Separate string with explode php - php

I am using explode in PHP, because I need to separate a string. of this type:
$Data = '10 x 4';
I need to separate the numbers because then I do a math operation on them . The code I have works well when they are integers. If I have a string of this type 10 x 2.5 it does not take into account the decimal part that would be the , 5. How can I do to make me take this part into account too?
$data = '10 x 2,5';
$array = explode("x", $data);
$total = $array[0]*$array[1];

Here are two approaches you could take. If you can change the comma separator to a period/full stop:
$data = '10 x 2.5';
$floats = array_map('floatval', explode(' x ', $data));
echo $floats[0] * $floats[1];
Demo: https://3v4l.org/hFMEt
or you could use a regex which also will confirm you have the right data format.
echo preg_replace_callback('/(\d+(?:[.,]\d+)?)\h*x\h*(\d+(?:[.,]\d+)?)/', function($match) {
return str_replace(',' , '.', $match[1]) * str_replace(',' , '.', $match[2]);
}, $data);
PHP Demo: https://3v4l.org/I82Gt
Regex Demo: https://regex101.com/r/tTcJSp/1/

Try with this. Just replace "," with "." and it's working.
$data = '10 x 2,5';
$data = str_replace(',','.','10 x 2,5');
$array = explode("x", $data);
echo $total = $array[0]*$array[1];

try this:
<?php
$data = '10 x 2,5';
$array = explode("x", $data);
$total = floatval(str_replace(',', '.', $array[0]))*floatval(str_replace(',', '.', $array[1]));
?>
here str_replace() is used to check if there are ,
in the string and then convert into its float value.
Hope this helps.

$data = '10 x 2,5';
$array = explode("x", $data);
$decimal =$array[1];
//replace the comma with dot
$decimal_formated = str_replace(',', '.', $decimal);
//format the string to float
$decimal_formated = (float)$decimal_formated;
//OR $decimal_formated = floatval($decimal_formated);
//get total
$total = $array[0]*$decimal_formated;
//french format $total, with comma
$total_with_comma =number_format($total, 1, ',', ' ');
echo $decimal.'</br>'; //output 2,5
echo $decimal_formated.'</br>'; //output 2.5
echo $total.'</br>'; //output 25
echo $total_with_comma.'</br>'; // output 25,0
You can use number_format(), floatval().

Related

Modify decimal point and thousands separator without changing the number of decimals

I'm new to php and I'm trying to use number_format :
number_format ( float $number , int $decimals = 0 , string $dec_point = "." , string $thousands_sep = "," )
As in the title, my goal is to modify decimal point and thousands separator without changing the number of decimals as below:
$Num=123456.789;
$Num2=number_format ($Num, [decimals as in $Num], ",", "'" );
My result should be:
$Num2="123'456,789";
Edit
I need a code for an unknown number of decimals
You can use NumberFormatter.
You will still need to specify a certain amount of fraction digits, but you can just use a high enough value and be fine. It's not like the number of digits is really arbitrary. It's tied to your precision ini setting.
$formatter = new NumberFormatter("en_US", NumberFormatter::DECIMAL);
$formatter->setAttribute(NumberFormatter::MAX_FRACTION_DIGITS, 42);
$formatter->setSymbol(NumberFormatter::GROUPING_SEPARATOR_SYMBOL, "'");
$formatter->setSymbol(NumberFormatter::DECIMAL_SEPARATOR_SYMBOL, ",");
echo $formatter->format(123456.7891234); // 123'456,7891234
Demo https://3v4l.org/TCAIA
You can do it such a way (firstly take a look to #Gordon answer – it's much more better):
<?php
function extendedNumberFormat($num, $decimalSeparator, $thousandSeparator) {
$asStr = strval($num);
$exploded = explode('.', $asStr);
$int = $exploded[0];
$decimal = isset($exploded[1]) ? $exploded[1] : null;
$result = number_format($int, 0, ".", $thousandSeparator);
if ($decimal !== null) {
$result .= $decimalSeparator . $decimal;
}
return $result;
}
echo extendedNumberFormat(123456.789, ',', "'") . "\n";
echo extendedNumberFormat(123456.7891, ',', "'") . "\n";
echo extendedNumberFormat(123456, ',', "'") . "\n";
//123'456,789
//123'456,7891
//123'456

