I need to create an empty date with DateTime(). So, all zeros. The time should be displayed in that way: 0000:00:0:00:00.
What I have tried:
$date = new DateTime("2019-05-09 12:07");
$date->setTime(0, 0);
$date->setDate(0, 0, 0);
echo $date->format("Y:W:j:H:i");
That outputs
-0001:49:30:00:00
instead of 0000:00:0:00:00
What could I do to achieve a zero datetime?
More an explanation of what is going wrong than how to achieve what you are after - even if it is possible.
From a date point of view - 0 is invalid for both the month and day. In the manual it has the example
Example #2 Values exceeding ranges are added to their parent values
So if you have greater than the number of days in a month, it will make it the next month
In your case it is almost the opposite, having a number less than the start of the month. So 0 as the month and day, it will act as -1, so if you formatted it as
echo $date->format("Y:m:d:H:i");
the output is
-0001:11:30:00:00
So as you can see, the day and month are 0-1 (11 and 30) and this has overflowed into the year with -1.
No, You cannot make a datetime 0000:00:0:00:00 from DateTime()
php > echo (new DateTime("0000-00-00 00:00:00"))->format("Y-W-j H:i");
-0001-49-30 00:00
php > echo (new DateTime())->setISODate(0,0,0)->setTime(0,0,0,0)->format("Y-W-j H:i");
-0001-52-26 00:00
Surely Not..!
although you can create any Date with PHP helper function (that uses DateTime class behind) any of you desire date with Zeor Time only
$date = date_create('now'); // or any '1970-01-01'
$date = date_format($date, 'Y-m-d 00:00:00');
// or
$date = date('Y-m-d 00:00:00', strtotime('2021-12-21'));
// or
$date = date('Y-m-d 00:00:00');
output: "2021-12-21 00:00:00"
you can initialize the time with current time and take difference of the current time after. its a trick you can perfom to get (0000-00-00 00:00:00).
$currentTime = new DateTime('NOW');
$diff = $currentTime->diff(new DateTime('NOW'));
echo $diff->format("%Y-%m-%d %H %i %s");
that will give you 0000-00-00 00:00:00
Related
I have two Datetimes like this (the dates being actually $vars)
$startTime = \DateTime::createFromFormat('Y/m/d H:i', '2015/01/01 23:00');
$endTime = \DateTime::createFromFormat('Y/m/d H:i', '2015/01/02 01:00');
I struggle with a (possibly pretty) simple problem: How could I determine if the two dates are on different calendar days?
I cannot do < as 2015/01/01 22:00 < 2015/01/01 23:00 would also be true. I can also not do this:
$diff = $startTime->diff($endTime);
$days = $diff->format('%d');
echo $days;
as it gives me 0.
THIS gives me an idea about how to do it, but for javascript, what would be the equivalent for php?
//UPDATE
$startDate = $startTime->format('Y/m/d');
$endDate = $endTime->format('Y/m/d');
$diffDates = $startDate->diff($endDate);
$daysDiff = $diffDates->format('%d');
echo $daysDiff;
I think that might be the right approach now, thanks to the comments, but now I get Error: Call to a member function diff() on string
//UPDATE FOR CLARIFICATION WHAT I'M TRYING TO DO
I just want to have the difference in days, so for the above it would be '1' (although only 2 hours difference actually) and for example '2015/01/01 23:00' and '2015/01/03 17:00' would be '2'.
