I am working on an API endpoint that returns a list of users that have all of the given services ID's.
In my case:
Users can have many services
Tables: 'users', 'services', 'service_user'
I am passing an array via Vue JS to my end point for example:
/endpoint/32,35,38
My query is currently:
$servicesArray = explode(',', $services);
$users = User::whereHas('services', function ($query) use ($servicesArray) {
foreach ($servicesArray as $key => $value) {
$query->where('id', $value);
}
})
->get();
The issue is that it seems to return now results, even if a user does have the correct services. My relationship is fine, and if I only pass one service to the endpoint it correctly returns a user that has that service assigned. I used whereIn before, but I need to only show users that have ALL of the services specified in the endpoint array.
Any obvious reason why what I have is not working as expected?
I would try something like this:
$q = User::query();
foreach ($servicesArray as $key => $value) {
$q->whereHas('services', function ($query) use ($value) {
$query->where('id', $value);
});
}
$users = $q->get();
You can also use laravel hasmany realationship function for getting multiple records from other table.
Example:
---In your Controller use query like.
$users = User::with('services')->where('id', $value)->get();
---And in your model's class use function services like this.
function services(){
return $this->hasMany('App\Service','user_id','id');
}
Related
I do a specific relation query all over the application, where I only need the User's subscriptions that have active column set to true.
And I have a scope method in User model, which applies said filter, to avoid copy/paste, like:
public function scopeWithActiveSubscriptions($query)
{
$query->with([
'subscriptions' => function ($query) {
$query->where('active', true);
},
]);
}
Now sometimes I want to eager-load the plan of each subscription, too.
For that I tried something like:
$user = User::where('id', 1)
->withActiveSubscriptions()
->with('subscriptions.plan')
->first();
$subscriptionList = $user->subscriptions;
But query results to all subscriptions,
in other words, ignores the ->where('active', true) part (of scope method).
How can I make this work correctly?
A quick solution would be modifying the scopeWithActiveSubscriptions method to allow it to accept another optional parameter that tells it which additional relations should also be included and thus you don't loose your filtering.
public function scopeWithActiveSubscriptions($query, array $with = [])
{
// just merges hard coded subscription filtering with the supplied relations from $with parameter
$query->with(array_merge([
'subscriptions' => function ($query) {
$query->where('active', true);
}
], $with));
}
Now you can tell that scope which nested relations you want to include and you no longer need to call with to include them by yourself.
$user = User::where('id', 1)
->withActiveSubscriptions(['subscriptions.plan'])
// ->with('subscriptions.plan') // no longer needed as we're telling the scope to do that for us
->first();
$subscriptionList = $user->subscriptions;
With that you can pass custom relations to the scope something like (am improvising here just for demo purposes)
$user = User::where('id', 1)
->withActiveSubscriptions([
'subscriptions.plan' => fn($q) => $q->where('plans.type', 'GOLD')
])->first();
Learn more about Laravel's Eloquent Scopes.
Hope i have pushed you further.
Seems Laravel does not have yet any chainable (Builder-style) solution (for asked situation), and we ended up editing the scope filter.
Into something like:
public function scopeWithPendingSubscriptions(Builder $query, $subRelations = null)
{
$query->with([
'subscriptions' => function (HasMany $query) use ($subRelations) {
$query->where('active', '=', true);
if ($subRelations) {
$query->with($subRelations);
}
},
]);
}
Which allows me to do query like:
// ...
->withActiveSubscriptions('plan');
Instead of my old (not working) code, which was:
// ...
->withActiveSubscriptions()
->with('subscriptions.plan');
Note that even passing nested-filters is now possible, like:
// ...
->withActiveSubscriptions(['plan' => function ($query) {
$query->where('name');
}]);
(Basically same as Laravel's ->with(...) method.)
Let's say I have the relation: Role has many Users. Role and user stores a code value.
If I want to select all roles that have users with same code, how would be this query using whereHas clause?
What I tried:
$roles = Role::whereHas('users', function ($users) {
// Obviously doesn't work but it is what I need to access.
$code = $users->first()
->role
->code;
return $users->where('code', $code);
})->get();
Use this:
$roles = Role::whereHas('users', function ($query) {
$query->whereColumn('users.code', 'roles.code');
})->get();
i am trying to query many to many relation for my get api call. i have three table as shown here but i am not using pivot table.
This is my Projects model class and this the function
public function projectRewd()
{
return $this
->belongsToMany('App\Rewards','rewards','project_id','reward_id');
}
And this is my Rewards model class and function
public function projectShip()
{
return $this->belongsToMany('App\Shipping_location','shipping_location','projects_id','rewards_id');
}
This is my api controller function
Route::get('projects/{id}', function($id) {
$proj = Projects::whereHas('projectRewd', function($q)
{
$q->where('id', $id);
});
return $proj;
});
i am using this link for api call
http://localhost:8000/api/projects/1
i want to extract rewards data and shipping_location data associate with project_id.
i am getting this error
"message": "Object of class Illuminate\\Database\\Eloquent\\Builder could not be converted to string"
i check and tried all related error from different post.
i also search and tried many technique. Cant solve my problem.
Please suggest me how to do this??
can i do this type of query in larvel without using pivot table??
You are getting Builder model because you forgot to add ->first() or ->get().
You should write:
$proj = Projects::whereHas('projectRewd', function($q){
$q->where('id', $id);
})->first();
Your closure-based controller returns your query-builder object. Not a project. You need to retrieve results from the query by fetching e.g. the first result (->first()) or all (->get()).
Route::get('projects/{id}', function($id) {
$proj = Projects::whereHas('projectRewd', function($q)
{
$q->where('id', $id);
})->first();
return $proj;
});
Referencing $id:
The reason why $id is unknown, is that the closure doesn't know about it.
