Add space after every 4th character - php

Question

I want to add a space to some output after every 4th character until the end of the string.
I tried:
$str = $rows['value'];
<? echo substr($str, 0, 4) . ' ' . substr($str, 4); ?>
Which just got me the space after the first 4 characters.
How can I make it show after every 4th ?

Answer 1

You can use chunk_split [docs]:
$str = chunk_split($rows['value'], 4, ' ');
DEMO
If the length of the string is a multiple of four but you don't want a trailing space, you can pass the result to trim.

Answer 2

Wordwrap does exactly what you want:
echo wordwrap('12345678' , 4 , ' ' , true )
will output:
1234 5678
If you want, say, a hyphen after every second digit instead, swap the "4" for a "2", and the space for a hyphen:
echo wordwrap('1234567890' , 2 , '-' , true )
will output:
12-34-56-78-90
Reference - wordwrap

Answer 3

Have you already seen this function called wordwrap?
http://us2.php.net/manual/en/function.wordwrap.php
Here is a solution. Works right out of the box like this.
<?php
$text = "Thiswordissoverylong.";
$newtext = wordwrap($text, 4, "\n", true);
echo "$newtext\n";
?>

Answer 4

Here is an example of string with length is not a multiple of 4 (or 5 in my case).
function space($str, $step, $reverse = false) {
if ($reverse)
return strrev(chunk_split(strrev($str), $step, ' '));
return chunk_split($str, $step, ' ');
}
Use :
echo space("0000000152748541695882", 5);
result: 00000 00152 74854 16958 82
Reverse mode use ("BVR code" for swiss billing) :
echo space("1400360152748541695882", 5, true);
result: 14 00360 15274 85416 95882
EDIT 2021-02-09
Also useful for EAN13 barcode formatting :
space("7640187670868", 6, true);
result : 7 640187 670868
short syntax version :
function space($s=false,$t=0,$r=false){return(!$s)?false:(($r)?trim(strrev(chunk_split(strrev($s),$t,' '))):trim(chunk_split($s,$t,' ')));}
Hope it could help some of you.

Answer 5

On way would be to split into 4-character chunks and then join them together again with a space between each part.
As this would technically miss to insert one at the very end if the last chunk would have exactly 4 characters, we would need to add that one manually (Demo):
$chunk_length = 4;
$chunks = str_split($str, $chunk_length);
$last = end($chunks);
if (strlen($last) === $chunk_length) {
$chunks[] = '';
}
$str_with_spaces = implode(' ', $chunks);

Answer 6

one-liner:
$yourstring = "1234567890";
echo implode(" ", str_split($yourstring, 4))." ";
This should give you as output:
1234 5678 90
That's all :D

Answer 7

The function wordwrap() basically does the same, however this should work as well.
$newstr = '';
$len = strlen($str);
for($i = 0; $i < $len; $i++) {
$newstr.= $str[$i];
if (($i+1) % 4 == 0) {
$newstr.= ' ';
}
}

Answer 8

PHP3 Compatible:
Try this:
$strLen = strlen( $str );
for($i = 0; $i < $strLen; $i += 4){
echo substr($str, $i, 4) . ' ';
}
unset( $strLen );

Answer 9

StringBuilder str = new StringBuilder("ABCDEFGHIJKLMNOP");
int idx = str.length() - 4;
while (idx > 0){
str.insert(idx, " ");
idx = idx - 4;
}
return str.toString();
Explanation, this code will add space from right to left:
str = "ABCDEFGH" int idx = total length - 4; //8-4=4
while (4>0){
str.insert(idx, " "); //this will insert space at 4th position
idx = idx - 4; // then decrement 4-4=0 and run loop again
}
The final output will be:
ABCD EFGH