Check with Carbon if a date is on a different day [duplicate] - php

I have two Datetimes like this (the dates being actually $vars)
$startTime = \DateTime::createFromFormat('Y/m/d H:i', '2015/01/01 23:00');
$endTime = \DateTime::createFromFormat('Y/m/d H:i', '2015/01/02 01:00');
I struggle with a (possibly pretty) simple problem: How could I determine if the two dates are on different calendar days?
I cannot do < as 2015/01/01 22:00 < 2015/01/01 23:00 would also be true. I can also not do this:
$diff = $startTime->diff($endTime);
$days = $diff->format('%d');
echo $days;
as it gives me 0.
THIS gives me an idea about how to do it, but for javascript, what would be the equivalent for php?
//UPDATE
$startDate = $startTime->format('Y/m/d');
$endDate = $endTime->format('Y/m/d');
$diffDates = $startDate->diff($endDate);
$daysDiff = $diffDates->format('%d');
echo $daysDiff;
I think that might be the right approach now, thanks to the comments, but now I get Error: Call to a member function diff() on string
//UPDATE FOR CLARIFICATION WHAT I'M TRYING TO DO
I just want to have the difference in days, so for the above it would be '1' (although only 2 hours difference actually) and for example '2015/01/01 23:00' and '2015/01/03 17:00' would be '2'.

Just create the dates with time set to 00:00:00:
$startTime = \DateTime::createFromFormat('Y/m/d H:i:s', '2015/01/01 00:00:00');
$endTime = \DateTime::createFromFormat('Y/m/d H:i:s', '2015/01/02 00:00:00');
or reset time to zero on existing dates:
$startTime->setTime(0, 0, 0);
$endTime->setTime(0, 0, 0);
then it should work:
$diff = $startTime->diff($endTime);
$days = $diff->format('%d');
echo $days; // 1
Bonus
If you want to work only with dates, remember to set the time to 00:00:00 in createFromFormat or reset it with setTime. If you won't provide time in createFromFormat PHP will set it to the current time:
$date = DateTime::createFromFormat('Y-m-d', '2016-01-21');
print $date->format('H:i:s'); //not 00:00:00
To fix it, you must either:
provide 00:00:00 time in format:
$date = DateTime::createFromFormat('Y-m-d H:i:s', '2016-01-21 00:00:00');
prefix the date format with exclamation mark and omit the time, this will set the time to 00:00:00 automatically:
$date = DateTime::createFromFormat('!Y-m-d', '2016-01-21');
reset the time after creation:
$date = DateTime::createFromFormat('Y-m-d', '2016-01-21');
$date->setTime(0, 0);

I think this is one of the few situations where the use of strings for date calculations is justified:
function onDifferentDays(\DateTimeInterface $startTime, \DateTimeInterface $endTime){
return $startTime->format('Y-m-d')!==$endTime->format('Y-m-d');
}
This code should be easy to extend to include time zone.
There're other alternatives but I don't think they're normally worth the effort:
Compare element by element (day, month and year):
The PHP DateTime class doesn't offer dedicated functions, only format().
Normalize both dates to a common time and compare with == (not ===):
Unless you're using immutable objects you need to clone input or expect side effects
You also need to ensure that time exists in the active time zone though midnight is probably safe enough.
Whatever, YMMV ;-)

Comparing formatted dates is the right thing to do:
$a->format('Y-m-d') === $b->format('Y-m-d')
There is a method for that if you use Carbon:
$dt1->isSameDay($dt2)
So I recommend to use it instead of previous answers given here.
http://carbondoc/docs/#api-comparison

Related

How can I create a zero DateTime with php?