Just create the dates with time set to 00:00:00:
$startTime = \DateTime::createFromFormat('Y/m/d H:i:s', '2015/01/01 00:00:00');
$endTime = \DateTime::createFromFormat('Y/m/d H:i:s', '2015/01/02 00:00:00');
or reset time to zero on existing dates:
$startTime->setTime(0, 0, 0);
$endTime->setTime(0, 0, 0);
then it should work:
$diff = $startTime->diff($endTime);
$days = $diff->format('%d');
echo $days; // 1
Bonus
If you want to work only with dates, remember to set the time to 00:00:00 in createFromFormat or reset it with setTime. If you won't provide time in createFromFormat PHP will set it to the current time:
$date = DateTime::createFromFormat('Y-m-d', '2016-01-21');
print $date->format('H:i:s'); //not 00:00:00
To fix it, you must either:
provide 00:00:00 time in format:
$date = DateTime::createFromFormat('Y-m-d H:i:s', '2016-01-21 00:00:00');
prefix the date format with exclamation mark and omit the time, this will set the time to 00:00:00 automatically:
$date = DateTime::createFromFormat('!Y-m-d', '2016-01-21');
reset the time after creation:
$date = DateTime::createFromFormat('Y-m-d', '2016-01-21');
$date->setTime(0, 0);
I think this is one of the few situations where the use of strings for date calculations is justified:
function onDifferentDays(\DateTimeInterface $startTime, \DateTimeInterface $endTime){
return $startTime->format('Y-m-d')!==$endTime->format('Y-m-d');
}
This code should be easy to extend to include time zone.
There're other alternatives but I don't think they're normally worth the effort:
Compare element by element (day, month and year):
The PHP DateTime class doesn't offer dedicated functions, only format().
Normalize both dates to a common time and compare with == (not ===):
Unless you're using immutable objects you need to clone input or expect side effects
You also need to ensure that time exists in the active time zone though midnight is probably safe enough.
Whatever, YMMV ;-)
Comparing formatted dates is the right thing to do:
$a->format('Y-m-d') === $b->format('Y-m-d')
There is a method for that if you use Carbon:
$dt1->isSameDay($dt2)
So I recommend to use it instead of previous answers given here.
http://carbondoc/docs/#api-comparison
is it possible to add a variable string like '2 day, 2 weeks or even 4 hours' to a date time in PHP.
For example:
I have a date time like this: '2017-08-02 12:00'
now the user choose an interval like '4 hours or 2 weeks'
now the user choice should be added to the date time.
Is this possible?
I don't want the whole code, maybe just an advice how to do that.
thanks
Yes, use
$userDate = strtotime('2017-08-02 12:00:00');
echo date('Y-m-d H:i:s', strtotime('+4 hours', $userDate));
to get date after 4 hours
Example
Explanation
strtotime converts about any English textual datetime description into a Unix timestamp. Most commonly it's used with actual date string or with difference string. E.g. +5 months, 'next Monday' and so on. It will return Unix timestamp - integer that represents how much seconds there is after 1970-01-01 (1970-01-01 00:00:00 is 0, 1970-01-01 00:01:00 is 60 and so on).
So in strtotime('2017-08-02 12:00:00') we convert date to integer for later use.
strtotime('+4 hours', $userDate) - here we use our date as "now" parameter (by default it's time()) and requesting to return timestamp after 4 hours.
echo date('Y-m-d H:i:s', ...); - date accepts format and Unix timestamp to convert from integer back to human readable text.
May be you are looking for this:
http://php.net/manual/en/datetime.modify.php
$date = new DateTime('2006-12-12');
$date->modify('+1 day');
echo $date->format('Y-m-d');
For a datetime you can use the add method but you have to put in the correct code for the amount to add.
$my_date = new DateTime();
$addition = 4;
$my_new_date = $my_date->add(new DateInterval("P${addition}D"));
echo $my_new_date->format('Y-m-d H:i:s');
Where addition is your variable that you want to add.
I have two Datetimes like this (the dates being actually $vars)
$startTime = \DateTime::createFromFormat('Y/m/d H:i', '2015/01/01 23:00');
$endTime = \DateTime::createFromFormat('Y/m/d H:i', '2015/01/02 01:00');
I struggle with a (possibly pretty) simple problem: How could I determine if the two dates are on different calendar days?
I cannot do < as 2015/01/01 22:00 < 2015/01/01 23:00 would also be true. I can also not do this:
$diff = $startTime->diff($endTime);
$days = $diff->format('%d');
echo $days;
as it gives me 0.
THIS gives me an idea about how to do it, but for javascript, what would be the equivalent for php?
