Laravel paginate, changing the query string to search - php

Currently trying to paginate some results on a product object.
The paginate object that I am receiving in my view {{ $products->links() }} is returning correctly however instead of the query being "test.com/search?search=test&page2" it is returning "test.com/search?query=test&page2" how can i change it so it returns search instead of query?
The html output is:
2
but what i need is:
2
EDIT:
Controller:
public function searchable(Request $request)
{
// search database, with result, list on page, with links to products,
$products = Product::search($request->search)->paginate(3);
return view('search.index', compact('products', 'request'));
}
use Laravel\Scout\Searchable;
use Illuminate\Database\Eloquent\Model;
use Carbon\Carbon;
class Product extends Model
{
use Searchable;
/**
* Creates searchable index for product model
* #return [type] [description]
*/
public function searchableAs()
{
return 'products_index';
}
}
form:
{{ Form::open(array('url' => '/search', 'method' => 'GET', 'files' => 'false')) }}
<div class="row">
<div class="col-md-2">
<button type="submit" class="custom-search-button btn btn-lrg btn-primary">Search</button>
</div>
<div class="col-md-10">
<input class="search-bar" type="search" name="search" placeholder="type keyword(s) here" />
</div>
</div>
{{-- <input type="hidden" name="${_csrf.parameterName}" value="${_csrf.token}"/> --}}
{{ Form::close() }}

You have field named query in your search form. Change its name to search, adjust logic in controller to be using search param instead of query and you are done.

Related

i'm trying to create a search method by name but it showing this error

I'm very confused, I need your help, this is the error:
Missing required parameter for [Route: single.temp] [URI: singlepost/{name}] [Missing parameter: name]. (View: C:\Users\Toshiba\Desktop\working\mouhawla\resources\views\index.blade.php)
The search field:
<div class="search">
<form role="form" action="{{route('single.temp')}}">
<i class="fa fa-search"></i>
<div class="field-toggle">
<input type="text" name="name" class="search-form" autocomplete="off" placeholder="Search">
</div>
</form>
</div>
The method:
public function getPostByName($name) {
$products = DB::table('templates')
->where('name', $name)
->first();
return view('singlepost', compact('products'));
}
The route:
Route::get('/singlepost/{name}', 'App\http\controllers\TemplatesController#getPostByName')->name('single.temp');
The final view:
<h1 style="text-align: center;">ACH-template</h1>
<table>
<tr>
<td><img src="/storage/{{$products->image_path}}"></td>
<td><img src="/storage/{{$products->image_path2}}"></td>
<td><img src="/storage/{{$products->image_path3}}"></td>
<td>
<p>
<h2 style="text-align:center;">{{$products->name}}</h2>
</br>
<p>{{$products->description}}</p>
</p>
</td>
</tr>
</table>
<a href="/storage/{{$products->file_path}}" class="btn btn-primary">
<button class="btn" style="width:100%">
<i class="fa fa-download"></i> Download
</button>
</a>
The error is very explanatory. You are trying to use /singlepost/{name} route, but on your blade file, you are doing route('single.temp'), it is telling you that it needs the parameter name, else it cannot create the URL as it is a missing parameter.
You should have something like:
<form role="form" action="{{route('single.temp', ['name' => VALUE'])}}">
But that will not solve your problem, as you are trying to do a search, so you want something like /singlepost/John, and John is going to be input by the user on the input field. So you have to do an AJAX call because {{ route('single.temp') }} is going to be rendered by PHP and served to the user, so it is always going to miss the needed parameter.
What you can also do is get that value from the Request instead of a URL parameter.
You have defined a route which requires a parameter: {$name}. You have also used the route helper to generate a URL which takes the name of a route as the first argument and an array of parameters as an optional second argument.
When you have used route('single.temp') in your form action, you have not specified any parameters and so Laravel is throwing the error you're seeing. To resolve this error, you would need to specify a $name parameter as the second argument (i.e. route('single.temp', ['name' => 'something'])). This is not ideal though as if you're using $name as a search term, you don't know the value when the page is first rendered and so can't provide that value.
There are a few ways you could achieve your goal of searching records, a basic example of how you could do this follows.
web.php
Define two routes, the first to return a view with a form and another to process the form submission and show the results.
Route::get('/templates', [TemplateController::class, 'index'])
->name('templates.index');
Route::get('/templates/search', [TemplateController::class, 'search')
->name('templates.search');
TemplateController.php
Define the two functions which will be used when one of the routes defined above is requested.
class TemplateController extends Controller
{
// return a view
public function index()
{
return view('templates.search', ['templates' => []]);
}
// process the form submission
// perform a search for the $request search term
// return a view with the results
public function search(Request $request)
{
$request->validate([
'term' => ['required', 'string']
]);
$templates = Template::where('name', $request->term)->get();
return view('templates.search', ['templates' => $templates]);
}
}
templates/search.blade.php
{{-- create a form which will submit to the search route --}}
{{-- note I use GET rather than POST here, explained later --}}
<form action="{{ route('templates.search') }}" method="GET">
#csrf
<input type="text" id="term" name="term" />
<button type="submit">
{{ __('Search') }}
</button>
{{-- loop over and show results if there are any --}}
#forelse ($templates as $template)
{{ $template->name }}
#empty
{{ __('Empty') }}
#endforelse
</form>
The above should be self explanatory. My reason for using GET rather than POST in the search is because the value will be added to the URL as a query string parameter meaning it can be bookmarked or shared with ease.