I need to create an empty date with DateTime(). So, all zeros. The time should be displayed in that way: 0000:00:0:00:00.
What I have tried:
$date = new DateTime("2019-05-09 12:07");
$date->setTime(0, 0);
$date->setDate(0, 0, 0);
echo $date->format("Y:W:j:H:i");
That outputs
-0001:49:30:00:00
instead of 0000:00:0:00:00
What could I do to achieve a zero datetime?
More an explanation of what is going wrong than how to achieve what you are after - even if it is possible.
From a date point of view - 0 is invalid for both the month and day. In the manual it has the example
Example #2 Values exceeding ranges are added to their parent values
So if you have greater than the number of days in a month, it will make it the next month
In your case it is almost the opposite, having a number less than the start of the month. So 0 as the month and day, it will act as -1, so if you formatted it as
echo $date->format("Y:m:d:H:i");
the output is
-0001:11:30:00:00
So as you can see, the day and month are 0-1 (11 and 30) and this has overflowed into the year with -1.
No, You cannot make a datetime 0000:00:0:00:00 from DateTime()
php > echo (new DateTime("0000-00-00 00:00:00"))->format("Y-W-j H:i");
-0001-49-30 00:00
php > echo (new DateTime())->setISODate(0,0,0)->setTime(0,0,0,0)->format("Y-W-j H:i");
-0001-52-26 00:00
Surely Not..!
although you can create any Date with PHP helper function (that uses DateTime class behind) any of you desire date with Zeor Time only
$date = date_create('now'); // or any '1970-01-01'
$date = date_format($date, 'Y-m-d 00:00:00');
// or
$date = date('Y-m-d 00:00:00', strtotime('2021-12-21'));
// or
$date = date('Y-m-d 00:00:00');
output: "2021-12-21 00:00:00"
you can initialize the time with current time and take difference of the current time after. its a trick you can perfom to get (0000-00-00 00:00:00).
$currentTime = new DateTime('NOW');
$diff = $currentTime->diff(new DateTime('NOW'));
echo $diff->format("%Y-%m-%d %H %i %s");
that will give you 0000-00-00 00:00:00

hh:mm:ss difference return wrong answer in php

I am using this code to calculate the time period. In fact, I want the period between two HH:MM:SS moment and have a result in HH:MM:SS format.
$time1 = strtotime('00:00:00');
$time2 = strtotime('00:00:07');
$diff = $time2 - $time1;
$diff = date('H:i:s', $diff);
I'm expecting 00:00:07 but I get 01:00:07. What could be the problem?
Irvin run here, and get right answer but I run the same code on my local machine and wrong!!
Is it timezone or maybe some configuration effect the result?!
Please stop using strtotime and date functions. Use the DateTime class.
And if you would have searched better, finding difference for two dates has already been all over SO. For instance, my answer here. Slightly changed it would look like:
$create_time = "00:00:00";
$current_time="00:00:07";
$dtCurrent = DateTime::createFromFormat('H:i:s', $current_time);
$dtCreate = DateTime::createFromFormat('H:i:s', $create_time);
$diff = $dtCurrent->diff($dtCreate);
echo $diff->format("%H:%I:%S"); // to get HH:MM:SS format
This returns 00:00:07
See DateInterval::format for more formatting details.
It's because when you minus time 1 from time 2 you end up with 7;
The date function needs a timestamp, 7 is not a timestamp.
You could use http://php.net/manual/en/datetime.diff.php to calculate the difference instead?
You should consider the UNIX epoch which cancels timezone diffrences in ini settings, essentially. it's Jan 1st '70. You can check your server/app's setup for timezone by adding e, O or P. Check this code:
$time1 = strtotime('00:00:00 +0000');
$time2 = strtotime('00:00:07 +0000');
$epoch = strtotime('01 Jan 1970');
$diff = $time2 - $time1;
var_dump($time1,$time2,$epoch,$diff);
$diff = date('H:i:s', $epoch+$diff);
echo $diff;

