PHP: check time and output appropriate greeting - php

Question

I am writing a small php program that greets according to the time of day on the server. The rules are as follows:
Between 3:00:00 AM and 11:59:59 AM say Good morning!.
Between 12:00:00 PM and 4:59:59 PM say Good afternoon!.
Between 5:00:00 PM and 2:59:59 AM say Good evening!.
First, to simply matters, I decide to use military time. My program is as follows:
function greetingWord()
$hour = date("G");
if($hour >= 15 && $hour < 24)
{
echo "<p>Good Morning. Today is: </p>";
} else if($hour >= 12 && $hour < 17)
{
echo "<p>Good afternoon. Today is: </p>";
}
else if($hour >= 17 && $hour < 3)
{
echo "<p>Good evening. Today is: </p>";
}
}
my question regards that last else if. I suspect there is something wrong with my logic there so I'd apperciate it if someone would help me out with that final condition, the case of it being between 5pm and 2:59am.
Thank you!
DB

Answer 1

I think the easiest way to do it is leaving the last condition with a simple "else", so:
function greetingWord(){
$hour = date("G");
if($hour > 0 && $hour < 24){
if($hour >= 3 && $hour < 12)
{
echo "<p>Good Morning. Today is: </p>";
}else if($hour >= 12 && $hour < 17){
echo "<p>Good afternoon. Today is: </p>";
}else{
echo "<p>Good evening. Today is: </p>";
}
}
}
Hope it works.

Answer 2

I used ternary operators to display a part of day with a small modification of the code.
function greetingWord(int $hour): string
{
return ($hour >= 3 && $hour < 12)
? "Morning: "
: (($hour >= 12 && $hour < 17) ? "afternoon: " : "evening:");
}
foreach(range(0, 23) as $hour) {
echo "<p> Good " . greetingWord($hour) . " Today is: ". $hour ."</p>\n";
}
//or
echo "<p> Good " . greetingWord((int) date('G')) . " Today is: ". $hour ."</p>\n";