Get range letter and number with php

how can I get range for bottom string in php?
M0000001:M0000100
I want result
M0000001
M0000002
M0000003
..
..
..
M0000100
this is what i do
<?php
$string = "M0000001:M0000100";
$explode = explode(":",$string );
$text_one = $explode[0];
$text_two = $explode[1];
$range = range($text_one,$text_two);
print_r($range);
?>
So can anyone help me with this?
This is one of many ways you could do this and this is a little verbose but hopefully it shows you some "steps" to take.
It doesn't check for the 1st number being bigger than the 2nd.
It doesn't check your Range strings start with a "M".
It doesn't have all of the required comments.
Those are things for you to consider and work out...
<?php
$string = "M00000045:M000099";
echo generate_range_from_string($string);
function generate_range_from_string($string) {
// First explode the two strings
$explode = explode(":", $string);
$text_one = $explode[0];
$text_two = $explode[1];
// Remove the Leading Alpha character
$range_one = str_replace('M', '', $text_one);
$range_two = str_replace('M', '', $text_two);
$padding_length = strlen($range_one);
// Build the output string
$output = '';
for ( $index = (int) $range_one; $index <= (int) $range_two; $index ++ ) {
$output .= 'M' . str_pad($index, $padding_length, '0', STR_PAD_LEFT) . '<br>';
}
return $output;
}
The output lists a String in the format you have specified in the question. So this is based solely upon that.
This could undergo a few more revisions to make it more function like, as I'm sure some folks will pick out!

Add commas as thousands separator and floating point dot in php

I have this
$example = "1234567"
$subtotal = number_format($example, 2, '.', '');
the return of $subtotal is "1234567.00"
how to modify the definition of $subtotal, make it like this "1,234,567.00"
Below will output 1,234,567.00
$example = "1234567";
$subtotal = number_format($example, 2, '.', ',');
echo $subtotal;
Syntax
string number_format ( float $number , int $decimals = 0 , string $dec_point = '.' , string $thousands_sep = ',' )
But I advise you to use money_format which will formats a number as a currency string
You have many options, but money_format can do the trick for you.
// Example:
$amount = '100000';
setlocale(LC_MONETARY, 'en_IN');
$amount = money_format('%!i', $amount);
echo $amount;
// Output:
"1,00,000.00"
Please note that money_format() is only defined if the system has strfmon capabilities. For example, Windows does not, so it is undefined in Windows.
Final edit: Here's a pure PHP Implementation that will work on any system:
$amount = '10000034000';
$amount = moneyFormatIndia( $amount );
echo number_format($amount, 2, '.', '');
function moneyFormatIndia($num){
$explrestunits = "" ;
if(strlen($num)>3){
$lastthree = substr($num, strlen($num)-3, strlen($num));
$restunits = substr($num, 0, strlen($num)-3); // extracts the last three digits
$restunits = (strlen($restunits)%2 == 1)?"0".$restunits:$restunits; // explodes the remaining digits in 2's formats, adds a zero in the beginning to maintain the 2's grouping.
$expunit = str_split($restunits, 2);
for($i=0; $i<sizeof($expunit); $i++){
// creates each of the 2's group and adds a comma to the end
if($i==0){
$explrestunits .= (int)$expunit[$i].","; // if is first value , convert into integer
}else{
$explrestunits .= $expunit[$i].",";
}
}
$thecash = $explrestunits.$lastthree;
} else {
$thecash = $num;
}
return $thecash; // writes the final format where $currency is the currency symbol.
}
Ref: http://php.net/manual/en/function.money-format.php
string money_format ( string $format , float $number )
ex:
// let's print the international format for the en_US locale
setlocale(LC_MONETARY, 'en_US');
echo money_format('%i', $number) . "\n";
// USD 1,234.56
Note: The function money_format() is only defined if the system has strfmon capabilities. For example, Windows does not, so money_format() is undefined in Windows.
Note: The LC_MONETARY category of the locale settings, affects the behavior of this function. Use setlocale() to set to the appropriate default locale before using this function.
Use number_format : http://www.php.net/manual/en/function.number-format.php
string number_format ( float $number , int $decimals = 0 , string $dec_point = '.' , string $thousands_sep = ',' )
$number = 123457;
$format_number = number_format($number, 2, '.', ',');
// 1,234.57