You can pass it to the closure using use(...).
Route::get('projects/{id}', function($id) {
$proj = Projects::whereHas('projectRewd', function($q) use ($id)
{
...
Further:
Your whereHas query looks incorrect to me:
$q->where('id', $id);
Apparently $id is the project id. But the 'id' column in projectRewd is the primary key of projectRewd (unless you have modified the defaults).
I assume you want to query all projects that have at least one projectRewd:
Route::get('projects/{id}', function($id) {
$proj = Projects::has('projectRewd')->first();
return $proj;
});
And if you want to eager load the joined tables:
Route::get('projects/{id}', function($id) {
$proj = Projects::with('projectRewd. projectShips')->has('projectRewd')->first();
return $proj;
});
I have 3 models
User
Pick
Schedule
I'm trying to do something like the following
$picksWhereGameStarted = User::find($user->id)
->picks()
->where('week', $currentWeek)
->first()
->schedule()
->where('gameTime', '<', Carbon::now())
->get();
This code only returns one array inside a collection. I want it to return more than 1 array if there is more than 1 result.
Can I substitute ->first() with something else that will allow me to to return more than 1 results.
If not how can I set up my models relationship to allow this to work.
My models are currently set up as follow.
User model
public function picks()
{
return $this->hasMany('App\Pick');
}
Schedule model
public function picks()
{
return $this->hasMany('App\Pick');
}
Pick model
public function user()
{
return $this->belongsTo('App\User');
}
public function schedule()
{
return $this->belongsTo('App\Schedule');
}
Since you already have a User model (you used it inside you find method as $user->id), you can just load its Pick relationship and load those Picks' Schedule as follows:
EDIT:
Assuming you have a schedules table and your picks table has a schedule_id column. Try this.
$user->load(['picks' => function ($q) use ($currentWeek) {
$q->join('schedules', 'picks.schedule_id', '=', 'schedules.id')
->where('schedules.gameTime', '<', Carbon::now()) // or Carbon::now()->format('Y-m-d'). See what works.
->where('picks.week', $currentWeek);
}])->load('picks.schedule');
EDIT: The code above should return the user's picks which have a schedules.gameTime < Carbon::now()
Try it and do a dump of the $user object to see the loaded relationships. That's the Eloquent way you want.
Tip: you may want to do $user->toArray() before you dump $user to see the data better.
EDIT:
The loaded picks will be in a form of Collections so you'll have to access it using a loop. Try the following:
foreach ($user->picks as $pick) {
echo $pick->schedule->gameTime;
}
If you only want the first pick from the user you can do: $user->picks->first()->schedule->gameTime
I think a foreach loop may be what you're looking for:
$picks = User::find($user->id)->picks()->where('week', $currentWeek);
foreach ($picks as $pick){
$pickWhereGameStarted = $pick->schedule()->where('gameTime', '<', Carbon::now())->get();
}
Try this and see if it's working for you
I have a tag system, where you can add tags to photos and users.
I have a function where the users are able to add their favorite tags, and select images based on those tags
But my problem i am a really big beginner with php and laravel and i do not know how to pass the values to the whereIn function
Model
public function tag()
{
return $this->belongsToMany('Tag', 'users_tag');
}
Controller
// get the logged in user
$user = $this->user->find(Auth::user()->id);
// get tags relation
$userTags = $user->tag->toArray();
// select photos based on user tags
$photos = Photo::whereHas('tag', function($q) use ($userTags)
{
$q->whereIn('id', $userTags);
})->paginate(13);
$trendyTags = $this->tag->trendyTags();
$this->layout->title = trans('tag.favorite');
$this->layout->content = View::make('main::favoritetags')
->with('user', $user)
->with('photos', $photos)
->with('trendyTags', $trendyTags);
When i pass i get an error
preg_replace(): Parameter mismatch, pattern is a string while replacement is an array
than i tried to use array_flatten() to clean my array
// get the logged in user
$user = $this->user->find(Auth::user()->id);
// get tags relation
$userTags =array_flatten($user->tag->toArray());
// select photos based on user tags
$photos = Photo::whereHas('tag', function($q) use ($userTags)
{
$q->whereIn('id', $userTags);
})->paginate(13);
$trendyTags = $this->tag->trendyTags();
$this->layout->title = trans('tag.favorite');
$this->layout->content = View::make('main::favoritetags')
->with('user', $user)
->with('photos', $photos)
->with('trendyTags', $trendyTags);
This way it works but not returning the correct tags.
Could please someone could lend me a hand on this?
Sure thing and I'll make a couple recommendations.
To get the user model, you simply have to use $user = Auth::user().
To use whereIn(), it's expecting a 1 dimensional array of user id's. The toArray() function is going to return an array of associative arrays containing all the users and their properties, so it's not going to work quite right. To get what you need, you should use lists('id').
And one last thing that has really helped me is when you are setting up a relation that's going to return a collection of objects (hasMany, belongsToMany()), make the relation name plurual, so in this case you would modify your tag() function to tags().
So with all that in mind, this should work for you.
// get the logged in user
$user = Auth::user();
// get tags relation
$userTags = $user->tags()->lists('id');
// select photos based on user tags
$photos = Photo::whereHas('tags', function($q) use ($userTags)
{
$q->whereIn('id', $userTags);
})->paginate(13);
$trendyTags = $this->tags->trendyTags();
$this->layout->title = trans('tag.favorite');
$this->layout->content = View::make('main::favoritetags')
->with('user', $user)
->with('photos', $photos)
->with('trendyTags', $trendyTags);
And I'd suggest to modify your relation to... though not hugely important.
public function tags()
{
return $this->belongsToMany('Tag', 'users_tag');
}