Laravel Search function - php

Question

i have a question about the Laravel search function, i had follow the guildeline online and i still fail to search the category, can someone guide me and tell me where i did wrongly ? Much appreciated
My category Controller php code:
public function search(Request $request)
{
$search = $request->get('search');
$posts = DB::table('bit_app_policy_category')->where('id','like','%' .$search. '%')->paginate(5);
return view('category.index',['posts' => $posts]);
}
My index.blade code
<div align="left">
<div class="col-md-4">
<h1>Policy</h1>
</div>
<div class="col-md-4">
<form action="/search" method="get" role="search">
{{ csrf_field() }}
<div class="input-group">
<input type="text" class="form-control" name="_method" placeholder="Search ID / Code"> <span class="input-group-btn">
<button type="submit" class="btn btn-primary">Search</button></span>
</div>
</form>
</div>
</div>
web.php
Route::get('/search','categoryController#search');
What error i get is here
Error image
interface
Database

Answer 1

You are sending $posts variable to your view. But the error says you are referencing a $category variable.
return view('category.index',['posts' => $posts]);
Maybe you might want to update view to use $posts. If you could post your full code (category/index.blade.php) we might be able to help you better.
__
Here is how I would do:
$categories= DB::table('bit_app_policy_category')->where('id','like','%' .$search. '%')->paginate(5);
return view('category.index',['categories' => $categories]); //you can also use compact return view('category.index', compact('categories') );
And to display:
#foreach( $categories as $category )
<div>{{ $category->id }}</div>
#endforeach
Another tip: you can name your routes like so
Route::get('search','categoryController#search')->name('search');
Then you can reference this route (in form or anywhere else you want) like so:
<form action="{{ route('search') }}" ..>