mysql query and implode - php

Question

I try to retrieve a array from one table What is wrong with this code?
$_fbexclude = mysql_query("SELECT fbempfang FROM fbinvite WHERE fbreturn = '1' ");
$fbexcludearray= mysql_fetch_array($_fbexclude);
// Convert the array
$excludes = implode(',', $fbexcludearray);
From echo $excludes; It only gives me just the following response: 1000033xxx161,1000033xxx161 Twice the same fbempfang

Answer 1

See if the following gives you what you want (FIXED):
$_fbexclude = mysql_query("SELECT fbempfang FROM fbinvite WHERE fbreturn = '1'");
$fbexcludearray = array();
while ($row = mysql_fetch_assoc($_fbexclude)) {
$fbexcludearray[] = $row['fbempfang'];
}
// Convert the array
$excludes = implode(',', $fbexcludearray);
mysql_fetch_array() and it's siblings (_assoc, _row) only retrieve one row at a time. This means that your original code will only give you the first returned row - to work around this, we use the loop you see above.
The reason you see the same data twice is because mysql_fetch_array() returns a mixed indexed and associative array, which contains all the data twice over. For this reason, it is much better to use mysql_fetch_assoc() or mysql_fetch_row(), as you rarely need both formats.
In fact, it is much better to use mysqli, but the same information applies to that as well.

Answer 2

Use right SQL query:
SELECT GROUP_CONCAT(`fbempfang`) as imploded from `fbinvite` WHERE fbreturn = '1'
It's return string as PHP implode(',', array(…));

Answer 3

Try this on for size:
$implode_arr = array();
$_fbexclude = mysql_query("SELECT fbempfang
FROM fbinvite
WHERE fbreturn = '1'");
while($row = mysql_fetch_array($_fbexclude)) {
$implode_arr[] = $row['fbempfang'];
}
// Convert the array
$excludes = implode(',', $implode_arr);
You need to loop over the mysql_fetch_* functions because they only return one of the result rows at a time. For more information and examples see the manual page for mysql_fetch_assoc().