I am trying to read table data and display in on a table the only thing is that i am trying to read it on 2 tables. The 2 tables have the same structure and i have tried it with the code below but nothing happens.
$sql = "SELECT pricedatamt5.symbol_name, pricedatamt5.symbol_bid, pricedatamt5.symbol_ask, pricedatamt4.symbol_bid, pricedatamt4.symbol_ask FROM pricedatamt5 LEFT JOIN pricedatamt4 ON pricedatamt5.symbol_name = pricedatamt4.symbol_name WHERE symbol_name='".$value."'";
$result = mysql_query($sql);
while($row = mysql_fetch_assoc($result))
{
echo "<tr>";
echo "<td>".$row["symbol_date"]."</td>";
echo "<td>".$row["symbol_bid"]."</td>";
echo "<td>".$row["symbol_ask"]."</td>";
echo "</tr>";
}
I hope you can help me with this one because i am really having a hard time especially on retrieving data from 2 tables.
Thanks...
if you need the union your sql query will be:
$sql = "SELECT pricedatamt5.symbol_name, pricedatamt5.symbol_bid, pricedatamt5.symbol_ask FROM pricedatamt5 WHERE symbol_name='".$value."'"."
UNION
SELECT pricedatamt4.symbol_name, pricedatamt4.symbol_bid, pricedatamt4.symbol_ask FROM pricedatamt4 WHERE symbol_name='".$value."'";
otherwise you should clarify your question.
Related
I have one MySQL table and it has two columns -
I want to display in my site like this -
I can easily take the table name Boy | Girl . But when i try to display the table I get like this -
I am just showing one example here. There may be 50 boys and 10 girls.. So I need help.
After displaying the heading
while($row_type = mysql_fetch_array($type))
{
$type_name = $row_type['type_name']; //Boy (or) Girl taking from another table
$type_name = Database::getInstance()->query("SELECT * FROM details WHERE type='type_name'");
echo "<tr>";
while($row_name = mysql_fetch_array($type_name))
{
echo "<td>$row_name[type_name]</td>"; //Displaying the names
}
echo "</tr>";
}
So many views but not getting any answer. Please help guys. Please catch my mistake.
Try with two queries.
Make an array for each category(Male & Female)
It Works.
$maleQuery = mysql_query("SELECT * FROM table WHERE category='male'");
$femaleQuery = mysql_query("SELECT * FROM table WHERE category='female'");
while(($row = mysql_fetch_assoc($maleQuery))) {
$males[] = $row['name'];
}
while(($row = mysql_fetch_assoc($femaleQuery))) {
$females[] = $row['name'];
}
$number_of_rows = max(sizeof($males),sizeof($females));
echo "<table border='1'>";
echo "<tr><td>Male</td><td>Female</td></tr>";
for($i=0;$i<$number_of_rows;$i++)
{
echo "<tr><td>".#$males[$i]."</td><td>".#$females[$i]."</td></tr>";
}
Try this query 100% working but set php code.
SELECT IFNULL(c.Boy,'')AS Boy,IFNULL(c.Girl,'')AS Girl FROM
(SELECT x.name,CASE WHEN (x.category = 'boy') THEN x.name END AS Boy,CASE WHEN (x.category = 'girl') THEN x.name END AS Girl FROM (SELECT * FROM tablename) X)c
Is your problem to do with the creation of the table using PHP or is it related to the SQL query itself?