Add space after every 4th character

I want to add a space to some output after every 4th character until the end of the string.
I tried:
$str = $rows['value'];
<? echo substr($str, 0, 4) . ' ' . substr($str, 4); ?>
Which just got me the space after the first 4 characters.
How can I make it show after every 4th ?
You can use chunk_split [docs]:
$str = chunk_split($rows['value'], 4, ' ');
DEMO
If the length of the string is a multiple of four but you don't want a trailing space, you can pass the result to trim.
Wordwrap does exactly what you want:
echo wordwrap('12345678' , 4 , ' ' , true )
will output:
1234 5678
If you want, say, a hyphen after every second digit instead, swap the "4" for a "2", and the space for a hyphen:
echo wordwrap('1234567890' , 2 , '-' , true )
will output:
12-34-56-78-90
Reference - wordwrap
Have you already seen this function called wordwrap?
http://us2.php.net/manual/en/function.wordwrap.php
Here is a solution. Works right out of the box like this.
<?php
$text = "Thiswordissoverylong.";
$newtext = wordwrap($text, 4, "\n", true);
echo "$newtext\n";
?>
Here is an example of string with length is not a multiple of 4 (or 5 in my case).
function space($str, $step, $reverse = false) {
if ($reverse)
return strrev(chunk_split(strrev($str), $step, ' '));
return chunk_split($str, $step, ' ');
}
Use :
echo space("0000000152748541695882", 5);
result: 00000 00152 74854 16958 82
Reverse mode use ("BVR code" for swiss billing) :
echo space("1400360152748541695882", 5, true);
result: 14 00360 15274 85416 95882
EDIT 2021-02-09
Also useful for EAN13 barcode formatting :
space("7640187670868", 6, true);
result : 7 640187 670868
short syntax version :
function space($s=false,$t=0,$r=false){return(!$s)?false:(($r)?trim(strrev(chunk_split(strrev($s),$t,' '))):trim(chunk_split($s,$t,' ')));}
Hope it could help some of you.
On way would be to split into 4-character chunks and then join them together again with a space between each part.
As this would technically miss to insert one at the very end if the last chunk would have exactly 4 characters, we would need to add that one manually (Demo):
$chunk_length = 4;
$chunks = str_split($str, $chunk_length);
$last = end($chunks);
if (strlen($last) === $chunk_length) {
$chunks[] = '';
}
$str_with_spaces = implode(' ', $chunks);
one-liner:
$yourstring = "1234567890";
echo implode(" ", str_split($yourstring, 4))." ";
This should give you as output:
1234 5678 90
That's all :D
The function wordwrap() basically does the same, however this should work as well.
$newstr = '';
$len = strlen($str);
for($i = 0; $i < $len; $i++) {
$newstr.= $str[$i];
if (($i+1) % 4 == 0) {
$newstr.= ' ';
}
}
PHP3 Compatible:
Try this:
$strLen = strlen( $str );
for($i = 0; $i < $strLen; $i += 4){
echo substr($str, $i, 4) . ' ';
}
unset( $strLen );
StringBuilder str = new StringBuilder("ABCDEFGHIJKLMNOP");
int idx = str.length() - 4;
while (idx > 0){
str.insert(idx, " ");
idx = idx - 4;
}
return str.toString();
Explanation, this code will add space from right to left:
str = "ABCDEFGH" int idx = total length - 4; //8-4=4
while (4>0){
str.insert(idx, " "); //this will insert space at 4th position
idx = idx - 4; // then decrement 4-4=0 and run loop again
}
The final output will be:
ABCD EFGH

Replacing last x amount of numbers

I have a PHP variable that looks a bit like this:
$id = "01922312";
I need to replace the last two or three numbers with another character. How can I go about doing this?
EDIT Sorry for the confusion, basically I have the variable above, and after I'm done processing it I'd like for it to look something like this:
$new = "01922xxx";
Try this:
$new = substr($id, 0, -3) . 'xxx';
Result:
01922xxx
You can use substr_replace to replace a substring.
$id = substr_replace($id, 'xxx', -3);
Reference:
http://php.net/substr-replace
function replaceCharsInNumber($num, $chars) {
return substr((string) $num, 0, -strlen($chars)) . $chars;
}
Usage:
$number = 5069695;
echo replaceCharsInNumber($number, 'xxx'); //5069xxx
See it in action here: http://codepad.org/XGyVQ1hk
Strings can be treated as arrays, with the characters being the keys:
$id = 1922312; // PHP converts 01922312 => 1 because of that leading zero. Either make it a string or remove the zero.
$id_str = strval($id);
for ($i = 0; $i < count($id_str); $i++)
{
print($id_str[$i]);
}
This should output your original number. Now to do stuff with it, treat it as a normal array:
$id_str[count($id_str) - 1] = 'x';
$id_str[count($id_str) - 2] = 'y';
$id_str[count($id_str) - 3] = 'z';
Hope this helps!
Just convert to string and replace...
$stringId = $id . '';
$stringId = substr($id, 0, -2) . 'XX';
We can replace specific characters in a string using preg_replace(). In my case, I want to replace 30 with 50 (keep the first two digits xx30), in the $start_time which is '1030'.
Solution:
$start_time = '1030';
$pattern = '/(?<=\d\d)30/';
$start_time = preg_replace($pattern, '50', $start_time);
//result: 1050

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