Edit: I am using API routes, so i have no views and such
I have a database like this
User:
id
name
card:
id
card_number
user_id
swipe:
id
time
card_number
the relationships go as followed user has one card one card has many swipe
the joins would be as such
user.id = card.user_id
card.card_number = swipe.card_number
In Larvel i have 3 models.
user
card
swipe
user Model
class user extends Model
{
public function card()
{
return $this->hasOne('App\card','user_id','id');
}
}
in a controller if i do
$model = user::with('card')->get();
i get the card data joined with the user data as expected.
class card extends Model
{
public function person()
{
return $this->belongsTo('App\user');
}
public function swipe(){
return $this->hasMany('App\swipe','card_number','card_number');
}
}
if i now do
$model = user::with('card.swipe')->get();
which i would expect to return all the users with their cards, and swipes associated to that card.
However what i get is
500 internal server error
What am i doing wrong here?
For Example you can use like this.
$shares = DB::table('shares')
->join('users', 'users.id', '=', 'shares.user_id')
->join('follows', 'follows.user_id', '=', 'users.id')
->where('follows.follower_id', '=', 3)
->get();
You cant use like this,
user::with('card.swipe')->get();
Use Has many Through
https://laravel.com/docs/5.5/eloquent-relationships#has-many-through
user - countries (in docs)
card - users (in docs)
swipe - posts (in docs)
$country->posts;
$user->swipe;
I don't know if this is right solution, but you can try:
public function swipe(){
return $this->hasMany('App\swipe')->where('card_number','card_number');
}
You should be able to extract your data in your controller like this:
return user::with(['card' => function($query) {
$query->with('swipe');
}])->get();
Make sure your swipe model "belongsTo('App\card')".
Related
Good day. I have this relationship problem in laravel
I have three models
User
State
School
I have established the following relationships between them
a. School - User (A user can enroll in many schools)
In User Model
public function schools(){
return $this->belongsToMany('App\Models\School', 'school_user', 'user_id', 'school_id');
}
b. A school can have many users
In School Model
public function users(){
return $this->belongsToMany('App\Models\User', 'school_user', 'school_id', 'user_id');
}
c. A school belongs to a state (i.e c an be found in a state)
In School Model
public function states(){
return $this->belongsTo('App\Models\State');
}
d. A state has many schools
In State Model
public function schools(){
return $this->hasMany('App\Models\School');
}
Now, I know how to query models with immediate relationship. For example, I can get the users associated with a school and vice-versa. I can also get the schools in a state.
My Question
How do I get all users associated with schools in a given state (using a query)? Assuming all we have is just the name of a state.
And probably get all schools the users are associated with and the date(time) in which there were associated with the schools?
This is what I have done. The second query is not giving me an answer
public function details(){
//Get all schools associated with a state
$schools = State::with('schools')->where('id',1)->first();
foreach($schools->schools as $data){
//Get all users associated with the schools
$users = School::with('users')->where('id',$data->id);
dd($users);
}
}
Apart from the fact that this approach is not probably right, I am not getting any answer. Is there a query or method that can solve this?
Thanks.
You should see the related models in the relations array attribute
$school= App\Models\School::with('User', 'State')->get();
Using a whereHas you can get all users that belong to schools with the given state_id.
$state = State::find(1);
$users = User::whereHas('schools', function ($query) use ($state) {
$query->where('state_id', $state->id);
})->get();
Querying Relationship Existence
If you need even more power, you may use the whereHas and orWhereHas
methods to define additional query constraints on your has queries,
such as inspecting the content of a comment:
use Illuminate\Database\Eloquent\Builder;
// Retrieve posts with at least one comment containing words like code%...
$posts = Post::whereHas('comments', function (Builder $query) {
$query->where('content', 'like', 'code%');
})->get();
// Retrieve posts with at least ten comments containing words like code%...
$posts = Post::whereHas('comments', function (Builder $query) {
$query->where('content', 'like', 'code%');
}, '>=', 10)->get();
I have many to many connect with between user - cityarea.
I have also area which connect cityarea (One cityarea can connect only one area).