//UPDATE
$startDate = $startTime->format('Y/m/d');
$endDate = $endTime->format('Y/m/d');
$diffDates = $startDate->diff($endDate);
$daysDiff = $diffDates->format('%d');
echo $daysDiff;
I think that might be the right approach now, thanks to the comments, but now I get Error: Call to a member function diff() on string
//UPDATE FOR CLARIFICATION WHAT I'M TRYING TO DO
I just want to have the difference in days, so for the above it would be '1' (although only 2 hours difference actually) and for example '2015/01/01 23:00' and '2015/01/03 17:00' would be '2'.
Just create the dates with time set to 00:00:00:
$startTime = \DateTime::createFromFormat('Y/m/d H:i:s', '2015/01/01 00:00:00');
$endTime = \DateTime::createFromFormat('Y/m/d H:i:s', '2015/01/02 00:00:00');
or reset time to zero on existing dates:
$startTime->setTime(0, 0, 0);
$endTime->setTime(0, 0, 0);
then it should work:
$diff = $startTime->diff($endTime);
$days = $diff->format('%d');
echo $days; // 1
Bonus
If you want to work only with dates, remember to set the time to 00:00:00 in createFromFormat or reset it with setTime. If you won't provide time in createFromFormat PHP will set it to the current time:
$date = DateTime::createFromFormat('Y-m-d', '2016-01-21');
print $date->format('H:i:s'); //not 00:00:00
To fix it, you must either:
provide 00:00:00 time in format:
$date = DateTime::createFromFormat('Y-m-d H:i:s', '2016-01-21 00:00:00');
prefix the date format with exclamation mark and omit the time, this will set the time to 00:00:00 automatically:
$date = DateTime::createFromFormat('!Y-m-d', '2016-01-21');
reset the time after creation:
$date = DateTime::createFromFormat('Y-m-d', '2016-01-21');
$date->setTime(0, 0);
I think this is one of the few situations where the use of strings for date calculations is justified:
function onDifferentDays(\DateTimeInterface $startTime, \DateTimeInterface $endTime){
return $startTime->format('Y-m-d')!==$endTime->format('Y-m-d');
}
This code should be easy to extend to include time zone.
There're other alternatives but I don't think they're normally worth the effort:
Compare element by element (day, month and year):
The PHP DateTime class doesn't offer dedicated functions, only format().
Normalize both dates to a common time and compare with == (not ===):
Unless you're using immutable objects you need to clone input or expect side effects
You also need to ensure that time exists in the active time zone though midnight is probably safe enough.
Whatever, YMMV ;-)
Comparing formatted dates is the right thing to do:
$a->format('Y-m-d') === $b->format('Y-m-d')
There is a method for that if you use Carbon:
$dt1->isSameDay($dt2)
So I recommend to use it instead of previous answers given here.
http://carbondoc/docs/#api-comparison
I can add x week to my date
//$ultima_azione <--- 2015/07/15
//$data['intervallo'] <---- 5
$mydate = date("Y-m-d",strtotime($ultima_azione." +".$data['intervallo']." weeks"));
now how can i give a day starting from that week
example:
//$mydate + "next Monday" -----> final date
and this ve to work like, if today is Monday and i add weeks to jump to an other Monday and then i select the next Monday the week don't ve to change
The simplest way would be to use strtotime. It can do date calculations based on a textual representation of the delta:
$mydate = strtotime('+3 weeks');
It also accepts a second parameter, which is a timestamp to start from when doing the calculation, so after you get the offset in weeks, you can pass the new date to a second calculation:
// Get three weeks from 'now' (no explicit time given)
$mydate = strtotime('+3 weeks');
// Get the Monday after that.
$mydate = strtotime('next Monday', $mydate);
See strtotime documentation for more examples of notations that you can use.
I would highly recommend using PHP's built-in DateTime class for any date and time logic. It's a much better API than the older date and time functions and creates much cleaner and easier to read code.
For example:
// Current date and number of weeks to add
$date = '2015/07/15';
$weeks = 3;
// Create and modify the date.
