I have a database crm_data in which I have multiple tables. Now I want to calculate all rows in whole database where column_name value is equal to YES. To calculate all rows in database I am using this mysql query.
My SQL Query:
$sql = $db_con2->prepare("SELECT SUM(TABLE_ROWS) AS all_rows FROM
INFORMATION_SCHEMA.TABLES WHERE TABLE_SCHEMA = 'crm_data'");
$sql->execute();
$all_rows = $sql->fetchAll();
if (count($all_rows) > 0) {
foreach ($all_rows as $all_rows) {
echo $all_rows['all_rows'];
}
} else {
$all_rows = '0';
}
Thanks
What I did I went back to basics and used SHOW TABLES then I use table query SELECT * FROM $company WHERE rental_status = 'YES'. and I got the results.
BTW thanks guys giving me your suggestion.
Try this, i hope it works for you
// connect to Database.
$links = mysqli_connect($db_host, $db_username, $db_password, $db_name );
if($links === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
//get total
$n = 'YES';
$result = mysqli_query($links,"SELECT Count(*) As column_name FROM crm_data WHERE column_name='".$n."'");
$rows = mysqli_num_rows($result);
if($rows){
$gt = mysqli_fetch_assoc($result);
$total = $gt["column_name"];
}
echo $total;
Using PDO as requested.
// using PDO
$servername = "localhost";
$username = "user";
$password = "pass";
try {
$conn = new PDO("mysql:host=$servername;dbname=dbname", $username, $password);
// set the PDO error mode to exception
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
//echo "Connected successfully";
// call for the row count here.
$w='YES';
$rs = $conn->prepare("SELECT Count(*) As column_name FROM crm_data WHERE column_name='".$w."'");
$rs->execute();
$count = $rs->rowCount();
echo '<p>Total:'.$count.'</p>';
}
catch(PDOException $e)
{
echo "Connection failed: " . $e->getMessage();
}
You're not querying the data in your database you're now querying the actual structure of the database, which is concerning.
Nevertheless...
SELECT SUM(`COLUMN_NAME`) FROM `INFORMATION_SCHEMA`.`COLUMNS` where `COLUMN_NAME` = 'YES' AND `TABLE_SCHEMA` = 'crm_data';
Is the query you are looking for...
Related
I need help with some code. I want to select data from mySQL to a graph on my web page.
The data must be from the current logged in user, and when I select data to a card it works fine, but when I select it to a graph the graph disappears.
I'm using this code for the cards, and it works fine:
$sql = "SELECT energyexpenditure FROM energy4project WHERE user_id = '{$_SESSION["user_id"]}' ORDER BY time_stamp DESC LIMIT 1;";
This is the code for my current graph that don't show data based on logged in user:
<?php
header('Content-Type: application/json');
$host = "localhost";
$user = "`blabla";
$pwd = "blabla";
$db = "blabla";
$conn = new mysqli($host, $user, $pwd, $db);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT energyexpenditure, time_stamp FROM energy4project ORDER BY time_stamp DESC LIMIT 7;";
$result = $conn->query($sql);
$data = array();
foreach ($result as $row) {
$data[] = $row;
}
mysqli_close($conn);
echo json_encode($data);
?>
When I implement the code from the cards in the graph code it doesn't work.
Why does the SELECT WHERE user = '{$_SESSION["user_id"]} not work in the graphs?
If I understood good your Mysql query return an empty result. Try to modify your code as follows:
if(!$result = $conn->query($sql)) {
echo "query error.";
die();
}
$data = array();
while($row = $result->fetch_array(MYSQLI_ASSOC))
{
$data[] = $row;
}
/* free result set */
$result->free();
/* close connection */
$conn->close();
//uncomment the below line if you want to check de result of your mysql query because it seems be good.
//var_dump($data); die(); echo "<pre>";
echo json_encode($data);
So if you don't have any mysql error, verify your database name, table name are correctly and if it has data in your table.
