_url() function:
(PHP 4, PHP 5)
parse_url — Parse a URL and return its components
This function parses a URL and returns an associative array containing any of the various components of the URL that are present.
This function is not meant to validate the given URL, it only breaks it up into the above listed parts. Partial URLs are also accepted, parse_url() tries its best to parse them correctly.
From your example: www.page.com/image.gif?123 (or even just image.gif?123) using parse_url() will look something like this:
var_dump( parse_url( "www.page.com/image.gif?123" ) );
array(2) {
["path"]=>
string(22) "www.page.com/image.gif"
["query"]=>
string(3) "123"
}
As you can see, without the need for regular expressions or string manipulations we have broken up the URL into it's separate components. No need to re-invent the wheel. Nice and clean :)
You could do this:
$str = "somecontent.gif?anddata";
$pattern = ".gif";
echo strstr($str,$pattern,true).$pattern;
// Set up string to search through
$haystack = "blahblah.gif?12345";
// Determine substring and length of it
$needle = ".gif";
$length = strlen($needle);
// Find position of last substring
$location = strrpos($haystack, $needle);
// Use location of last occurence + it's length to get new string
$newtext = substr($haystack, 0, $location+$length);
I am working on query string pattern for a redirection application. Can we use multiple OR statement in strstr. ex. if i am not sure whether it will be & or & or $ or / then is it possible to use the other signs in OR condition with $code= strstr($code, '/',+1);
Explanation:
the url will come to our redirect application like this
https://www.sample.com?key=1234~rety~1234~retu&c=12&k=12
OR
https://www.sample.com?key=1234~rety~1234~retu/c=12/k=12
OR
https://www.sample.com?key=1234~rety~1234~retu$c=12$k=12
the only variable for our purpose is key(whose name can be changed but data will come int he same pattern) all i want is to get data with ~ pattern.
I am doing following:
parse_str(parse_url($url, PHP_URL_QUERY), $parts);
$keys = array_keys($parts);
$size=sizeof($keys);
$total=substr_count($uri, '~');
$var=$keys[0];
$value=$parts[$var];
for($i=0;$i<$size;$i++){
$var=$keys[$i];
$value=$parts[$var];
$total=substr_count($value, '~');
if($total==3){
$digit_code = preg_split('/\~+/', $value);
$digit_code = array_filter($digit_code);
$digit_code = array_values($digit_code);
$project_id=$digit_code[0];
$country_id=$digit_code[1];
$vendor=$digit_code[2];
$code=$digit_code[3];
//$code= strstr($code, '/',+1);
}
But it is not working when url is coming like this
https://www.sample.com?key=1234~rety~1234~retu/c=12/k=12
or
https://www.sample.com?key=1234~rety~1234~retu$c=12$k=12
This is where using regex could be applicable:
preg_match('/((?:\/|&|\$).*)/', $code, $matches);
$code = $matches[1];
This will match a / or & or $ followed by the rest of the string.
http://au1.php.net/preg_match
are you referring in PHP redirection? or a query string in database to fetch data?
you can read strstr manual.
I found the solution:
I just put
if (strpos($code,'/') !== false) {
$code= strstr($code, '/',+1);
}
if (strpos($code,'$') !== false) {
$code= strstr($code, '$',+1);
}
once after for loop
I need to get the vine video id from the url
so the output from link like this
https://vine.co/v/bXidIgMnIPJ
be like this
bXidIgMnIPJ
I tried to use code form other question here for Vimeo (NOT VINE)
Get img thumbnails from Vimeo?
This what I tried to use but I did not succeed
$url = 'https://vine.co/v/bXidIgMnIPJ';
preg_replace('~^https://(?:www\.)?vine\.co/(?:clip:)?(\d+)~','$1',$url)
basename maybe?
<?php
$url = 'https://vine.co/v/bXidIgMnIPJ';
var_dump(basename($url));
http://codepad.org/vZiFP27y
Assuming it will always be in that format, you can just split the url by the / delimiter. Regex is not needed for a simple url such as this.
$id = end(explode('/', $url));
Referring to as the question is asked here is a solution for preg_replace:
$s = 'https://vine.co/v/bXidIgMnIPJ';
$new_s = preg_replace('/^.*\//','',$s);
echo $new_s;
// => bXidIgMnIPJ
or if you need to validate that an input string is indeed a link to vine.co :
$new_s = preg_replace('/^(https?:\/\/)?(www\.)?vine\.co.*\//','',$s);
I don't know if that /v/ part is always present or is it always v... if it is then it may also be added to regex for stricter validation:
$new_s = preg_replace('/^(https?:\/\/)?(www\.)?vine\.co\/v\//','',$s);
Here's what I am using:
function getVineId($url) {
preg_match("#(?<=vine.co/v/)[0-9A-Za-z]+#", $url, $matches);
if (isset($matches[0])) {
return $matches[0];
}
return false;
}
I used a look-behind to ensure "vine.co/v/" always precedes the ID, while ignoring if the url is HTTP or HTTPS (or if it lacks a protocol altogether). It assumes the ID is alphanumeric, of any length. It will ignore any characters or parameters after the id (like Google campaign tracking parameters, etc).