The PUT method is not supported for this route. Supported methods: GET, HEAD, POST, DELETE. (note I am using model biding)

I am using model biding, but I am basically trying to create a form that can edit and update comments. It runs perfectly and even prompts me to edit the form. However, every time I try to update it the POST method is not supported for the root. which is bogus as I did the spoofing correctly, someone help me please.
Here us my CommentsController methods
public function edit($id)
{
$comment = Commenting::find($id);
return view('comments.edit', compact('comment'));
}
public function update(Request $request, $id, $posts)
{
$comment = Commenting::find($id);
$comment->update($request->all());
$comment->posts_id = $posts;
return view('post.show', compact('comment'));
}
Here is the routing in my web.php
Route::get('/posts/comment/{comment}', 'CommentsController#edit')->name('comments.edit')->middleware('auth');
Route::put('/posts/comment/{comment}', 'CommentsController#update')->name('comments.update')->middleware('auth');
Here's what I call the link to edit the form in my show.blade
Edit
lastly this is my edit.blade file
#extends ('layouts.home')
#section ('content')
<div class="card">
<h1> Edit Comment </h1>
<div class="card-block">
<form method="POST" action="{{route('comments.update', ['comments' => $comment])}}">
#csrf
#method('PUT')
<div class="form-group">
<textarea name="body" placeholder="Enter you comment here..." class="form-control"> {{$comment->body}}</textarea>
</div>
<div class="form-group">
<button type="submit" class="btn btn-success">Update</button>
</div>
</form>
#include ('layouts.errors')
</div>
</div>
#endsection
Take a look your update method
public function update(Request $request, $id, $posts)
Try to delete the $posts variable on update function
Try
{{method_field('put')}}
or
<input type="hidden" name="_method" value="PUT">
add patch method in blade file:
#extends ('layouts.home')
#section ('content')
<div class="card">
<h1> Edit Comment </h1>
<div class="card-block">
<form method="POST" action="{{route('comments.update', ['comments' => $comment])}}">
{{ csrf_field() }}
<input type="hidden" name="_method" value="PATCH">
<div class="form-group">
<textarea name="body" placeholder="Enter you comment here..." class="form-control"> {{$comment->body}}</textarea>
</div>
<div class="form-group">
<button type="submit" class="btn btn-success">Update</button>
</div>
</form>
#include ('layouts.errors')
</div>
</div>
#endsection
write post method in route file :
Route::post('/posts/comment/{comment}', 'CommentsController#update')->name('comments.update')->middleware('auth');
Your route binding is named comment not comments. This will not generate a URL to your comments.update route:
route('comments.update', ['comments' => $comment])
This will generate a URL to /posts/comment?comments=3 not /posts/comment/3. You want to use the same name as the route parameter so it knows to replace that route parameter:
route('comments.update', ['comment' => $comment])
Which would generate a URL to /posts/comment/3.
Also your controller method
public function update(Request $request, $id, $posts)
has a $posts variable but there is no parameter for that defined for the route, so where does that come from?
If you actually want to use Model Binding, which it would appear you are not, you could use Implicit Bindings by type-hinting a $comment argument on that controller method:
public function update(Request $request, Comment $comment)
as the route pararemeter is named comment not id.
Laravel 5.8 - Routing - Route Model Binding - Implicit Binding