Reference: https://www.php.net/manual/en/mysqli-result.fetch-array.php
Regards
When i run the following code it will return 100 users record from a table but when i increase the value of LIMIT from 100 to a greater number like 5000 then it will not return anything.i have total 6000 records in table. So how can i access different number of records like 2000, 3000 or even all 6000 records? kindly Guide what's wrong!
<?php
$db = mysql_connect("localhost","root","");
if (!$db) {
die('Could not connect to db: ' . mysql_error());}
mysql_select_db("distributedsms",$db);
$result = mysql_query("select * from users LIMIT 100", $db);
$json_response = array();
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
$row_array['user no'] = $row['sno'];
$row_array['mnc'] = $row['mnc'];
$row_array['mcc'] = $row['mcc'];
$row_array['lac'] = $row['lac'];
$row_array['cell id'] = $row['cell id'];
$row_array['lat'] = $row['lat'];
$row_array['lng'] = $row['lng'];
$row_array['address'] = $row['address'];//push the values in the array
array_push($json_response,$row_array);
$users = $json_response;}
$fp = fopen('users_data.json', 'w+');
fwrite($fp, json_encode($json_response));
fclose($fp);
echo json_encode($json_response);
?>
First, enable error reporting in your INI or Script:
<?php error_reporting(E_ALL);
ini_set('display_errors', 1);
This will help you if there is any error/warning in case of low memory allocation or similar.
To fetch all records, you shouldn't use LIMIT, remove LIMIT from your SQL.
i.e. select * from users
You should not use mysql_connect as it is deprecated. Use mysqli_connect instead. Also, I don't think you need to iterate so much, just choose what you want in your select statement.
UPDATE: another factor on why this might be happening can also be the returned information from the database, if you have apostrophes ' in your strings and you try to use json_encode, it will break, you would need to addslashes first.
Try the following, change your LIMIT as you wish, and let me know if you still have those errors:
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT sno,mnc,mcc,lac,cell_id,lat,lng,address FROM users LIMIT 100";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
$response = array();
while ($row = $result->fetch_assoc()) {
foreach($row as $k => $str){
$row[$k] = addslashes($str);
}
array_push($response, $row);
}
echo json_encode($response);
} else {
echo "0 results";
}
$conn->close();
?>
I have a working SQL query that I'm trying to use in a small PHP script but getting Parse error, tried many variations. Hope you can help. End result would be to have a two field form with 'Date' and 'Channel No' then giving result count of number of 'channel' rows for a given date. Sorry fairly new PHP/SQL, thanks.
<?php
// Connect to MSSQL and select the database
$link = mssql_connect('localhost', 'root', '', 'jm_db');
mssql_select_db('jm_db');
// Select all our records from a table
$mysql_query = mssql_query ('SELECT COUNT(*) FROM asterisk_cdr
WHERE calldate LIKE '%2014-10-11%'
AND channel LIKE '%SIP/4546975289%');
echo $sql;
?>
I have re-done the code but getting 'Warning: mysql_fetch_array() expects parameter 1 to be resource' and undefined variable.
<?php
// Create connection
$mysqli = new mysqli($localhost, $root, $jm_db);
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$sql = ("SELECT COUNT(*) FROM asterisk_cdr
WHERE calldate LIKE '%2014-10-11%'
AND channel LIKE '%SIP/4546975289%'");
$results= array();
while ($result = mysql_fetch_array($sql)) {
$results[]= $result;
}
foreach($results as $result){
echo $result['calldate'] . " " . $result['channel'];
}
?>
You're missing a quote (Stack's syntax highlighting shows you), yet it should be replaced with an opening double quote and ending with the same. You can't use all single quotes.
I replaced the opening single quote with a double, along with a matching closing double quote.
$mysql_query = mssql_query ("SELECT COUNT(*) FROM asterisk_cdr
WHERE calldate LIKE '%2014-10-11%'
AND channel LIKE '%SIP/4546975289%'");
As a sidenote, you're echoing the wrong variable.
However, that is not how you would echo out results, but with a loop.
