I am getting some data from a database, and it returns an array $rows as shown below:
However the returned rows doesn't contain a pure array with the CV data. I would like just to have a pure array which has only the values.
My code:
$sql = 'SELECT CATEGORY_VALUE from '.self::TABLE_NAME. ' where E_ID = :E_ID and C_TYPE = :C_TYPE';
$where = array('E_ID'=>$id, 'C_TYPE'=> $c);
$stmt = $this->_db->query($sql,$where);
$rows = $stmt->fetchAll();
return $rows;
I think you have misunderstanding of how php arrays work. You can learn more here. http://php.net/manual/en/language.types.array.php
In PHP, you would get the value you want by doing the following:
$rows[0]['CATEGORY_VALUE'] will return 'H3
You need to use PDO::FETCH_COLUMN.
$rows = $stmt->fetchAll(PDO::FETCH_COLUMN);
Related
I have a file file.php and inside my file I am using the code bellow to pull some data from my database and display some information.
My code is
$array = $_GET['theurl']; // My url looks like myfile.php?theurl=1,2,3 (id,s)
$sqlnt4 = "select * from mytable WHERE `id` IN ($array)";
$rsdt4 = mysql_query($sql);
$tc4a = mysql_fetch_assoc($rsdt4);
$mycomma4 = ",";
if ($tc4a['a_youtube'] == "#"){
}else{
while ($tc4 = mysql_fetch_assoc($rsdt4))
{
echo $tc4['a_youtube'];
echo ",";
}
}
I expect to echo the infos of the two id's (in array) inside my while function, but it returns the results only from the first.
Any ideas?
I am confusing on $sql :
$sqlnt4 = "select * from mytable WHERE `id` IN ($array)";
$rsdt4 = mysql_query($sql);
Can you take a look after changing below:
$sqlnt4 = "select * from mytable WHERE `id` IN ($array)";
$rsdt4 = mysql_query($sqlnt4);
First that's extremely vulnerable to security issues - I hope this isn't used in production and just for playing around.
I recommend switching to PDO, or at the very least securing your variables.
To put that array into the query, you need to implode it into a list, as such.
$list = implode(',', $array);
You can then use the list in the statement, which will look like 1,2,3.
Edit:
I've just realized your $array value isn't actually an array - have you missed code out or is it badly named?
mysql_fetch_assoc: "Returns an associative array that corresponds to the fetched row and moves the internal data pointer ahead." http://pt2.php.net/mysql_fetch_assoc
Try mysql_fetch_rows to return all matching rows into an array.
I try to retrieve a array from one table What is wrong with this code?
$_fbexclude = mysql_query("SELECT fbempfang FROM fbinvite WHERE fbreturn = '1' ");
$fbexcludearray= mysql_fetch_array($_fbexclude);
// Convert the array
$excludes = implode(',', $fbexcludearray);
From echo $excludes; It only gives me just the following response: 1000033xxx161,1000033xxx161 Twice the same fbempfang
See if the following gives you what you want (FIXED):
$_fbexclude = mysql_query("SELECT fbempfang FROM fbinvite WHERE fbreturn = '1'");
$fbexcludearray = array();
while ($row = mysql_fetch_assoc($_fbexclude)) {
$fbexcludearray[] = $row['fbempfang'];
}
// Convert the array
$excludes = implode(',', $fbexcludearray);
mysql_fetch_array() and it's siblings (_assoc, _row) only retrieve one row at a time. This means that your original code will only give you the first returned row - to work around this, we use the loop you see above.
The reason you see the same data twice is because mysql_fetch_array() returns a mixed indexed and associative array, which contains all the data twice over. For this reason, it is much better to use mysql_fetch_assoc() or mysql_fetch_row(), as you rarely need both formats.
In fact, it is much better to use mysqli, but the same information applies to that as well.
Use right SQL query:
SELECT GROUP_CONCAT(`fbempfang`) as imploded from `fbinvite` WHERE fbreturn = '1'
It's return string as PHP implode(',', array(…));
Try this on for size:
$implode_arr = array();
$_fbexclude = mysql_query("SELECT fbempfang
FROM fbinvite
WHERE fbreturn = '1'");
while($row = mysql_fetch_array($_fbexclude)) {
$implode_arr[] = $row['fbempfang'];
}
// Convert the array
$excludes = implode(',', $implode_arr);
You need to loop over the mysql_fetch_* functions because they only return one of the result rows at a time. For more information and examples see the manual page for mysql_fetch_assoc().
I'm selecting a single column from a MySQL table with mysql_query(). Is there already a function for getting the results into an array, or will I have to iterate through all the results with something like mysql_fetch_array()?
You have to iterate.