I have this database structure:
users
id
username
password
cityareas
id
name
area_id
cityarea_user
id
cityarea_id
user_id
areas
id
name
Next I have Models
User
public function cityareas()
{
return $this->belongsToMany('App\Cityarea');
}
Cityarea
public function area()
{
return $this->belongsTo('App\Area');
}
public function users()
{
return $this->belongsToMany('\App\User');
}
Area
public function cityareas()
{
return $this->hasMany('App\Cityarea');
}
QUESTION:
How I can get all users where areas.name = "South" with Eloquent ?
Thanks!!
By using whereHas, you can do:
$users = User::whereHas('cityareas.area', function ($query) {
$query->where('name', 'South');
})->get();
Jeune Guerrier solution is perfect, but you can use with() method of eloquent If you also need cityarea collection along with users collection.
$users = User::with('cityareas')->whereHas('cityareas.area', function ($query) {
$query->where('name', 'South');
})->get();
This is exactly what the belongs to many relationships is built for.
You simply have to do, Cityarea::where('name', 'South')->first()->users;
If you want to do something further with the query, e.g. sort by users created at, you can do
Cityarea::where('name', 'South')->first()->users()->orderBy('creaated_at', desc')->get();
Note that if there is no such Cityarea with name 'South', the ->first() query above will return null and therefore will fail to fetch the users.
A more performant way to do it programmatically is to use the whereHas approach as discussed in the comments below.
For example: I have these models in my application.
User, Profile, Interest.
I linked the users table with the profiles table by adding the user_id column in the profiles table. And I linked profiles and interests by using a pivot table (interest_profile), Which is (as obvious) will have two columns (profile_id, interest_id).
However, I want to query the users who are associated with a profile, too see who is associated with a particular interest, In other words: "select all users who are having (in their profiles) that particular interest".
I know that I can do this with raw SQL by joining the four tables and then use (where clause).. But I want to do it the Laravel way.
Thanks in advance.
First make sure you have your relationships setup correctly on your models like:
class User extends Model
{
public function profile()
{
return $this->hasOne(Profile::class);
}
}
class Profile extends Model
{
public function user()
{
return $this->belongsTo(User::class);
}
public function interests()
{
return $this->belongsToMany(Interest::class, 'interest_profile');
}
}
class Interest extends Model
{
public function profiles()
{
return $this->belongsToMany(Profile::class, 'interest_profile');
}
}
Then you can use whereHas() to constrain a query by a related model and dot notation for nested relations. So your query would be:
User::whereHas('profile.interests', function($query) use ($interestName) {
return $query->where('name', $interestName);
})->get();
That would just return a collection of users. If you wanted to return their profiles and interests as well you would use with():
User::whereHas('profile.interests', function($query) use ($interestName) {
return $query->where('name', $interestName);
})
->with('profile.interests')
->get();
Assuming the User model has a relationship profile and the Profile model has a relationship interests, you can do this.
$interest_id = 1;
$users = User::whereHas('profile', function ($query) use ($interest_id) {
$query->whereHas('interests', function ($query) use ($interest_id) {
$query->where('id', $interest_id);
});
})->get();
I have 3 models
User
Channel
Reply
model relations
user have belongsToMany('App\Channel');
channel have hasMany('App\Reply', 'channel_id', 'id')->oldest();
let's say i have 2 channels
- channel-1
- channel-2
channel-2 has latest replies than channel-1
now, i want to order the user's channel by its channel's current reply.
just like some chat application.
how can i order the user's channel just like this?
channel-2
channel-1
i already tried some codes. but nothing happen
// User Model
public function channels()
{
return $this->belongsToMany('App\Channel', 'channel_user')
->withPivot('is_approved')
->with(['replies'])
->orderBy('replies.created_at'); // error
}
// also
public function channels()
{
return $this->belongsToMany('App\Channel', 'channel_user')
->withPivot('is_approved')
->with(['replies' => function($qry) {
$qry->latest();
}]);
}
// but i did not get the expected result
EDIT
also, i tried this. yes i did get the expected result but it would not load all channel if there's no reply.
public function channels()
{
return $this->belongsToMany('App\Channel')
->withPivot('is_approved')
->join('replies', 'replies.channel_id', '=', 'channels.id')
->groupBy('replies.channel_id')
->orderBy('replies.created_at', 'ASC');
}
EDIT:
According to my knowledge, eager load with method run 2nd query. That's why you can't achieve what you want with eager loading with method.
I think use join method in combination with relationship method is the solution. The following solution is fully tested and work well.