Something like, and replacing Fieldname with the one you want to use:
while ($row = mssql_fetch_assoc($mysql_query)) {
print $row['Fieldname'] . "\n";
}
or use mssql_fetch_array()
You can also use:
$results= array();
while ($result = mssql_fetch_array($mysql_query)) {
$results[]= $result;
}
foreach($results as $result){
echo $result['calldate'] . " " . $result['channel'];
}
For more information on Microsoft SQL Server's function, consult:
http://php.net/manual/en/book.mssql.php
$mysql_query = mssql_query ('SELECT COUNT(*) FROM asterisk_cdr
WHERE calldate LIKE '%2014-10-11%'
AND channel LIKE '%SIP/4546975289%');
while($row=mssql_fetch_array($mysql_query))
{
echo $row[0];
}
$mysqli = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($mysqli->connect_error) {
die("Connection failed: " . $mysqli->connect_error);
}
$mysql_query = mysqli ("SELECT COUNT(*) FROM asterisk_cdr WHERE calldate LIKE '%2014-10-11%' AND channel LIKE '%SIP/4546975289%'");
while ($row = mysql_fetch_array($mysql_query, MYSQL_ASSOC)) {
echo ($row["channel"]);
}
this is a simple example with PDO
<?php
try {
$dns = 'mysql:host=localhost;dbname=jm_db';
$user = 'root';
$pass = '';
$options = array(
PDO::MYSQL_ATTR_INIT_COMMAND => "SET NAMES utf8",
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION
);
$cnx = new PDO( $dns, $user, $pass, $options );
$select = $cnx->query("SELECT COUNT(*) as count FROM asterisk_cdr WHERE calldate LIKE '%2014-10-11%' AND channel LIKE '%SIP/4546975289%'");
$select->setFetchMode(PDO::FETCH_OBJ);
while( $row = $select->fetch() )
{
echo '<h1>', $row->count , '</h1>';
}
} catch ( Exception $e ) {
echo "Connect failed : ", $e->getMessage();
die();
}
I'm trying to echo the last 10 items in my database with pdo. However I keep getting Query failed. However when I do the code snippet at the very bottom I can get just the very last item in my database.
$db2 = new PDO('mysql:host='. $host .';dbname='.$db_name_uroll, $db_username, $db_password);
$statement2 = $db2->prepare("select * from `{$user}` ORDER BY bet_id DESC LIMIT 2");
if ($stmt = $db2->query($statement2)) //PDO::query() returns a PDOStatement on success or false on failure.
{
//If we got a PDOStatement as a return value from PDO::Query() !!!ECHO WHILE FETCHING!!!
while($row2 = $stmt->fetch(PDO::FETCH_ASSOC)) //This loop will keep going for as many rows as the PDOStatement returns.
{
echo $row2['roll'] . "<br />";
}
}
else
{
//If PDO::Query returned false, then something is wrong with our query. Or connection or whatever.
echo "Query failed.";
}
But when I do this below it works, but only prints out the very last item
$row2 = $statement2->fetch();
echo $row2[roll];
You need to remove prepare statement. and run query directly inside query function.
$db2 = new PDO('mysql:host='. $host .';dbname='.$db_name_uroll, $db_username, $db_password);
//Remove $db2 prepare
$statement2 = "select * from `{$user}` ORDER BY bet_id DESC LIMIT 2";
if ($stmt = $db2->query($statement2)) //PDO::query() returns a PDOStatement on success or false on failure.
{
//If we got a PDOStatement as a return value from PDO::Query() !!!ECHO WHILE FETCHING!!!
while($row2 = $stmt->fetch(PDO::FETCH_ASSOC)) //This loop will keep going for as many rows as the PDOStatement returns.
{
echo $row2['roll'] . "<br />";
}
}
else
{
//If PDO::Query returned false, then something is wrong with our query. Or connection or whatever.
echo "Query failed.";
}
This code is working.
Docs link: http://www.php.net/pdo.query
Using prepare you have to use execute method.
http://www.php.net/manual/en/pdo.prepare.php
this is tested code.