Laravel Search function

i have a question about the Laravel search function, i had follow the guildeline online and i still fail to search the category, can someone guide me and tell me where i did wrongly ? Much appreciated
My category Controller php code:
public function search(Request $request)
{
$search = $request->get('search');
$posts = DB::table('bit_app_policy_category')->where('id','like','%' .$search. '%')->paginate(5);
return view('category.index',['posts' => $posts]);
}
My index.blade code
<div align="left">
<div class="col-md-4">
<h1>Policy</h1>
</div>
<div class="col-md-4">
<form action="/search" method="get" role="search">
{{ csrf_field() }}
<div class="input-group">
<input type="text" class="form-control" name="_method" placeholder="Search ID / Code"> <span class="input-group-btn">
<button type="submit" class="btn btn-primary">Search</button></span>
</div>
</form>
</div>
</div>
web.php
Route::get('/search','categoryController#search');
What error i get is here
Error image
interface
Database
You are sending $posts variable to your view. But the error says you are referencing a $category variable.
return view('category.index',['posts' => $posts]);
Maybe you might want to update view to use $posts. If you could post your full code (category/index.blade.php) we might be able to help you better.
__
Here is how I would do:
$categories= DB::table('bit_app_policy_category')->where('id','like','%' .$search. '%')->paginate(5);
return view('category.index',['categories' => $categories]); //you can also use compact return view('category.index', compact('categories') );
And to display:
#foreach( $categories as $category )
<div>{{ $category->id }}</div>
#endforeach
Another tip: you can name your routes like so
Route::get('search','categoryController#search')->name('search');
Then you can reference this route (in form or anywhere else you want) like so:
<form action="{{ route('search') }}" ..>

How to solve the problem of getting unusual id in laravel

Here is my routes
Route::get('add-members/{id}','MemberController#create');
Route::post('save-member/{id}','MemberController#store');
This is my code to show the create form
public function create($id)
{
$team=Team::find($id);
$users = User::doesntHave('teams')->whereHas('roles', function($role) {
$role->where('name', 'member');
})->get();
return view('members.create',compact('users','team'));
}
An this is my code to store it
public function store(Request $request,$id)
{
$team=Team::find($id);
dd($request->id);
$team->users()->attach($request->id);
return redirect('home');
}
and this is my blade file
#extends('layouts.app')
#section('content')
<form action="{{url('save-member',$team->id)}}" method="post" accept-charset="utf-8">
#csrf
<div class="form-group row">
<label for="name" class="col-md-4 col-form-label text-md-right">{{ __('Select Member/s') }}</label>
<div class="col-md-6">
#foreach($users as $key => $user)
<input type="checkbox" name="id[]" value="{{$user->id}}">{{$user->email}}<br>
#endforeach
#error('member_id')
<span class="invalid-feedback" role="alert"><strong><font
color="red">{{ $message }}</font></strong></span>
#enderror
</div>
</div>
<button type="submit" class="btn btn-primary">Save</button>
</form>
#endsection
Now when i select none of the user and just click save button it will save the the user id as 1. After i am doing dd($request->id) it will show me the output 1. But in my form there is no users left or my form is empty.So where from 1 is coming. you can see this picture for clearify.
Please help me to solve this problems
You should be more specific with what data you are requesting from the Request:
$request->id; // could be an input named 'id' or a route parameter named 'id'
$request->input('id'); // is an input
$request->route('id'); // is a route parameter
You are running into a situation where you have a route parameter named id and potentially an input named id. Using the dynamic property of the Request, $request->id, will return the input id if it is there, if not it falls back to returning a route parameter named id.
Here is an article from the past that shows the issue with not being specific about what you are trying to get from the Request object:
asklagbox - blog - watch out for request

Adding input query to route value for search function Laravel Scout

Trying to set up basic search functionality for products. I am having trouble sorting the route parameter variable and passing the query string to the search function.
Route::get('/search/{query?}', 'ProductController#searchable');
This works and returns a query when I input the query manually.
Controller
public function searchable($query)
{
// search database, with result, list on page, with links to products,
$products = Product::search($query)->get();
return view('search.index', compact('products'));
}
However, I would like it to come from the URL /search?test.
My form shows:
{{ Form::open(array('action' => 'ProductController#searchable', 'method' => 'get', 'files' => 'false')) }}
<input type="search" name="search" placeholder="type keyword(s) here" />
<button type="submit" class="btn btn-primary">Search</button>
{{ Form::close() }}`
I am new to Laravel and need a little help. I am using Laravel Scout and TNTSearch.
You don't need to user {wildcard} for searching. We have Request for that
Route::get('search', 'ProductController#searchable');
Pass the url instead.
{{ Form::open(array('url' => 'search', 'method' => 'GET', 'files' => 'false')) }}
<input type="search" name="search" placeholder="type keyword(s) here" />
<button type="submit" class="btn btn-primary">Search</button>
{{ Form::close() }}
In Controller simple fetch $request->search
public function searchable(Request $request)
{
// search database, with result, list on page, with links to products,
$products = Product::search($request->search)->get();
return view('search.index', compact('products'));
}

Categories