I used the "#" delimiter so I wouldn't have to escape the forward slashes (/), for a cleaner look.
explode the string with '/' and the last string is what you are looking for :) Code:
$vars = explode("/",$url);
echo $vars[count($vars)-1];
$url = 'https://vine.co/v/b2PFre2auF5';
$regex = '/^http(?:s?):\/\/(?:www\.)?vine\.co\/v\/([a-zA-Z0-9]{1,13})$/';
preg_match($regex,$url,$m);
print_r($m);
1. b2PFre2auF5
I know it may sound as a common question but I have difficulty understanding this process.
So I have this string:
http://domain.com/campaign/tgadv?redirect
And I need to get only the word "tgadv". But I don't know that the word is "tgadv", it could be whatever.
Also the url itself may change and become:
http://domain.com/campaign/tgadv
or
http://domain.com/campaign/tgadv/
So what I need is to create a function that will get whatever word is after campaign and before any other particular character. That's the logic..
The only certain thing is that the word will come after the word campaign/ and that any other character that will be after the word we are searching is a special one ( i.e. / or ? )
I tried understanding preg_match but really cannot get any good result from it..
Any help would be highly appreciated!
I would not use a regex for that. I would use parse_url and basename:
$bits = parse_url('http://domain.com/campaign/tgadv?redirect');
$filename = basename($bits['path']);
echo $filename;
However, if want a regex solution, use something like this:
$pattern = '~(.*)/(.*)(\?.*)~';
preg_match($pattern, 'http://domain.com/campaign/tgadv?redirect', $matches);
$filename = $matches[2];
echo $filename;
Actually, preg_match sounds like the perfect solution to this problem. I assume you are having problems with the regex?
Try something like this:
<?php
$url = "http://domain.com/campaign/tgadv/";
$pattern = "#campaign/([^/\?]+)#";
preg_match($pattern, $url, $matches);
// $matches[1] will contain tgadv.
$path = "http://domain.com/campaign/tgadv?redirect";
$url_parts = parse_url($path);
$tgadv = strrchr($url_parts['path'], '/');
You don't really need a regex to accomplish this. You can do it using stripos() and substr().
For example:
$str = '....Your string...';
$offset = stripos($str, 'campaign/');
if ( $offset === false ){
//error, end of h4 tag wasn't found
}
$offset += strlen('campaign/');
$newStr = substr($str, $offset);
At this point $newStr will have all the text after 'campaign/'.
You then just need to use a similar process to find the special character position and use substr() to strip the string you want out.
You can also just use the good old string functions in this case, no need to involve regexps.
First find the string /campaign/, then take the substring with everything after it (tgadv/asd/whatever/?redirect), then find the next / or ? after the start of the string, and everything in between will be what you need (tgadv).
I have a input form field which collects mixed strings.
Determine if a posted string contains an URL (e.g. http://link.com, link.com, www.link.com, etc) so it can then be anchored properly as needed.
An example of this would be something as micro blogging functionality where processing script will anchor anything with a link. Other sample could be this same post where 'http://link.com' got anchored automatically.
I believe I should approach this on display and not on input. How could I go about it?
You can use regular expressions to call a function on every match in PHP. You can for example use something like this:
<?php
function makeLink($match) {
// Parse link.
$substr = substr($match, 0, 6);
if ($substr != 'http:/' && $substr != 'https:' && $substr != 'ftp://' && $substr != 'news:/' && $substr != 'file:/') {
$url = 'http://' . $match;
} else {
$url = $match;
}
return '' . $match . '';
}
function makeHyperlinks($text) {
// Find links and call the makeLink() function on them.
return preg_replace('/((www\.|(http|https|ftp|news|file)+\:\/\/)[_.a-z0-9-]+\.[a-z0-9\/_:#=.+?,##%&~-]*[^.|\'|\# |!|\(|?|,| |>|<|;|\)])/e', "makeLink('$1')", $text);
}
?>
You will want to use a regular expression to match common URL patterns. PHP offers a function called preg_match that allows you to do this.
The regular expression itself could take several forms, but here is something to get you started (also maybe just Google 'URL regex':
'/^(((http|https|ftp)://)?([[a-zA-Z0-9]-.])+(.)([[a-zA-Z0-9]]){2,4}([[a-zA-Z0-9]/+=%&_.~?-]))$/'
So your code should look something this:
$matches = array(); // will hold the results of the regular expression match
$string = "http://www.astringwithaurl.com";
$regexUrl = '/^(((http|https|ftp):\/\/)?([[a-zA-Z0-9]\-\.])+(\.)([[a-zA-Z0-9]]){2,4}([[a-zA-Z0-9]\/+=%&_\.~?\-]*))*$/';
preg_match($regexUrl, $string, $matches);
print_r($matches); // an array of matched patterns
From here, you just want to wrap those URL patterns in an anchor/href tag and you're done.
Just how accurate do you want to be? Given just how varied URLs can be, you're going to have to draw the line somewhere. For instance. www.ca is a perfectly valid hostname and does bring up a site, but it's not something you'd EXPECT to work.
You should investigate regular expressions for this.
You will build a pattern that will match the part of your string that looks like a URL and format it appropriately.
It will come out something like this (lifted this, haven't tested it);
$pattern = "((https?|ftp|gopher|telnet|file|notes|ms-help):((//)|(\\\\))+[\w\d:##%/;$()~_?\+-=\\\.&]*)";
preg_match($pattern, $input_string, $url_matches, PREG_OFFSET_CAPTURE, 3);
$url_matches will contain an array of all of the parts of the input string that matched the url pattern.
You can use $_SERVER['HTTP_HOST'] to get the host information.
<?php
$host = $SERVER['HTTP_HOST'];
?>
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