Difference between timestamps in minutes in PHP

I want to get difference between 2 timestamps of format Y-m-d H:i:s in minutes in PHP.
The code used is,
$currentDate = date('Y-m-d H:i:s');
$userLastActivity = date($date);
$timeLapse = (($currentDate - $userLastActivity)/60);
Here, $date is obtained from database.
The value of $timeLapse is 0 in output. Please help.
Try using unix timestamp. Practically it measures the time in seconds from 1/1/1970 and it's a lot easier to use and understand than a php object.
$currentTimestamp = new DateTime()->getTimestamp();
$userLastActivity = date($date)->getTimestamp();
$timeLapse = (($currentDate - $userLastActivity)/60);
You should have the time saved as timestamp on the server too, in that case you could use the $date directly as a number, with no need for a conversion. And also, because it's universal, you can pass it around to javascript or any other language without any worries for conversion
Use strtotime to parse textual datetime into a Unix timestamp and substract $userLastActivity from $currentDate and divide by 60.
See if this helps -
<?php
$currentDate = strtotime(date('Y-m-d H:i:s'));
$date = "2016-10-11 02:40:50";
$userLastActivity = strtotime($date);
echo round(abs($currentDate - $userLastActivity) / 60). " minutes";
?>
For more details :strtotime
Change these 2 lines for a start, as I don't think dividing dates by 60 is gonna work to well.
$currentDate = time();
$userLastActivity = strtotime($date);
That way you have time stamps and not dates (string)

PHP check if two Datetimes are not on the same calendar day

I have two Datetimes like this (the dates being actually $vars)
$startTime = \DateTime::createFromFormat('Y/m/d H:i', '2015/01/01 23:00');
$endTime = \DateTime::createFromFormat('Y/m/d H:i', '2015/01/02 01:00');
I struggle with a (possibly pretty) simple problem: How could I determine if the two dates are on different calendar days?
I cannot do < as 2015/01/01 22:00 < 2015/01/01 23:00 would also be true. I can also not do this:
$diff = $startTime->diff($endTime);
$days = $diff->format('%d');
echo $days;
as it gives me 0.
THIS gives me an idea about how to do it, but for javascript, what would be the equivalent for php?
//UPDATE
$startDate = $startTime->format('Y/m/d');
$endDate = $endTime->format('Y/m/d');
$diffDates = $startDate->diff($endDate);
$daysDiff = $diffDates->format('%d');
echo $daysDiff;
I think that might be the right approach now, thanks to the comments, but now I get Error: Call to a member function diff() on string
//UPDATE FOR CLARIFICATION WHAT I'M TRYING TO DO
I just want to have the difference in days, so for the above it would be '1' (although only 2 hours difference actually) and for example '2015/01/01 23:00' and '2015/01/03 17:00' would be '2'.
Just create the dates with time set to 00:00:00:
$startTime = \DateTime::createFromFormat('Y/m/d H:i:s', '2015/01/01 00:00:00');
$endTime = \DateTime::createFromFormat('Y/m/d H:i:s', '2015/01/02 00:00:00');
or reset time to zero on existing dates:
$startTime->setTime(0, 0, 0);
$endTime->setTime(0, 0, 0);
then it should work:
$diff = $startTime->diff($endTime);
$days = $diff->format('%d');
echo $days; // 1
Bonus
If you want to work only with dates, remember to set the time to 00:00:00 in createFromFormat or reset it with setTime. If you won't provide time in createFromFormat PHP will set it to the current time:
$date = DateTime::createFromFormat('Y-m-d', '2016-01-21');
print $date->format('H:i:s'); //not 00:00:00
To fix it, you must either:
provide 00:00:00 time in format:
$date = DateTime::createFromFormat('Y-m-d H:i:s', '2016-01-21 00:00:00');
prefix the date format with exclamation mark and omit the time, this will set the time to 00:00:00 automatically:
$date = DateTime::createFromFormat('!Y-m-d', '2016-01-21');
reset the time after creation:
$date = DateTime::createFromFormat('Y-m-d', '2016-01-21');
$date->setTime(0, 0);
I think this is one of the few situations where the use of strings for date calculations is justified:
function onDifferentDays(\DateTimeInterface $startTime, \DateTimeInterface $endTime){
return $startTime->format('Y-m-d')!==$endTime->format('Y-m-d');
}
This code should be easy to extend to include time zone.
There're other alternatives but I don't think they're normally worth the effort:
Compare element by element (day, month and year):
The PHP DateTime class doesn't offer dedicated functions, only format().
Normalize both dates to a common time and compare with == (not ===):
Unless you're using immutable objects you need to clone input or expect side effects
You also need to ensure that time exists in the active time zone though midnight is probably safe enough.
Whatever, YMMV ;-)
Comparing formatted dates is the right thing to do:
$a->format('Y-m-d') === $b->format('Y-m-d')
There is a method for that if you use Carbon:
$dt1->isSameDay($dt2)
So I recommend to use it instead of previous answers given here.
http://carbondoc/docs/#api-comparison

