I have a tag system, where you can add tags to photos and users.
I have a function where the users are able to add their favorite tags, and select images based on those tags
But my problem i am a really big beginner with php and laravel and i do not know how to pass the values to the whereIn function
Model
public function tag()
{
return $this->belongsToMany('Tag', 'users_tag');
}
Controller
// get the logged in user
$user = $this->user->find(Auth::user()->id);
// get tags relation
$userTags = $user->tag->toArray();
// select photos based on user tags
$photos = Photo::whereHas('tag', function($q) use ($userTags)
{
$q->whereIn('id', $userTags);
})->paginate(13);
$trendyTags = $this->tag->trendyTags();
$this->layout->title = trans('tag.favorite');
$this->layout->content = View::make('main::favoritetags')
->with('user', $user)
->with('photos', $photos)
->with('trendyTags', $trendyTags);
When i pass i get an error
preg_replace(): Parameter mismatch, pattern is a string while replacement is an array
than i tried to use array_flatten() to clean my array
// get the logged in user
$user = $this->user->find(Auth::user()->id);
// get tags relation
$userTags =array_flatten($user->tag->toArray());
// select photos based on user tags
$photos = Photo::whereHas('tag', function($q) use ($userTags)
{
$q->whereIn('id', $userTags);
})->paginate(13);
$trendyTags = $this->tag->trendyTags();
$this->layout->title = trans('tag.favorite');
$this->layout->content = View::make('main::favoritetags')
->with('user', $user)
->with('photos', $photos)
->with('trendyTags', $trendyTags);
This way it works but not returning the correct tags.
Could please someone could lend me a hand on this?
Sure thing and I'll make a couple recommendations.
To get the user model, you simply have to use $user = Auth::user().
To use whereIn(), it's expecting a 1 dimensional array of user id's. The toArray() function is going to return an array of associative arrays containing all the users and their properties, so it's not going to work quite right. To get what you need, you should use lists('id').
And one last thing that has really helped me is when you are setting up a relation that's going to return a collection of objects (hasMany, belongsToMany()), make the relation name plurual, so in this case you would modify your tag() function to tags().
So with all that in mind, this should work for you.
// get the logged in user
$user = Auth::user();
// get tags relation
$userTags = $user->tags()->lists('id');
// select photos based on user tags
$photos = Photo::whereHas('tags', function($q) use ($userTags)
{
$q->whereIn('id', $userTags);
})->paginate(13);
$trendyTags = $this->tags->trendyTags();
$this->layout->title = trans('tag.favorite');
$this->layout->content = View::make('main::favoritetags')
->with('user', $user)
->with('photos', $photos)
->with('trendyTags', $trendyTags);
And I'd suggest to modify your relation to... though not hugely important.
public function tags()
{
return $this->belongsToMany('Tag', 'users_tag');
}
Related
I want to select all the users in my table "User" except the first One cause its the admin,
im using this function index in my controller but it doesn't work .
public function index()
{
// this '!=' for handling the 1 row
$user = User::where('id', '!=', auth()->id())->get();
return view('admin.payroll',compact('user'))->with(['employees' => User::all()]);
}
Better to used here whereNotIn Method
Note: first you find the admin role users and create a static array
$exceptThisUserIds = [1];
$user = User::whereNotIn('id', $exceptThisUserIds)->get();
It's not a good idea to specify the admin user with just id. A better design would be using some sort of a flag like is_admin as a property of your User model.
Still you can use the following code to get the users who have an id greater than 1:
User::where('id', '>', 1)->get()
For getting data skipping the first one you should use skip() method and follow the code like below
public function index()
{
$user = User::orderBy('id','asc')->skip(1)->get();
return view('admin.payroll',compact('user'))->with(['employees' => User::all()]);
}
I have a User model which has the following method:
public function articles()
{
return $this->hasMany('App\Article');
}
And also Article model, which has:
public function user()
{
return $this->belongsTo('App\User');
}
I want to return a list of users that contains each of thems articles. So with this one:
// only returns list of users
return $user = User::all();
And with the following:
$user = User::all();
foreach ($user[0]->articles as $article) {
return $article;
}
I only get the first one's articles. Is there any way (in laravel) to retrieve the whole list with each one's articles?
you need to call with method to eager load all articles.
$user = User::with('articles')->get();
dd($user);
or if you want to lazy load then.
