AJAX Response and PHP Loop - php

I am using PHP to retrieve some records from a MySQL database, I would like to send these to my AJAX and loop through them, in order to prepend rows to an existing table.
However I can only see the last (most recent) record returned from my query. Could someone please point out where I am going wrong?
AJAX:
$.ajax({
type: "POST",
url: 'feed.php',
data: {lastSerial: true},
dataType: 'json',
success: function(data){
console.log(data); // logs `{Direction: "O", CardNo: "02730984", SerialNo: 20559303}`
$.each(data, function(key, value) {
// here I want to loop through the returned results - for example
$("#transactionTable").prepend('<tr><td>'+ SerialNo +'</td><td>'+ CardNo +'</td><td>'+ Direction +'</td></tr>');
});
}
});
feed.php
if(isset($_POST['lastSerial']) && $_POST['lastSerial'] == true) {
$query = "SELECT TimeStamp, Direction, CardNo, SerialNo FROM Transactions";
// this query returns approx. 20 results
$stmt = $conn->prepare($query);
$stmt->execute();
$result = $stmt->get_result();
while($row = $result->fetch_assoc()) {
$data["Direction"] = $row['Direction'];
$data["CardNo"] = $row['CardNo'];
$data["SerialNo"] = $row['SerialNo'];
}
echo json_encode($data);
}
Also in my PHP, should I be using a while or if statement?

You're using a single $data object and resetting its contents each time. You want to build an array of objects:
$data = array();
while($row = $result->fetch_assoc()) {
$data[] = array(
"Direction" => $row['Direction'],
"CardNo" => $row['CardNo'],
"SerialNo" => $row['SerialNo']
);
}
echo json_encode($data);
Followed by:
success: function(data) {
$.each(data, function(key, value) {
$("#transactionTable").prepend(
'<tr><td>' + value.SerialNo + '</td>' +
'<td>' + value.CardNo + '</td>' +
'<td>'+ value.Direction +'</td></tr>');
});
}

In your feed.php you loop through the results, but on each loop you overwrite the data. Thus, you are only returning the last result from the database to the AJAX request.
Many solutions exist, but you have to do something like
$data["Direction"][] = $row['Direction'];
$data["CardNo"][] = $row['CardNo'];
$data["SerialNo"][] = $row['SerialNo'];
or better:
$data[] = $row;
Since you dont change the key, you can use the last option. With jQuery you can loop over it, and access the data with value.Direction, value.CardNo, value.SerialNo
note: not tested

Related

Select multiple rows into array and send them via AJAX

I am trying to run a SELECT query in PHP and then multiple rows are selected, but I need to fetch them into an array and then use: echo json_encode($array). After That I need to get this array into AJAX.
Here is the PHP code:
$val = $_POST['data1'];
$search = "SELECT * FROM employee WHERE emp_name = :val OR salary = :val OR date_employed = :val";
$insertStmt = $conn->prepare($search);
$insertStmt->bindValue(":val", $val);
$insertStmt->execute();
$insertStmt->fetchAll();
//echo "success";
//$lastid = $conn->lastInsertId();
$i = 0;
foreach($insertStmt as $row)
{
$arr[$i] = $row;
$i++;
}
echo json_encode($arr);
The problem is that I can't get all the lines of this array into AJAX so I can append them into some table. Here is the script:
var txt = $("#txtSearch").val();
$.ajax({
url: 'search.php', // Sending variable emp, pos, and sal, into this url
type: 'POST', // I will get variable and use them inside my PHP code using $_POST['emp']
data: {
data1: txt
}, //Now we can use $_POST[data1];
dataType: "json", // text or html or json or script
success: function(arr) {
for() {
// Here I don't know how to get the rows and display them in a table
}
},
error:function(arr) {
alert("data not added");
}
});
You need to loop over your "arr" data in the success callback. Something along the lines of:
var txt = $("#txtSearch").val();
$.ajax
({
url: 'search.php', //Sending variable emp, pos, and sal, into this url
type: 'POST', //I will get variable and use them inside my PHP code using $_POST['emp']
data: {data1: txt},//Now we can use $_POST[data1];
dataType: "json", //text or html or json or script
success:function(arr)
{
var my_table = "";
$.each( arr, function( key, row ) {
my_table += "<tr>";
my_table += "<td>"+row['employee_first_name']+"</td>";
my_table += "<td>"+row['employee_last_name']+"</td>";
my_table += "</tr>";
});
my_table = "<table>" + my_table + "</table>";
$(document).append(my_table);
},
error:function(arr)
{
alert("data not added");
}
});
You could just return
json_encode($insertStmt->fetchAll());
Also, be sure to retrieve only characters in UTF-8 or JSON_encode will "crash".
Your success function should be like this :
success:function(arr)
{
$.each(arr,function (i,item) {
alert(item.YOUR_KEY);
});
}