Given a Unix timestamp, how to get beginning and end of that day?

I have a Unix timestamp like this:
$timestamp=1330581600
How do I get the beginning of the day and the end of the day for that timestamp?
e.g.
$beginOfDay = Start of Timestamp's Day
$endOfDay = End of Timestamp's Day
I tried this:
$endOfDay = $timestamp + (60 * 60 * 23);
But I don't think it'll work because the timestamp itself isn't the exact beginning of the day.
strtotime can be used to to quickly chop off the hour/minutes/seconds
$beginOfDay = strtotime("today", $timestamp);
$endOfDay = strtotime("tomorrow", $beginOfDay) - 1;
DateTime can also be used, though requires a few extra steps to get from a long timestamp
$dtNow = new DateTime();
// Set a non-default timezone if needed
$dtNow->setTimezone(new DateTimeZone('Pacific/Chatham'));
$dtNow->setTimestamp($timestamp);
$beginOfDay = clone $dtNow;
$beginOfDay->modify('today');
$endOfDay = clone $beginOfDay;
$endOfDay->modify('tomorrow');
// adjust from the start of next day to the end of the day,
// per original question
// Decremented the second as a long timestamp rather than the
// DateTime object, due to oddities around modifying
// into skipped hours of day-lights-saving.
$endOfDateTimestamp = $endOfDay->getTimestamp();
$endOfDay->setTimestamp($endOfDateTimestamp - 1);
var_dump(
array(
'time ' => $dtNow->format('Y-m-d H:i:s e'),
'start' => $beginOfDay->format('Y-m-d H:i:s e'),
'end ' => $endOfDay->format('Y-m-d H:i:s e'),
)
);
With the addition of extended time in PHP7, there is potential to miss a second if using $now <= $end checking with this.
Using $now < $nextStart checking would avoid that gap, in addition to the oddities around subtracting seconds and daylight savings in PHP's time handling.
Just DateTime
$beginOfDay = DateTime::createFromFormat('Y-m-d H:i:s', (new DateTime())->setTimestamp($timestamp)->format('Y-m-d 00:00:00'))->getTimestamp();
$endOfDay = DateTime::createFromFormat('Y-m-d H:i:s', (new DateTime())->setTimestamp($timestamp)->format('Y-m-d 23:59:59'))->getTimestamp();
First a DateTime object is created and the timestamp is set to the desired timestamp. Then the object is formatted as a string setting the hour/minute/second to the beginning or end of the day. Lastly, a new DateTime object is created from this string and the timestamp is retrieved.
Readable
$dateTimeObject = new DateTime();
$dateTimeObject->setTimestamp($timestamp);
$beginOfDayString = $dateTimeObject->format('Y-m-d 00:00:00');
$beginOfDayObject = DateTime::createFromFormat('Y-m-d H:i:s', $beginOfDayString);
$beginOfDay = $beginOfDayObject->getTimestamp();
We can get the end of the day in an alternate manner using this longer version:
$endOfDayObject = clone $beginOfDayOject(); // Cloning because add() and sub() modify the object
$endOfDayObject->add(new DateInterval('P1D'))->sub(new DateInterval('PT1S'));
$endOfDay = $endOfDayOject->getTimestamp();
Timezone
The timezone can be set as well by adding a timestamp indicator to the format such as O and specifying the timestamp after creating the DateTime object:
$beginOfDay = DateTime::createFromFormat('Y-m-d H:i:s O', (new DateTime())->setTimezone(new DateTimeZone('America/Los_Angeles'))->setTimestamp($timestamp)->format('Y-m-d 00:00:00 O'))->getTimestamp();
Flexibility of DateTime
