Find the average number for each user - php

Question

First off, I am fairly new to coding. I try to do my due diligence before coming here for advice.
I am trying to write a function that will query the database for a users numbers and get the average for each user.
function getUserAverage($userID) {
//loop through user totals & calculate average for each user
$sql = "select p.userID, p.user, p.number ";
$sql .= "from " . DB_PREFIX . "numbers p ";
$sql .= "inner join " . DB_PREFIX . "users u on p.userID = u.userID ";
$sql .= "where u.userID = " . $user->userID . " ";
$sql .= "order by u.lastname, u.firstname";
$query = $mysqli->query($sql);
while ($row = $query->fetch_assoc()) {
//player average of numbers
$tba = ROUND(AVG(`number`),2);
}
$query->free;
return $tba;
}
The result I am hoping to get is something like:
user1 = 14.5
user2 = 35.8
user3 - 7.4
I have written code to get the average numbers for all, but the need is to get by individual user.
//Average Numbers
$sql_avgNum = "SELECT ROUND(AVG(`number`),2) AS `Average` \n"
. "FROM `" . DB_PREFIX . "numbers` \n";
$data = $mysqli->query($sql_avgNum);
$result_avgNum = mysqli_fetch_array($data);
echo ' <tr class="altrow"><td> Average Number: </td><td> ' .
$result_avgNum[0] . ' </td></tr>';
//End Average Numbers

Answer 1

for count average of individual data you must do it using group by. Further reference of group by is here:

Answer 2

I'm not very sure, but I think that this is what you're looking for:
function getUserAverage($userID) {
// loop through user totals & calculate average for each user
$sql = "SELECT p.userID, u.user, AVG(p.number) AS 'avarage' ";
$sql .= "FROM " . DB_PREFIX . "numbers p ";
$sql .= "INNER JOIN " . DB_PREFIX . "users u ON(p.userID = u.userID) ";
$sql .= "WHERE p.userID = " . $user->userID . " ";
$sql .= "GROUP BY p.userID ";
$sql .= "ORDER BY u.lastname, u.firstname";
$query = $mysqli->query($sql);
while ($row = $query->fetch_assoc()) {
//player average of numbers
$tba = $row['avarage'];
}
$query->free;
return $tba;
}