$dateTime = DateTime::createFromFormat('Y/m/d', $date);
$dateTime->add(DateInterval::createFromDateString($weeks . ' weeks'));
$dateTime->modify('next monday');
// Output the new date.
echo $dateTime->format('Y-m-d');
References:
DateTime.
DateTime::createFromFormat
DateTime::add
DateTime::modify
DateInterval::createFromDateString
DateTime::format
Are you looking for something like this?
$today = time();
$weeks = 2;
// timestamp 2 weeks from now
$futureWeeks = strtotime("+ ".$weeks." weeks");
// the next monday after the timestamp date
$futureMonday = strtotime("next monday",$futureWeeks);
echo date("Y-m-d", $futureMonday);
// or in one line
echo date("Y-m-d", strtotime("next monday", strtotime("+ ".$weeks." weeks")));
PHP is using an unix timestamp for date calculations. Functions as date() and strtotime() using a timestamp as an optional second parameter. This is used a reference for formatting and calculations. If no timestamp is passed to the function the current timestamp is used (time()).
I have the answer here. This will show the next wednesday every 2 weeks and the first date to start from would be the 10th.
I have also added in an estimated delivery which would be 6 weeks after that date.
We will be placing our next order for this on:
<?php
$date = '2020/05/26';
$weeks = 2;
$dateTime = DateTime::createFromFormat('Y/m/d', $date);
$dateTime->add(DateInterval::createFromDateString($weeks . ' weeks'));
$dateTime->modify('wednesday');
echo $dateTime->format('d/m/Y');
?>
Expected delivery for the next order will be:
<?php
$date = '2020/05/26';
$weeks = 2;
$dateTime = DateTime::createFromFormat('Y/m/d', $date);
$dateTime->add(DateInterval::createFromDateString($weeks . ' weeks'));
$dateTime->modify('+42 days next wednesday');
echo $dateTime->format('d/m/Y');
?>
If anyone can confirm this is correct that would be great.
Assume the date is:
$date = "2011-08-28";
It need to calculate 3 months previous to $date - how can that be done?
$new_timestamp = strtotime('-3 months', strtotime($date));
You can then use the new timestamp with the php date() function to display the new date how you wish, for example:
echo date("Y-m-d",$new_timestamp);
For me this way is much better because the code is more readable.
$datetime = Datetime::createFromFormat('Y-m-d', "2011-08-28");
$datetime->modify('-3 months');
echo $datetime->format('Y-m-d');
edit: I'm an idiot. You could do the above as follows
$datetime = new Datetime("2011-08-28");
$datetime->modify('-3 months');
echo $datetime->format('Y-m-d');
edit: As pointed out by calumbrodie, you can use the sub method instead of inverting the interval and adding it to the date object
I was trying to do something similar to the original question. I needed to subtract 1 day from a DateTime object. I know the other solutions work, but here's another way I liked better. I used this function:
function getPreviousDay($dateObject){
$interval = new DateInterval('P1D');
$dateObject->sub($interval);
return $dateObject;
}
$dateObject is a DateTime object that can have any date you wan't, but as I wanted the current date, I wrote:
$dateObject = new DateTime('now');
What my function does, is subtract 1 day from the date it receives, but you can modify it so it subtracts 3 months modifying the DateInterval constructor like this:
$interval = new DateInterval('P3M');
$dateObject->sub($interval);
return $dateObject;
You can find the explanation on the string format used in the DateInterval constructor here
DateInterval constructor documentation
There you'll se that letter 'P' (period) is mandatory, the you use an int to specify period length and then specify the period type, in the case of months 'M'. It looks as if there was an error in the documentation, it says that "M" is used for months and minutes, but it actually works for months. If you need to use minutes, you must specify "PTM", for example "PT3M" for 3 minutes, outside the table it says you must use the "T" identifier for time intervals.
edit:
To give a complete example, you have to use this format for a full date time interval:
$format = 'P1Y2M4DT2H1M40S';
This will represent an interval of 1 year, 2 months, 4 days, 2 hours,1 minute and 40 seconds
Hope this helps someone
<?php
$threemonthsago = mktime(0, 0, 0, date("m")-3, date("d"), date("Y"));
?>
<?php
$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>