We can also get other information such as the beginning/end of the month or the beginning/end of the hour by changing the second format specified. For month: 'Y-m-01 00:00:00' and 'Y-m-t 23:59:59'. For hour: 'Y-m-d H:00:00' and 'Y-m-d H:59:59'
Using various formats in combination with add()/sub() and DateInterval objects, we can get the beginning or end of any period, although some care will need to be taken to handle leap years correctly.
Relevant Links
From the PHP docs:
DateTime
date with info on the format
DateTimeZone
DateInterval
You can use a combination of date() and mktime():
list($y,$m,$d) = explode('-', date('Y-m-d', $ts));
$start = mktime(0,0,0,$m,$d,$y);
$end = mktime(0,0,0,$m,$d+1,$y);
mktime() is smart enough to wrap months/years when given a day outside the specified month (jan 32nd will be feb 1st, etc)
You could convert the time to the current data and then use the strtotime function to find the start of the day and simply add 24 hours to that to find the end of the day.
You could also use the remainder operator (%) to find the nearest day. For example:
$start_of_day = time() - 86400 + (time() % 86400);
$end_of_day = $start_of_day + 86400;
The accepted answer unfortunately breaks due to a php bug that occurs in very specific scenarios. I'll discuss those scenarios, but first the answer using DateTime. The only difference between this and the accepted answer occurs after the // IMPORTANT line:
$dtNow = new DateTime();
// Set a non-default timezone if needed
$dtNow->setTimezone(new DateTimeZone('America/Havana'));
$dtNow->setTimestamp($timestamp);
$beginOfDay = clone $dtNow;
// Go to midnight. ->modify('midnight') does not do this for some reason
$beginOfDay->modify('today');
// now get the beginning of the next day
$endOfDay = clone $beginOfDay;
$endOfDay->modify('tomorrow');
// IMPORTANT
// get the timestamp
$ts = $endOfDay->getTimestamp();
// subtract one from that timestamp
$tsEndOfDay = $ts - 1;
// we now have the timestamp at the end of the day. we can now use that timestamp
// to set our end of day DateTime
$endOfDay->setTimestamp($tsEndOfDay);
So you'll note that instead of using ->modify('1 second ago'); we instead get the timestamp and subtract one. The accepted answer using modify should work, but breaks because of php bug in very specific scenarios. This bug occurs in timezones that change daylight savings at midnight, on the day of the year that clocks are moved "forward". Here is an example you can use to verify that bug.
bug example code
// a time zone, Cuba, that changes their clocks forward exactly at midnight. on
// the day before they make that change. there are other time zones which do this
$timezone = 'America/Santiago';
$dateString = "2020-09-05";
echo 'the start of the day:<br>';
$dtStartOfDay = clone $dtToday;
$dtStartOfDay->modify('today');
echo $dtStartOfDay->format('Y-m-d H:i:s');
echo ', '.$dtStartOfDay->getTimestamp();
echo '<br><br>the start of the *next* day:<br>';
$dtEndOfDay = clone $dtToday;
$dtEndOfDay->modify('tomorrow');
echo $dtEndOfDay->format('Y-m-d H:i:s');
echo ', '.$dtEndOfDay->getTimestamp();
echo '<br><br>the end of the day, this is incorrect. notice that with ->modify("-1 second") the second does not decrement the timestamp by 1:<br>';
$dtEndOfDayMinusOne = clone $dtEndOfDay;