$user = User::get();
dd($user->articles());
you can use select() to select specific columns - for example
$user = User::select('name','email')->get();
if you want to select specific columns in with() then
$user = User::with(['articles' => function($query){
$query->select('id','title');
}])->get();
or
$user = User::with(['articles' => function($query){
$query->select('id','title');
}])->select('name','email')->get();
The issue here is that you return inside the foreach loop, which will stop the loop after the first iteration, and therefore only return the first article.
If you want to show the user and articles in a JSON response, you should look at Eloquent Resources, Writing Resources, especially the Relationships part of that chapter.
public function getTourDetail(Request $req)
{
//Get link detail
$tour = Tour::where('id',$req->id)->first();
//I want to take location.city of the location table
$detail = Tour::join('location','tour.id_location','=','location.id')
->whereColumn([
['tour.id_location','=','location.id']
])
->get(array(
'tour.id as id_tour',
'location.image',
'tour.name',
'tour.id_location',
'location.city'
));
return view('page.tour-detail',compact('tour','detail'));
}
I would like to be able to combine two query statements to get information from the location table ($ detail) like the id of the link request ($ tour).
Since you use models, you can use Eloquent relationships to load related data. First, define a relationship in the Tour model:
public function location()
{
return $this->belongsTo(Location::class, 'id_location')
}
Then load Tour and get related location:
$tour = Tour::find($req->id);
$relatedLocation = $tour->location;
First thing, if you are using model then using eloquent relationship will be a better idea to deal with the situation like yours. But if you want to join your table then this will be the way:
public function getTourDetail($id)
{
$tour = Tour::where('id',$id)->first();
//I want to take location.city of the location table
$detail = DB::table('location')
->join('tour','tour.id_location','=','location.id')
->select(
'tour.id as id_tour',
'location.image',
'tour.name',
'tour.id_location',
'location.city'
)->get();
return view('page.tour-detail',compact('tour','detail'));
}
Note: if you are getting id from submitted form then replace first portion of the code with:-
public function getTourDetail(Request $request)
{
$tour = Tour::where('id',$request->id)->first();
I have a user model that it has a collection of posts.
I want to return a collection of users data with their's posts except an especial post for each user as json; for that I user this code:
$users=User::with('posts')->get();
foreach($users as $user){
$user->posts=$user->posts->except($except_id);
// $user->posts=null;// ->>> also this code does not work
}
return $users;
But in output users' posts are not changed!!!
Edited:
$except_id = $user->golden_post_id;
I tried some ways finally I found that unset() can solve the problem.
This code works:
$users=User::with('posts')->get();
foreach($users as $user){
$posts=$user->posts->except($except_id);
unset($user->posts);
$user->posts=$post;
}
return $users;
You should probably do that as a query constraint in the with call instead, e.g. like this:
$users = User::with(['posts' => function($query) use ($except_id) {
$query->where('id', '!=', $except_id);
}])->get();
Now you get all posts for all users except the posts with the id of $except_id, and you don't have to go through them afterwards to sort them out.
In my Laravel app, I have the concept of users, friends, and groups. A user can create and sort friends into groups.
A user can have many friends:
function friendsOfMine()
{
return $this->belongsToMany('App\User', 'helpers', 'user_id', 'helper_id')
->wherePivot('accepted', '=', 1);
}
A group can have many users:
public function groupMembers()
{
return $this->belongstoMany('App\User')->withTimestamps();
}
In the UI for adding friends to a group, I want to show the full list of a user's friends, but exclude those friends that have already been added to the group. My Groups Controller function looks like this, though I'm positive I'm off-base.
public function add($id)
{
$group = Group::findOrFail($id);
$helpers = $group->groupMembers;
$id = $helpers->lists('id');
$invitees = $this->user
->friendsOfMine()
->where('helper_id', '!=', $id)
->Paginate(5);
return view('groups.add', compact('group','helpers','invitees'));
}
Ideally, what I'd love is some way to write:
$helper = $group->friendsOfMine->not->groupMembers->Paginate(5);
Is there anyway to filter data using functions from two different models?
With your approach you would have to use whereNotIn() since you have an array of ids:
$id = $helpers->lists('id');
$invitees = $this->user
->friendsOfMine()
->whereNotIn('helper_id', $id)
->Paginate(5);
However you probably could something like this as well (assuming the relation group)
$invitees = $this->user
->friendsOfMine()
->whereDoesntHave('group', function($q) use ($id){
$q->where('group_id', $id); // Note that id is the group id (not the array of ids from the helper)
})
->Paginate(5);
For a nicer syntax (like in your example) you should look into Query Scopes