Printing Specific JSON array elements in Javascript

A PHP script obtains data from a MySQL database and returns an array to javascript using JSON. I can get the results but I cannot get them to print them out individually.
The PHP code -
header('Content-type:application/json');
$link = #new mysqli(_HOST, _USER, _PASS, _DB); //constants
if(mysqli_connect_errno())
{
//failure
}
else
{
//success
$sqlQuery = "SELECT COL1, COL2 FROM TABLE"; //the query should return two
//columns from every selected row
$mix = array(); //array to return using JSON
$result = $link->query($sqlQuery);
if ($result->num_rows <= 0)
{
//no data
}
else
{
while ($row = $result->fetch_assoc()) //fetch loop
{
$mix["C1"][] = $row['COL1'];
$mix["C2"][] = $row['COL2'];
}
}
$result->free();
// Close connection
$link->close();
}
print json_encode($mix); //this line wont show up in previous code formatting block for some reason.
The Javascript / jQuery code -
$.ajax({ // ajax call
url: 'serv.php', // server page
data: 'fetch=1', //ignore any data
dataType: 'json', // server return type
success: function(data) // on success
{
for (var i in data) {
$('#someDiv').append( i + " = " + data[i] + '<br>');
}
}
});
The output, as expected is like this -
C1 = 1,2
C2 = A,B
What I want to accomplish is to put these data (1,2,A,B) inside a form table element. And to do that I need to pick the every element of C1 or C2 individually.
How can I accomplish this?
I've found the solution myself.
The following ajax call works-
$.ajax({ // ajax call
url: 'serv.php', // server page
data: 'fetch=1', //ignore any data
dataType: 'json', // server return type
success: function(data) // on success
{
for (var i in data["C1"]) {
$('#someDiv').append( i + " = " + data["C1"][i] + '<br>');
}
for (var i in data["C2"]) {
$('#someDiv').append( i + " = " + data["C2"][i] + '<br>');
}
}
});
Instead of accessing the data, I've tried to access the indices inside data. It was so simple.

returning multiple variables in JSON/PHP

Basically, i'm using an JSON response from a local PHP file to append data inside a div, currently it's only returning one variable, in which the code i'm using is shown here :
$.ajax({
url: "functions/ajax.php",
data: "func=auto",
type: "GET",
dataType: "json",
success: function(data){
$.each(data.search, function (i, v) {
$div = $('.bs-docs-example');
$div.append('+ v +');
});
},
error: function (jqXHR, textStatus, errorThrown){
console.log('Error ' + jqXHR);
}
});
The code which is returning the JSON is currently
while($row = mysql_fetch_assoc($res)) {
$search[] = $row['number'];
}
echo json_encode($search);
What i want to do is something like this
while($row = mysql_fetch_assoc($res)) {
$search[] = $row['number'];
$search[] = $row['name'];
}
echo json_encode($search);
But if i was to do the following, how would i access both number and name since in the success on the jQuery it's parsing using $.each(data.search, function (i, v) { which means the original $search[] = $row['number'] is now stored inside v
would i do something like v['name'] v['number'] or is that completely wrong ?
You'll want to pass an associative array to json_encode:
$search['number'] = $row['number'];
$search['name'] = $row['name'];
json_encode($search);
Or, if there will be multiple rows of results, as an array of associative arrays:
while($row = mysql_fetch_assoc($res)) {
$search[] = $row;
}
And then access the values in JavaScript by name:
var name = v['name'];
Or
var name = v[0]['name']
If you're using multiple rows of results.

