Could someone tell me how i request json from a php file located on another server that gives it to our asp.net?
It includes ~10 variables we want to use again.
I don't want just a string, but an array.
so this wont work:
//We don't actually use the given url of course
string url = "url";
var json = new WebClient().DownloadString(url);
Response.Write(json);
I'd like to use it somewhere like this jsonname[2]
Output a JSON array from your php page like this
$myArr = array("John", "Mary", "Peter", "Sally");
$myJSON = json_encode($myArr);
header('Content-Type: application/json');
echo $myJSON;
In your c# code you then need to deserialize the string returned by DownloadString into a type that matches the format of the JSON data. If your JSON is just an array of strings, then use JsonConvert.DeserializeObject<List<string>>(json) from the Newtonsoft.Json package. Otherwise you need to replace List with something that matches the Json data, for example a new class with all the same property names and types. In this case
string url = "url";
var json = new WebClient().DownloadString(url);
Response.Write(json);
var myArr = JsonConvert.DeserializeObject<List<string>>(json);
Response.Write(myArr[1]); // will output "Mary"
If you don't have Newtonsoft.Json, this question has some options for obtaining it
Related
How can I get a value of a second level JSON node using PHP from a Ajax request?
If I have the next JSON data in client:
var Data = {idJS: "1", dataToSet: "example", another:{ field1: "example2"} };
When the Ajax request is done, in PHP, dataToSet is get as follows: $_POST['dataToSet'], in particular, I use Codeigniter, then I use $this->input->post('dataToSet'). But, How can I get another->field1?
[Solved]:
$postdata = $this->input->post();
$postdata['another']['field1'];
I don't know how you do it with codeigniter, but you have to decode the json. Afterwards you can acces the field. This might look something like this:
$postdata = json_decode($this->input->post);
$postdata['another']['field1];
This should do it:
$data = $this->input->post('another');
print_r($data->field1);
// or you can do it in one line:
$this->input->post('another')->field1;
Try this:
$ata = json_decode($this->input->post('dataToSet'), true);
$field1 = $data['another']['field1'];
if my JSON data is coming back as this:
{"errorCodes":[0]}resultArray=[{....}]
how do I grab the resultArray as the actual JSON string and ignore the rest?
and why would I need errorCodes in front of it?
Just use string manipulation to get rid of everything up through resultArray= and then decode with json_decode().
$json_raw = '...'; // the raw "JSON" string
$delimiter = 'resultArray=';
$cleaned_json = substr($json_raw, strpos($json_raw,$delimiter) + strlen($delimiter)));
$object = json_decode($cleaned_json);
http://www.instamapper.com/api?action=getPositions&key=584014439054448247&num=10&format=json
is the url, which contains json data. I want to use that data and send SMS to a particular phone no if value of latitude and longitude(Extracted from JSON).
Check constraints, we can use through php. But the main problem is How to extract data from JSON file?
I don't want to give you the solution, so the below should be enough to get you started.
Read in the JSON data using file_get_contents
Parse the JSON string into a PHP object using json_decode
Your code should look something like this:
$url = "http://www.instamapper.com/api?action=getPositions&key=584014439054448247&num=10&format=json";
$contents = file_get_contents($url);
$jsonObj = json_decode($contents);
You mean something like this?
<?php
$jsonurl = "http://search.twitter.com/trends.json";
$json = file_get_contents($jsonurl,0,null,null);
$json_output = json_decode($json);
foreach ( $json_output->trends as $trend )
{
echo "{$trend->name}\n";
}
I am uploading a file using PHP and want to return the file name and the file status to javascript. In PHP I create the json object by:
$value = array('result' => $result, 'fileName' => $_FILES['myfile']['name']);
print_r ($value);
$uploadData = json_encode($value);
This creates the json object. I then send it to a function in javascript and recieve it as a variable called fileStatus.
alert (fileStatus);
It displays
{"result":"success","fileName":"cake"}
which should be good. But when I try and do
fileStatus.result or fileStatus.fileName
I get an error saying that they are undefined. Please help I'm really stuck on this. Thanks.
The fileStatus is just a string at this point, so it does not have properties such as result and fileName. You need to parse the string into a JSON object, using a method such as Firefox's native JSON.parse or jQuery's jQuery.parseJSON.
Example:
var fileStatusObj = jQuery.parseJSON(fileStatus);
If the alert displays {"result":"success","fileName":"cake"} then you probably still have to turn the string into a JSON object. Depending on the browsers you are developing for you can use the native JSON support or the JSON.org implementation to turn your string into an object. From there on it should work as expected.
When you are setting the variable, do not put quotes around it. Just set the variable like this:
var fileStatus = <?php echo $uploadData; ?>;
or:
var fileStatus = <?=$uploadData?>;
Do not do this:
var fileStatus = '<?php echo $uploadData; ?>';
I'm trying to access the individual member-fields of a JSON object in PHP from a JSON string but I can't to access the inner-json, all I get is Array.
This is the JSON string
data = (
{
"created_time" = "2018-10-07T04:42:39+0000";
id = 1069496473131329;
name = "NAME_0";
},
{
"created_time" = "2018-09-09T10:31:50+0000";
id = 955684974605664;
name = "NAME_1";
},
At the moment my code is:
$nameString = $_POST["nameData"];
$nameJsonString = json_encode($nameString, JSON_FORCE_OBJECT);
$jsonNameObj = json_decode($nameJsonString, true);
I've been trying to access the individual entry with:
$element = $jsonNameObj['data'][0];
But only receive Array.
Any help would be greatly appreciated,
Cheers :)
After checking the inputted JSON data, I've realised that it doesn't have a consistent form. As opposed to the overall structure being:
JSON -> List -> JSON
Instead, it's:
JSON -> List
The list contains individual elements that can be in a different order. Consequently, calling:
$element = $jsonNameObj['data'][0]['created_time'];
Works sometimes. As there are three-values/object, I can congregate these values into a trio.
I'm sure there's a way to condense this list into a fixed-JSON format but I'm not familiar with how I'd go about that.
At the moment, with a bit of logic on the back-end, I can retrieve the values.
Thanks for your help #Difster and #Osama!