Script to count two columns and echo result - php

Question

I have a working SQL query that I'm trying to use in a small PHP script but getting Parse error, tried many variations. Hope you can help. End result would be to have a two field form with 'Date' and 'Channel No' then giving result count of number of 'channel' rows for a given date. Sorry fairly new PHP/SQL, thanks.
<?php
// Connect to MSSQL and select the database
$link = mssql_connect('localhost', 'root', '', 'jm_db');
mssql_select_db('jm_db');
// Select all our records from a table
$mysql_query = mssql_query ('SELECT COUNT(*) FROM asterisk_cdr
WHERE calldate LIKE '%2014-10-11%'
AND channel LIKE '%SIP/4546975289%');
echo $sql;
?>
I have re-done the code but getting 'Warning: mysql_fetch_array() expects parameter 1 to be resource' and undefined variable.
<?php
// Create connection
$mysqli = new mysqli($localhost, $root, $jm_db);
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$sql = ("SELECT COUNT(*) FROM asterisk_cdr
WHERE calldate LIKE '%2014-10-11%'
AND channel LIKE '%SIP/4546975289%'");
$results= array();
while ($result = mysql_fetch_array($sql)) {
$results[]= $result;
}
foreach($results as $result){
echo $result['calldate'] . " " . $result['channel'];
}
?>

Answer 1

You're missing a quote (Stack's syntax highlighting shows you), yet it should be replaced with an opening double quote and ending with the same. You can't use all single quotes.
I replaced the opening single quote with a double, along with a matching closing double quote.
$mysql_query = mssql_query ("SELECT COUNT(*) FROM asterisk_cdr
WHERE calldate LIKE '%2014-10-11%'
AND channel LIKE '%SIP/4546975289%'");
As a sidenote, you're echoing the wrong variable.
However, that is not how you would echo out results, but with a loop.
Something like, and replacing Fieldname with the one you want to use:
while ($row = mssql_fetch_assoc($mysql_query)) {
print $row['Fieldname'] . "\n";
}
or use mssql_fetch_array()
You can also use:
$results= array();
while ($result = mssql_fetch_array($mysql_query)) {
$results[]= $result;
}
foreach($results as $result){
echo $result['calldate'] . " " . $result['channel'];
}
For more information on Microsoft SQL Server's function, consult:
http://php.net/manual/en/book.mssql.php

Answer 2

$mysql_query = mssql_query ('SELECT COUNT(*) FROM asterisk_cdr
WHERE calldate LIKE '%2014-10-11%'
AND channel LIKE '%SIP/4546975289%');
while($row=mssql_fetch_array($mysql_query))
{
echo $row[0];
}

Answer 3

$mysqli = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($mysqli->connect_error) {
die("Connection failed: " . $mysqli->connect_error);
}
$mysql_query = mysqli ("SELECT COUNT(*) FROM asterisk_cdr WHERE calldate LIKE '%2014-10-11%' AND channel LIKE '%SIP/4546975289%'");
while ($row = mysql_fetch_array($mysql_query, MYSQL_ASSOC)) {
echo ($row["channel"]);
}

Answer 4

this is a simple example with PDO
<?php
try {
$dns = 'mysql:host=localhost;dbname=jm_db';
$user = 'root';
$pass = '';
$options = array(
PDO::MYSQL_ATTR_INIT_COMMAND => "SET NAMES utf8",
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION
);
$cnx = new PDO( $dns, $user, $pass, $options );
$select = $cnx->query("SELECT COUNT(*) as count FROM asterisk_cdr WHERE calldate LIKE '%2014-10-11%' AND channel LIKE '%SIP/4546975289%'");
$select->setFetchMode(PDO::FETCH_OBJ);
while( $row = $select->fetch() )
{
echo '<h1>', $row->count , '</h1>';
}
} catch ( Exception $e ) {
echo "Connect failed : ", $e->getMessage();
die();
}