// In User Model
public function channels()
{
return $this->belongsToMany('App\Channel', 'channel_user')
->withPivot('is_approved');
}
public function sortedChannels($orderBy)
{
return $this->channels()
->join('replies', 'replies.channel_id', '=', 'channel.id')
->orderBy('replies.created_at', $orderBy)
->get();
}
Then you can call $user->sortedChannels('desc') to get the list of channels order by replies created_at attribute.
For condition like channels (which may or may not have replies), just use leftJoin method.
public function sortedChannels($orderBy)
{
return $this->channels()
->leftJoin('replies', 'channel.id', '=', 'replies.channel_id')
->orderBy('replies.created_at', $orderBy)
->get();
}
Edit:
If you want to add groupBy method to the query, you have to pay special attention to your orderBy clause. Because in Sql nature, Group By clause run first before Order By clause. See detail this problem at this stackoverflow question.
So if you add groupBy method, you have to use orderByRaw method and should be implemented like the following.
return $this->channels()
->leftJoin('replies', 'channels.id', '=', 'replies.channel_id')
->groupBy(['channels.id'])
->orderByRaw('max(replies.created_at) desc')
->get();
Inside your channel class you need to create this hasOne relation (you channel hasMany replies, but it hasOne latest reply):
public function latestReply()
{
return $this->hasOne(\App\Reply)->latest();
}
You can now get all channels ordered by latest reply like this:
Channel::with('latestReply')->get()->sortByDesc('latestReply.created_at');
To get all channels from the user ordered by latest reply you would need that method:
public function getChannelsOrderdByLatestReply()
{
return $this->channels()->with('latestReply')->get()->sortByDesc('latestReply.created_at');
}
where channels() is given by:
public function channels()
{
return $this->belongsToMany('App\Channel');
}
Firstly, you don't have to specify the name of the pivot table if you follow Laravel's naming convention so your code looks a bit cleaner:
public function channels()
{
return $this->belongsToMany('App\Channel') ...
Secondly, you'd have to call join explicitly to achieve the result in one query:
public function channels()
{
return $this->belongsToMany(Channel::class) // a bit more clean
->withPivot('is_approved')
->leftJoin('replies', 'replies.channel_id', '=', 'channels.id') // channels.id
->groupBy('replies.channel_id')
->orderBy('replies.created_at', 'desc');
}
If you have a hasOne() relationship, you can sort all the records by doing:
$results = Channel::with('reply')
->join('replies', 'channels.replay_id', '=', 'replies.id')
->orderBy('replies.created_at', 'desc')
->paginate(10);
This sorts all the channels records by the newest replies (assuming you have only one reply per channel.) This is not your case, but someone may be looking for something like this (as I was.)
I would like to display the posts of everyone the current user follows, ordered by date desc.
I have a many to many relationship supplying all the people the user is following.
$users = User::find(Auth::user()->id)->follow()->get();
I have a one to many relationship displaying the posts for any user.
$updates = App\User::find(?????)->updates()->orderBy('created_at', 'desc')->get();
The question mark's shows where the followers ID's need to be placed.
I can put the above query inside the for each loop but that obviously works its way through each follower rather than all posts in date order.
I suspect I may need to set a new relationship and work from the beginning. Can anyone advise.
User Model
public function updates()
{
return $this->hasMany('App\update');
}
/**
* User following relationship
*/
// Get all users we are following
public function follow()
{
return $this->belongsToMany('App\User', 'user_follows', 'user_id', 'follow_id')->withTimestamps()->withPivot('id');;;
}
// This function allows us to get a list of users following us
public function followers()
{
return $this->belongsToMany('App\User', 'user_follows', 'follow_id', 'user_id')->withTimestamps();;
}
}
Update Model
public function user_update()
{
return $this->belongsTo('App\User');
}
Thank you.
Since you want the posts, it is probably going to be easier starting a query on the Post model, and then filter the posts based on their relationships.
Assuming your Post model has an author relationship to the User that created the post, and the User has a follower relationship to all the Users that are following it, you could do:
$userId = Auth::user()->id;
$posts = \App\Post::whereHas('author.follower', function ($q) use ($userId) {
return $q->where('id', $userId);
})
->latest() // built in helper method for orderBy('created_at', 'desc')
->get();
Now, $posts will be a collection of your Post models that were authored by a user that is being followed by your authenticated user.