$dbhost = "localhost";
$dbname = "pdo";
$dbuser = "root";
$con = new PDO("mysql:host=$dbhost;dbname=$dbname", $dbuser);
echo $select = "SELECT * FROM books ORDER BY id DESC LIMIT 10";
$query = $con->prepare($select);
$query->execute();
$query->setFetchMode(PDO::FETCH_BOTH);
while($row = $query->fetch()) {
echo '<pre>';print_r($row);echo '</pre>';
}
or you can do like this
if($query->execute()) {
$query->setFetchMode(PDO::FETCH_BOTH);
while($row = $query->fetch()) {
echo '<pre>';print_r($row);echo '</pre>';
}
} else {
echo "Query failed";
}
I'm learning PHP and I'm well versed with Java and C. I was given a practice assignment to create a shopping project. I need to pull out the products from my database. I'm using the product id to do this. I thought of using for loop but I can't access the prod_id from the database as a condition to check! Can anybody help me?! I have done all the form handling but I need to output the products. This is the for-loop I am using. Please let me know if I have to add any more info. Thanks in advance :)
for($i=1; $i + 1 < prod_id; $i++)
{
$query = "SELECT * FROM products where prod_id=$i";
}
I would suggest that you use PDO. This method will secure all your SQLand will keep all your connections closed and intact.
Here is an example
EXAMPLE.
This is your dbc class (dbc.php)
<?php
class dbc {
public $dbserver = 'server';
public $dbusername = 'user';
public $dbpassword = 'pass';
public $dbname = 'db';
function openDb() {
try {
$db = new PDO('mysql:host=' . $this->dbserver . ';dbname=' . $this->dbname . ';charset=utf8', '' . $this->dbusername . '', '' . $this->dbpassword . '');
} catch (PDOException $e) {
die("error, please try again");
}
return $db;
}
function getproduct($id) {
//prepared query to prevent SQL injections
$query = "SELECT * FROM products where prod_id=?";
$stmt = $this->openDb()->prepare($query);
$stmt->bindValue(1, $id, PDO::PARAM_INT);
$stmt->execute();
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
return $rows;
}
?>
your PHP page:
<?php
require "dbc.php";
for($i=1; $i+1<prod_id; $i++)
{
$getList = $db->getproduct($i);
//for each loop will be useful Only if there are more than one records (FYI)
foreach ($getList as $key=> $row) {
echo $row['columnName'] .' key: '. $key;
}
}
First of all, you should use database access drivers to connect to your database.
Your query should not be passed to cycle. It is very rare situation, when such approach is needed. Better to use WHERE condition clause properly.
To get all rows from products table you may just ommit WHERE clause. Consider reading of manual at http://dev.mysql.com/doc.
The statement selects all rows if there is no WHERE clause.
Following example is for MySQLi driver.
// connection to MySQL:
// replace host, login, password, database with real values.
$dbms = mysqli_connect('host', 'login', 'password', 'database');
// if not connected then exit:
if($dbms->connect_errno)exit($dbms->connect_error);
$sql = "SELECT * FROM products";
// executing query:
$result = $dbms->query($sql);
// if query failed then exit:
if($dbms->errno)exit($dbms->error);
// for each result row as $product:
while($product = $row->fetch_assoc()){
// output:
var_dump($product); // replace it with requied template
}
// free result memory:
$result->free();
// close dbms connection:
$dbms->close();
for($i=1;$i+1<prod_id;$i++) {
$query = "SELECT * FROM products where prod_id=$i";
$result = mysqli_query($query, $con);
$con is the Database connection details
you can use wile loop to loop thru each rows
while ($row = mysqli_fetch_array($result))
{
......
}
}
Hope this might work as per your need..
for($i=1; $i+1<prod_id; $i++) {
$query = "SELECT * FROM products where prod_id = $i";
$result = mysql_query($query);
while ($row = mysql_fetch_array($result, MYSQL_NUM)) {
print_r($row);
}
}
I think you want all records from your table, if this is the requirement you can easily do it
$query = mysql_query("SELECT * FROM products"); // where condition is optional
while($row=mysql_fetch_array($query)){
print_r($row);
echo '<br>';
}
This will print an associative array for each row, you can access each field like
echo $row['prod_id'];