How to get MySQL data into correct array structure

I just finished getting a script to work by using a hard coded array like so:
dataArray[0] =[50,10,0.3,0.25,50,"FFF",3];
dataArray[1] =[50,10,0.3,0.2,50,"FFF",3];
....
dataArray[5] =[50,20,0.5,0.7,120,"FF0",4];
I put the contents of dataArray into a db table so I could eliminate the hard coded array.
I'm returning the data in a string from MySql with PHP, and a data dump shows that the number of values and the values themselves are correct.
However, I'm apparently not coding the data capture correctly because I'm not ending up with an array like my hard coded array (I need to maintain the structure of my hard coded array).
Here's the code for the db read:
function getSomeData(){
$.ajax({
type: "GET",
url: "GetSomeData.php",
dataType: "text",
success:function(result){
setSomeData(result);
}
});
}
var someDataArray = new Array();
function setSomeData(resultData){
var resData = resultData.split('^');//record split
for(var i = 0; i < resData.length; i++){
someDataArray[i] = resData[i].split('#');//field split
someDataArray[i].pop();//removes array element occupied by '^'
if(i == resData.length - 1){
setDataArray();
}
}
}
This for loop in setDataArray() doesn't create the correct array structure because someDataArray[x] is just a string:
var dataArray = new Array();
function setDataArray(){
for(var i = 0; i < dataArray.length; i++){
dataArray[i] = someDataArray[i];
}
}
So I tried putting someDataArray[x] in an array like so:
dataArray[i] = [someDataArray[i]];
But that didn't work either.
I've spent the 2 days trying to puzzle this out, reading blogs, and experimenting with everything I could think of, but no luck. I think it's a simple solution but I just can't get it.
Help?
EDIT:
After learning a bit about JSON and json_encode I now have my script working. I wanted to post the way I did it to acknowledge that I received some valuable advice from Pat Burke. The code below may not be what he had in mind but I massaged it until it worked. But I don't really understand why it works, so I'll have to do some more reading on json_encode I think.
Note that using dataType:"json" in the ajax call threw an error.
//GetSomeData.php
$return_arr = array();
$query1 = "SELECT * FROM mytable ORDER BY idx ASC";
$result = mysql_query($query1) or die('Query failed: ' . mysql_error());
while($row = mysql_fetch_array($result)){
$resultArray = array();
$resultArray[] = (int)$row['dc'];
$resultArray[] = (int)$row['smlspc'];
$resultArray[] = (float)$row['sclx'];
$resultArray[] = (float)$row['scly'];
$resultArray[] = (int)$row['lgspc'];
$resultArray[] = (int)$row['colr'];
$resultArray[] = (int)$row['diam'];
if(count($resultArray) == 7){
array_push($return_arr, $resultArray);
}
}
echo json_encode($return_arr);
mysql_free_result($result);
//new js
function getSomeData(){
resultData = new Array();
$.ajax({
type: "GET",
url: "GetSomeData.php",
dataType: "text",
//dataType: "json", //using this threw an error (see below)
success:function(result){
resultData = $.parseJSON(result);
$("#p1").append("resultData.length =" + resultData.length + "<br />");
//resultData.length =114 (it's a string not an array)
$("#p1").append("resultData =" + resultData + "<br />");
//resultData =
//[[50,10,0.375,0.25,50,0,0],
//[50,10,0.3,0.2,50,0,1],
//[50,10,0.6,0.4,0,0,2],
//[50,0,0.4,0.4,0,0,3],
//[50,0,0.4,0.4,0,0,3]]
for(var i = 0; i < resultData.length; i++){
$("#p1").append("resultData[" + i + "] =" + resultData[i] + "<br />");
//data displayed with dataType: "text"
//resultData[0] =50,10,0.375,0.25,50,0,0
//resultData[1] =50,10,0.3,0.2,50,0,1
//resultData[2] =50,10,0.6,0.4,0,0,2
//resultData[3] =50,0,0.4,0.4,0,0,3
//resultData[4] =50,0,0.4,0.4,0,0,3
//data displayed with dataType: "json"
//resultData is null
}
},
//this has no effect with either dataType: "text" or dataType: "json"
contentType: 'application/json'
});
}
if someDataArray[i] is a string of values separated by commas, you could do
dataArray[i] = someDataArray[i].split(',')

is php json_encode & AJAX breaking my array?

I'm grabbing some database entries, creating a 2D array and then passing them to js with AJAX. But when I loop through the array in javascript, it's an "undefined" mess. The console log for dbArray works fine, so I know the PHP/AJAX is working. Not sure what I am doing wrong with the loop...
PHP ('load-words.php):
$query = mysql_query("
SELECT * FROM words
ORDER BY RAND()
LIMIT 50
") or die(mysql_error());
$dbArray = array();
while ($row = mysql_fetch_assoc($query)) {
$word_phrase = stripslashes($row['word_phrase']);
$description = stripslashes($row['description']);
// construct a 2D array containing each word and description
$dbArray[] = array($word_phrase,$description);
};
echo json_encode($dbArray);
Javascript:
$.ajax({
url: 'func/load-words.php',
success: function(dbArray) {
console.log(dbArray);
var items = "<ul>";
for (var i in dbArray) {
items += "<li><a href='#'><b>" + dbArray[i][0] + ' : ' + dbArray[i][1] + "</a></li>";
}
items += "</ul>";
div = $('#dbArray');
div.html(items);
}
});
I guess this is failing because jQuery is interpreting the AJAX response as a string, since your PHP is not outputting a JSON header and your AJAX is not stipulating JSON. This is easily tested:
$.ajax({
url: 'func/load-words.php',
success: function(dbArray) { alert(typeof dbArray); /* "string"? */ }
});
Try
$.ajax({
url: 'func/load-words.php',
dataType: 'json', //<-- now we explicitly expect JSON
success: function(dbArray) { alert(typeof dbArray); /* "object"? */ }
});

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