If it is the creation of the table then I suggest you use two tables embedded in a single table like this. That way you can build the first table using one SQL query, then build the second table using a second query, then display the table and girls and boys will appear side by side regardless of how many entries on each side. Your code would look a bit like this:
echo "<table>
<tr>
<td>
<table>
<tr><th>Boy</th></tr>";
$table = mysql_query("SELECT Name FROM details WHERE Category = 'Boy'") or die(mysql_error());
while($row = mysql_fetch_row($table))
echo "<tr><td>".$row[0]."</td>";
echo "</table>
</td>
<td>
<table>
<tr><th>Girl</th></tr>";
$table = mysql_query("SELECT Name FROM details WHERE Category = 'Girl'") or die(mysql_error());
while($row = mysql_fetch_row($table))
echo "<tr><td>".$row[0]."</td>";
echo "</table>
</td>
</tr>
</table>";
If you need to cater for more categories, do an initial search to determine the distinct categories, then put the section of code above that creates the inner table in a loop.
eg. in pseudo code:
echo the outer table <table><tr>
SELECT DISTINCT Category FROM details
while row1=get next category
$cat = row1[0];
echo "<td>
<table>
<tr><th>".$cat."</th></tr>";
$table = mysql_query("SELECT Name FROM details WHERE Category = '".$cat."'") or die(mysql_error());
while($row = mysql_fetch_row($table))
echo "<tr><td>".$row[0]."</td>";
echo "</table>
</td>
echo the </tr></table> to close the outer table
I'm trying to do nested mysql query but I'm failing
it's as simple as I have a table called 'todo' which is for saving to-do list
when I do
well this code is just to show how I wanna do it logically , I know it doesn't work
and I think it probably needs JOIN or UNION but I couldn't do it
$result = mysqli_query($con,"SELECT type FROM todo WHERE user = '$username' GROUP BY type");
while($row = mysqli_fetch_array($result))
{
echo '<td>- '." ".$row['type'].'</td>';
echo "</br>";
$result2 = mysqli_query($con,"SELECT titleFROM todo WHERE type= '$row['type']'");
while($row = mysqli_fetch_array($result2))
{
echo '<td>-- '." ".$row['title'].'
}
</td>';
echo "</br>";
}
I want the result to like
-Work
--Mr Jack
--Company
-School
--Android Class
--Entrepreneurship
--php development
and so on...
Your inner loop overwrites the outerloop's $row variable. Try using a different variable name in the inner loop. Also, there's an error in your inner loop's SQL query (missing space between the tablename and FROM keyword).
I am trying to get data of 'indication' from two different tables.
The script works fine when selecting FROM number_one only.
Did try this with a , inbetween but that doesn't work.
How should I do this?
query2 = mysql_query("SELECT `indication` FROM `number_one`, `number_two` ORDER BY `indication` DESC");
while($row2 = mysql_fetch_object($query2)){
if($explode2[1] == $row2->indication){
echo "<option value=\"$row2->indication\" selected=\"selected\">$row2->indication</option>";
}
else{
echo "<option value=\"$row2->indication\">$row2->indication</option>";
}
}
Solution
query2 = mysql_query("SELECT `indication` FROM `number_one` UNION ALL SELECT `indication` FROM `number_two` ORDER BY `indication` DESC");
while($row2 = mysql_fetch_object($query2)){
if($explode2[1] == $row2->indication){
echo "<option value=\"$row2->indication\" selected=\"selected\">$row2->indication</option>";
}
else{
echo "<option value=\"$row2->indication\">$row2->indication</option>";
}
}
Assuming you have two tables, number_one and number_two with the indication column, your query would cross-join the two tables, giving you a set of rows which each have two columns (number_one.indication and number_two.indication, in all the possible combinations.
If I understand the question correctly, you want to have them as one column, with all the values from both tables. This can be done using the UNION ALL set operator, as I demonstrate below:
SELECT indication
FROM ( SELECT indication
FROM number_one
UNION ALL
SELECT indication
FROM number_two)
ORDER BY 1 DESC
OK,
In this query I am displaying the sales for a particular person, matching the passport number from the current form I am working on.
What I want to do however, is to sum the total sales and display it, excluding records which have been marked as paid.
I am having trouble because "paid" does not existent in the current form I am working on as a variable, nor the table it relates to.
I can´t use row['paid'] as I need to do this query outside of the while loop.
What should I do in this situation?
$sqlstr = mysql_query(
"SELECT * FROM sales where passport = ".
