Good day!
I'm doing a site. There is a checkbox which update the option I choose in phpmyadmin.
But if I press submit, then f5/reload page, the preference I choose disappears on client/html side, (look the image for better understanding)
Image, open me!
So basically I want the site remember my choice in the "user account"
I tried with
<form action="pr.php" method="POST">
<h3 style="color:red;">Numbers?</h3>
<input type="checkbox" name="a1" value="1" <?php if(isset($_POST['a1'])) echo "checked='checked'"; ?> /><label>One</label><br/>
<input type="checkbox" name="a2" value="2" <?php if(isset($_POST['a2'])) echo "checked='checked'"; ?> /><label>Two</label><br/>
<input type="checkbox" name="a3" value="3" <?php if(isset($_POST['a3'])) echo "checked='checked'"; ?> /><label>3</label><br/>
<input type="checkbox" name="a4" value="4" <?php if(!is_null($_POST['a4'])) echo "checked='checked'"; ?> /><label>Four</label><br/>
<input type="submit" value="submit" name="submit">
It doesnt work with isset, empty or is_null.
Thanks for all!
Unless you save the information on a database, even if you clicked on submit, after you refresh the webpage you are going to loose the the values of the variables.
You could use cookies to save the value of the choice that was checked:
setcookie("checkbox1","checked");
First parameter is name of the cookie, second one is the value of the cookie, and you can add a third one with the time you want the cookie to have before it expires.
And in your if condition, you could do this:
<?php if($_COOKIE['a1'] == "checked") echo "checked='checked'"; >
For more info, check this link.
Related
so I'm creating a small form where you can update the values of some fields pulled from a database.
Two of the fields I have however are acting wrong, when the page loads they display the information correctly but when you press 'submit' the fields in the MySQL table go blank. All the other fields update correctly including a checkbox, but not these two radio buttons.
Here's the code for it, I'm sorry to be asking this but does anyone see the error? I'm rather new with PHP so I'm not sure what to look for.
Snippet of the PHP Code (I can post the full code of it, but it's long):
<?php
if(isset($_POST['submit'])) {
$mbr=$_POST['mbr'];
$rec=$_POST['rec'];
$update = $dbconnect->query("UPDATE testing SET mbr='$mbr', rec='$rec'");
}
?>
HTML Code for the 2 radio buttons:
<input type="radio" name="mbr" <?php echo $upChecked; ?>>Up <input type="radio" name="mbr" <?php echo $downChecked; ?>>Down
<input type="radio" name="rec" <?php echo $yesChecked; ?>>Yes <input type="radio" name="rec" <?php echo $noChecked; ?>>No
Nevermind I'm dumb and tired and missed the obvious solution, I forgot to put the values of the buttons in their code.
How they should be
<input type="radio" name="mbr" value="up" <?php echo $upChecked; ?>>Up <input type="radio" name="mbr" value="down" <?php echo $downChecked; ?>>Down
<input type="radio" name="rec" value="yes" <?php echo $yesChecked; ?>>Yes <input type="radio" name="rec" value="no" <?php echo $noChecked; ?>>
I know there's "PHP keep checkbox checked after submitting form" on here, but that thread does not solve my problem, because I have multiple checkbox, what I need is when you check a checkbox, this stay checked after submit.
At the moment with this code nothing happens, I tried another way but when I check "id7" checkbox, all the checkbox get checked.
I have to know which checkbox was checked by the id that I give it, but I do not know how.
while ($fila = mysql_fetch_array($rs)) {
echo utf8_encode("
<tr>
<td>
".$fila['title']."
</td>
");?>
<td>
<input type="checkbox" name="checklist[]" value="<?php echo htmlspecialchars($fila['id']); ?>" <?php if(isset($_POST['checklist[]']) && is_array($_POST['checklist[]']) && in_array('$fila', $_POST['checklist[]'])) echo 'checked="checked"'; ?> />
</td>
<?php
}
}
?>
First, the value of checkbox is $fila['id'] so when you are checking, use $fila['id'] instead of $fila. Also, when PHP receive array input fields with [] in their names the [] will be removed so that the correct POST variable is $_POST['checklist'].
Try changing this line:
<input type="checkbox" name="checklist[]" value="<?php echo htmlspecialchars($fila['id']); ?>" <?php if(isset($_POST['checklist[]']) && is_array($_POST['checklist[]']) && in_array('$fila', $_POST['checklist[]'])) echo 'checked="checked"'; ?> />
to
<input type="checkbox" name="checklist[]" value="<?php echo htmlspecialchars($fila['id']); ?>" <?php if(isset($_POST['checklist']) && is_array($_POST['checklist']) && in_array($fila['id'], $_POST['checklist'])) echo 'checked="checked"'; ?> />
"name" is like a variable name - by using checklist[] you're defining an array as the variable.
Why not just name each checkbox properly? When the form is submitted, use the contents of $_POST to set each variable into the user's $_SESSION.