If you moved into the 21st century, and used mysqli, there's a mysqli_fetch_all() function.... and you'd be able to use prepared statements
you can do this with mysqli_fetch_all and array_column
$r = mysqli_query($c,"SELECT bug_name FROM bugs WHERE color='red'");
$bug_names = array_column(mysqli_fetch_all($r,MYSQLI_ASSOC),"bug_name");
Nothing like that built in, you will need to do this manually.
you can use mysql_result function still need to do some coding
mysql_result($result,$row_num,$fieldname) ;
retrieves $row_num 'th columes $field_name field .
and following snippet can be taken as an example
$con =mysql_connect($host,$uname,$passwd);
mysql_select_db($dbname,$con);
$result = mysql_query($query,$con);
$arr = array();
$numrows = mysql_num_rows($result);
for($i=0;$i<$numrows;$i++) {
$arr[] = mysql_result($result,$i,$fieldname);
}
this stores every elements of column $fieldname to
array $arr
I have a query that returns a few rows, and I have the following lines of code to retrieve them:
$result_set = mysql_query($query);
while($net_biz_sub_data[]=
mysql_fetch_array($result_set,MYSQL_ASSOC));
My question is what is the right way to retrieve that db query data without getting the last array empty ?
When I count() it is always num of rows + 1, and I would like to correct that.
Because of the way the while loop works, you should do
while($dataz = mysql_fetch_assoc($result_set))
{
$net_biz_sub_data[] = $dataz;
}
Use
$result_set = mysql_query($query);
while($net_biz_sub_data = mysql_fetch_assoc($result_set)){
//use $net_biz_sub_data here
}
can any one know the, convert mysql query in to an php array:
this is mysql query :
SELECT SUM(time_spent) AS sumtime, title, url
FROM library
WHERE delete_status = 0
GROUP BY url_id
ORDER BY sumtime DESC
I want to convert this query in to simple php array .
So, you need to get data out of MySQL. The best way, hands down, to fetch data from MySQL using PHP is PDO, a cross-database access interface.
So, first let's connect.
// Let's make sure that any errors cause an Exception.
// <http://www.php.net/manual/en/pdo.error-handling.php>
PDO::setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
// We need some credentials...
$user = 'username';
$pass = 'password';
$host = 'hostname';
$dbname = 'database';
// PDO wants a "data source name," made up of those credentials.
// <http://www.php.net/manual/en/ref.pdo-mysql.connection.php>
$dsn = "mysql:host={$host};dbname={$dbname}";
$pdo = new PDO($dsn, $user, $pass);
There, we've connected. Let's pretend that $sql has the SQL you provided in your question. Let's run the SQL:
$statement = $pdo->prepare($sql);
$statement->execute();
There, it's been executed. Let's talk about results. You steadfastly refuse to tell us how you want your data structured, so let's go through four ways that you could get your data.
Let's first assume that the query returns a single row. If you want a numerically indexed array, you would do this:
// <http://www.php.net/manual/en/pdostatement.fetch.php>
$array = $statement->fetch(PDO::FETCH_NUM);
unset($statement);
If you want an associative array with the column names as the keys, you would do this:
$array = $statement->fetch(PDO::FETCH_ASSOC);
unset($statement);
Now, what if the query returns more than one record? If we want each row in a numerically indexed array, with each row as an associative array, we would do this:
// <http://www.php.net/manual/en/pdostatement.fetchall.php>
$array = $statement->fetchAll(PDO::FETCH_ASSOC);
unset($statement);
What if we want each row as a numerically indexed array instead? Can you guess?
$array = $statement->fetchAll(PDO::FETCH_NUM);
unset($statement);
Tada. You now know how to query MySQL using the modern PDO interface and get your results as no less than four types of array. There's a tremendous number of other cool things that you can do in PDO with very minimal effort. Just follow the links to the manual pages, which I have quite intentionally not linked for you.
This over-the-top post has been brought to you by the letters T, F and W, and the number PHP_MAX_INT + 1.
i don't get you clearly, but
mysql_fetch_array and mysql_fetch_assoc
both returns only array
please refer:-
http://php.net/manual/en/function.mysql-fetch-array.php
http://php.net/manual/en/function.mysql-fetch-assoc.php
If you just need a simple array...
while ($row = mysql_fetch_array($query)) { //you can assume rest of the code, right?
$result[$row['url_id']] = array($row['sumtime']);
}
For a simple array
$sql = mysql_query("SELECT SUM(time_spent) AS sumtime, title, url
FROM library
WHERE delete_status = 0
GROUP BY url_id
ORDER BY sumtime DESC");
while($row = mysql_fetch_array($sql)){
$array1 = $row['sumtime'];
$array2 = $row['title'];
$array3 = $row['url'];
}
Hope this is one you wanted
Dude the fastest way is probably the following
$data = array();
while($row = mysql_fetch_array($result))
{
$data[] = $row;
}
print_r($data);