"'{$therecord['passport']}'");
if (mysql_numrows($sqlstr) != 0) {
echo "<b>Sales for {$therecord['firstname']} ".
"{$therecord['lastname']}</b><br />";
echo "<table><tr>";
echo '<tr><th align="left">Name</th><th align="left">Quantity</th>".
"<th align="left">Cost</th></tr>';
while ($row = mysql_fetch_array($sqlstr)) {
echo "<td>{$row['product']}</td>";
echo "<td>{$row['quantity']}</td>";
echo "<td>{$row['cost']}</td>";
echo "</tr>";
}
}
echo "</table>";
$sqltotal = mysql_query(
"SELECT SUM(cost) as total FROM sales where passport = ".
"'{$therecord['passport']} AND {$therecord['paid']} <> 1'");
$row = mysql_fetch_array($sqltotal);
echo "<br /><b>Total Owing: {$row['total']}</b>";
You could either create a MySQL view, of look at SQL joins. I'm not sure on your database structure, but you should have a SQL query like this:
SELECT SUM(sales.cost) AS total
FROM sales, table2
WHERE sales.passport = '$passport_id'
AND sales.passport = table2.passport
AND table2.paid = '1'
Not sure as that was wrote off-hand. Again, it'd be better if we knew the structure of your tables.
you've misplaced simple quote in :
"'{$therecord['passport']} AND {$therecord['paid']} <> 1'"
it must be :
"'{$therecord['passport']}' AND {$therecord['paid']} <> 1"
The code below works great. I have a MySQL database that contains book titles classified in different categories. In the code below, the variable "site" represents a book title. Each category is represented by a different table in the MySQL database.
The code below ranks the top 25 book titles (site) by total votes across all categories (MySQL tables). I am trying to exclude blank book titles (i. e. when site = ''). How can I do this?
I have tried inserting WHERE site != '' in a few places but I get an error message. So I guess I'm asking, where can I insert WHERE site != ''?
Thanks in advance,
John
<?
mysql_connect("mysqlv10", "username", "password") or die(mysql_error());
mysql_select_db("database") or die(mysql_error());
$result = mysql_query("SHOW TABLES");
$tables = array();
while ($row = mysql_fetch_assoc($result)) {
$tables[] = '`'.$row["Tables_in_bookfeather"].'`';
}
$subQuery = "SELECT site, votes_up FROM ".implode(" UNION ALL SELECT site, votes_up FROM ",$tables);
// Create one query that gets the data you need
$sqlStr = "SELECT site, sum(votes_up) sumVotesUp
FROM (
".$subQuery." ) subQuery
GROUP BY site ORDER BY sum(votes_up) DESC LIMIT 25";
$result = mysql_query($sqlStr);
$arr = array();
echo "<table class=\"samples2\">";
while ($row = mysql_fetch_assoc($result)) {
echo '<tr>';
echo '<td class="sitename2">'.$row["site"].'</td>';
echo '<td>'.$row["sumVotesUp"].'</td>';
echo '</tr>';
}
echo "</table>";
?>
You shouldn't have separate tables for each book category. I can't believe you have so many books that any of these tables would grow too large. Any scalability benefits you might gain by splitting the table are offset by the complexity of having to do these UNION queries.
Here's what I'd do:
Unify the tables into one table.
Add a Categories table.
Relate books to categories with a many-to-many table.
Then your SQL query becomes much simpler:
$sqlStr = "SELECT site, votes_up FROM Books
WHERE site IS NOT NULL AND site <> ''
ORDER BY votes_up DESC LIMIT 25";
It's probably safest to put it in the subquery:
$subQueryParts = array();
foreach($tables as $table)
$subQueryParts[] = "SELECT site, votes_up FROM $table WHERE LENGTH(site)";
$subQuery = implode(" UNION ALL ", $subQueryParts);
If possible, you should follow Bill Karwin's advice and store all your books in one table. Dynamic table names are very hard to search and manage, and they do not optimize well.