If the page is refreshed, use the values from $_SESSION to determine if the checkbox should be ticked. Something like (untested):
<input type="checkbox" name="vehicle" value="Bike"
<?php if (isset($_SESSION['bike_checked']) echo 'checked'; ?>> I have a bike<br>
<input type="checkbox" name="vehicle" value="Car"
<?php if (isset($_SESSION['car_checked']) echo 'checked'; ?>> I have a car<br>
<input type="submit" value="Submit">
two problem i have:
first:
i want users see my form with no prechecked in radio buttons but it does when they see it at first time(as you see)(explain that i use checked to show user which radio he/she selected after pushing the button)
second:
why when i name submit button "select sex" and push it in the form, it doesn't echo "it's done" but when i name it "select" it works?! i want my submit name has two words.
and the codes:
<html>
<body>
<?php
if(isset($_POST['select sex']))
echo "it's done";
?>
<form name="input" action="" method="post">
<input type="radio" name="sex" value="male" checked="
<?php if(isset($_POST['select sex']) and $_POST['sex']=='male') echo 'checked'; else echo '';?>
"> Male<br />
<input type="radio" name="sex" value="female" checked="
<?php if(isset($_POST['select sex']) and $_POST['sex']=='female') echo 'checked'; else echo '';?>
"> Female<br />
<input type="submit" name="select sex" value="Submit" />
</form>
</body>
For checkbox, not mentioned checked attribute for any of the check box option.
For submit button, normally we are not using the space in field name and this is the best practice. Though you have used then you have written the wrong code. Please check below updated code line for if statement.
if(isset($_POST['select sex']))
I have an array of checkboxes name="box[]". Through PHP I make sure that they're checked after they're submitted by echoing "checked='checked'" if they were checked at submit event.
Now, if I check the third box, the value jumps down to the first checkbox after submit, since the array was empty up until the third checkbox. Same, if I check the 2nd and 3rd checkbox, they jump down to 1st and 2nd after submit. This is the code I'm using:
<form method="post">
<input type="checkbox" name="box[]" value="true" <?php if ($box[0] == true) echo "checked='checked'"; ?>><br>
<input type="checkbox" name="box[]" value="true" <?php if ($box[1] == true) echo "checked='checked'"; ?>><br>
<input type="checkbox" name="box[]" value="true" <?php if ($box[2] == true) echo "checked='checked'"; ?>><br>
<p>
<input type="submit" value="Submit">
</form>
Try it at:
http://experiencerapanui.com/selecttest.php
Can I make the checkboxes fill up the array with a value "false" or whatever, if the box is unchecked? Which way should I go?
****** EDIT ******
Thanks to phant0m, I managed to come up with a solution:
<form method="post">
<input type="checkbox" name="box[]" value="1" <?php if (in_array("1", $box)) echo "checked='checked'"; ?>><br>
<input type="checkbox" name="box[]" value="2" <?php if (in_array("2", $box)) echo "checked='checked'"; ?>><br>
<input type="checkbox" name="box[]" value="3" <?php if (in_array("3", $box)) echo "checked='checked'"; ?>><br>
<p>
<input type="submit" value="Submit">
</form>
Putting unique values for the checkboxes, then if I find the value in the array $box[], the box is marked as checked.
This does not work, because only those checkboxes, that are checked, are being put into the $box array.
Either use different names, or different values to distinguish between them.
Consider this: You check the second and the third checkbox. In PHP, you will receive:
$_POST['box'] = array(0 => "true", 1 => "true");
You cannot know, which checkboxes have been checked, unless all of them are.
The POST value should start with isset, then !empty($array) determines if the POST value is an array and prevents a null array error when no options are selected.
&& is_array($_POST['box']) could be used in addition to !empty($_POST['box']) as well to check the validity of the array.
A variable is used in the following examples for the value field, as it makes it easier to define and populate inputs when using a foreach loop and may be sanitized if needed as a preventive measure.
It would probably be a good idea to sanitize the $_POST array also, and enclosing it in a function with the validation would allow it all to be called from the checkbox input and keep the input area tidy.
<input type="checkbox" name="box[]" value="<?php echo $unique_id; ?>" <?php if(isset($_POST['box']) && !empty($_POST['box']) && in_array($unique_id, $_POST['box'])) echo "checked='checked'"; ?>>
OR
<input type="checkbox" name="box[]" value="<?php echo $unique_id; ?>" <?php my_function(); ?>>
Excellent question and solutions! There seem to be relatively few examples that use an array method to preserve Post selections, and the one provided here is relevant and very helpful even years later.
How do I check a checkbox?
I've tried 1, On, and Yes. That doesn't work. Putting the worked "checked" alone works, but then how do I check with PHP after a form post of the checkbox is checked?
<input type="checkbox" class="inputcheckbox" id="newmsg" name=chk[newmsg2] value="1" />
A checkbox will only be a successful control if it is checked.
Controls that are not successful are not submitted as data.
Therefore, you can tell if a checkbox is checked by seeing if its value has been submitted.
E.g.
if ($_POST['chk']['newmsg2'] == 1) {
<input type="checkbox" class="inputcheckbox" id="newmsg" name=chk[newmsg2] value="1" <?php if ($_POST['chk']['newmsg2']): ?>checked="checked"<?php endif; ?> />
Here is the code;
<form action="test.php" method="POST">
<input type="checkbox" class="inputcheckbox" id="newmsg" name=chk[newmsg2] value="1" />
<input type="submit">
</form>
<?php
$check = $_POST['chk']['newmsg2'];
echo "***$check****"
?>
If it is checked $check will show 1.