$dtEndOfDayMinusOne->modify('1 second ago');
echo $dtEndOfDayMinusOne->format('Y-m-d H:i:s');
echo ', '.$dtEndOfDayMinusOne->getTimestamp();
echo '<br><br>the end of the day, this is correct:<br>';
$dtx = clone $dtEndOfDay;
$tsx = $dtx->getTimestamp() - 1;
$dty = clone $dtEndOfDay;
$dty->setTimestamp($tsx);
echo $dty->format('Y-m-d H:i:s');
echo ', '.$tsx;
bug example code output
the start of the day:
2020-03-26 00:00:00, 1585173600
the start of the *next* day:
2020-03-27 01:00:00, 1585260000
the end of the day, this is incorrect. notice that with ->modify("1 second ago") the
second does not decrement the timestamp by 1:
2020-03-27 01:59:59, 1585263599
the end of the day, this is correct:
2020-03-26 23:59:59, 1585259999
Today Starting date timestamp. Simple
$stamp = mktime(0, 0, 0);
echo date('m-d-Y H:i:s',$stamp);
$start_of_day = floor (time() / 86400) * 86400;
$end_of_day = ceil (time() / 86400) * 86400;
If your need both values in the same script. It is faster to +/- 86400 seconds to one of the variables than to fire both floor and ceil. For example:
$start_of_day = floor (time() / 86400) * 86400;
$end_of_day = $start_of_day + 86400;
For anyone that have this question in the future:
Any day code
<?php
$date = "2015-04-12 09:20:00";
$midnight = strtotime("midnight", strtotime($date));
$now = strtotime($date);
$diff = $now - $midnight;
echo $diff;
?>
Current day code
<?php
$midnight = strtotime("midnight");
$now = date('U');
$diff = $now - $midnight;
echo $diff;
?>
$date = (new \DateTime())->setTimestamp(1330581600);
echo $date->modify('today')->format('Y-m-d H:i:s'); // 2012-02-29 00:00:00
echo PHP_EOL;
echo $date->modify('tomorrow - 1 second')->format('Y-m-d H:i:s'); // 2012-02-29 23:59:59
$startOfDay = new \DateTime('tomorrow');
$startOfDay->modify('-1 day');
This works for me :)
A little late to the party, but here's another easy way to achieve what you're looking for:
$timestamp=1330581600;
$format = DATE_ATOM;
$date = (new DateTime())->setTimestamp($timestamp);
// Here's your initial date, created from the timestamp above
// 2012-03-01T06:00:00+00:00
$dateFromTimestamp = $date->format($format);
// This is the beginning of the day
// 2012-03-01T00:00:00+00:00
$startOfDay = $date->setTime(0,0);
// This is the beginning of the next day
// 2012-03-02T00:00:00+00:00
$startOfNextDay = $startOfDay->modify('+1 day');
I would personally avoid using the end of the day unless it's absolutely necessary. You can, of course, use 23:59:59 but this is not the actual end of the day (there's still 1 second left). What I do is use the start of the next day as my end boundary, for example:
$start = new DateTime('2021-11-09 00:00:00');
$end = new DateTime('2021-11-10 00:00:00');
if ($someDateTime >= $start && $someDateTime < $end) {
// do something
}
If I must use the end of the day, I'd go with calculating the start of the next day and then subtracting 1 microsecond from that.
$beginOfDay = (new DateTime('today', new DateTimeZone('Asia/Tehran')))->getTimestamp();
$endOfDay = $beginOfDay + 86399;
You can set a timezone by replacing "Asia/Tehran". One day is 86400 seconds, Don't ask me why 86399, It is a whisper in my mind that says it is 86399, So I do not even want to think about its truth.

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