php count 2 parameters error - php

Question

I'm making a function that brings me the sum of the records in my database that meet 2 conditions.
i start like this
function cuentaticketspendienteempleado($conexion){
$pendientes = (mysqli_query($conexion, "SELECT COUNT(*) AS conteo FROM ticket ")) or die("Error mostrando tickets pendientes: ".mysqli_error($conexion));
$resultados = mysqli_fetch_row($pendientes);
return $resultados[0];
}
I need to add one more field to the account.
the ID department parameter which I want to assign to only tell me the tickets or reports of that department
using the previous function
When I'm trying to account for that user's tickets in that department using this function
function listTicketUnrevisedSupervisor($conexion, $id){
$consulta = mysqli_query($conexion, "SELECT *, COUNT(t.id) as contador_tickets, t.id as id_ticket, u.id as user_id, t.fecha_creacion as t_fcreacion, t.hora_creacion as t_hcreacion
FROM ticket as t
JOIN usuario AS u
ON t.id_usuario = u.id
WHERE t.status <> '3' AND u.id_departamento = ".$id."")
or die("Error listando Ticket: ".mysqli_error($conexion));
return $consulta;
}
i get this
error

Answer 1

Maybe is just the formatting of your post, but the * can't be used on a query when you are selecting other specific fields, you can use the function like this
function listTicketUnrevisedSupervisor($conexion, $id) {
$query = "SELECT t.field1, u.field_2, t.id as id_ticket, u.id as user_id, "
. "t.fecha_creacion as t_fcreacion, "
. "t.hora_creacion as t_hcreacion "
. "FROM ticket as t "
. "JOIN usuario AS u ON t.id_usuario = u.id "
. "WHERE t.status <> '3' "
. "AND u.id_departamento = " . $id . " "
. "ORDER BY t.id DESC ";
if($consulta = mysqli_query($conexion, $query)){
return $consulta;
} else {
die("Error listando Ticket: ".mysqli_error($conexion));
}
}
Or just select everything
function listTicketUnrevisedSupervisor($conexion, $id) {
$query = "SELECT * "
. "FROM ticket as t "
. "JOIN usuario AS u ON t.id_usuario = u.id "
. "WHERE t.status <> '3' "
. "AND u.id_departamento = " . $id . " "
. "ORDER BY t.id DESC ";
if($consulta = mysqli_query($conexion, $query)){
return $consulta;
} else {
die("Error listando Ticket: ".mysqli_error($conexion));
}
}
Counting the rows
$num_rows = mysqli_num_rows($consulta);
mysqli_query documentation (en)
Here you can check the documentation about mysqli_query (En Español Juan)
Hope my answer helps you.
Edit, fetch all the results
You can do it with a procedure like this one
function getTheAssocArrayOfMyQuery($consulta){
$return= array();
while ($row= mysqli_fetch_assoc($consulta)) {
array_push($return, $consulta);
}
return $return;
}
Or, using mysqli_fetch_all()
$this_is_the_array_i_will_use = mysqli_fetch_all($consulta,MYSQLI_ASSOC);
mysqli_fetch_all() manual