PHP trying to add values to an array in a while loop - php

Question

I want to pull rows from the database, attach a value to those rows, then order those rows based on a value. The problem is that in trying to do this via the while loop I get an error:
"Parse error: syntax error, unexpected '=>' (T_DOUBLE_ARROW) in
C:\xampp\htdocs\productivitysuite\index.php on line 98"
My goal is to retrieve rows from a database and organize those rows based on a value I calculate in PHP php ($priority), then display certain values of those rows based on their priority. The problem is that I get this darn error and I don't know why, nor do I know where to look for help to resolve it! Hopefully SO can help diagnose this.
code:
<?php
$mysqli = mysqli_connect('127.0.0.1','root','', 'taskdb'); //open connection
//retrieve variables
$sql = "SELECT * FROM tasklist WHERE completion_flag = FALSE";
$sqldata = mysqli_query($mysqli,$sql) or die('error retrieving data');
//Display results
echo "<table>";
echo "<tr><th>Task</th><th>Type</th><th>Due Date</th>";
$counter = 0; //may need to make global, not sure
$results = array();
while($row = mysqli_fetch_array($sqldata, MYSQLI_ASSOC)){
//store each row as variables
if ($row['externalFlag'] == 1) {
$E = 1;
} else{
$E = 0.5;
}
//days until completion
$nowDate = date("m/d/Y");
$D = 1 / (date_diff($row['dueDate']- $nowDate));
//Activity category multiplier
if($row['taskType'] == "Daily"){
$C = 0.5;
} elseif($row['taskType'] == "Maintenance"){
$C = 0.2;
} elseif ($row['taskType'] == "School_Study") {
$C = 0.75;
} elseif ($row['taskType'] == "Personal_Project") {
$C = 0.80;
} elseif ($row['taskType'] == "Work_Project") {
$C = 0.65;
}
$U = ($C - (1 / $D))* $E; //urgency rating; SET PER ROW!
$I = $row['importance']; //Importance rating
$priority = $U + $I;
$results[] = ($row => $priority);
//The array
$priorityOutput = $priorityRow.$counter;
++$counter;
echo "<tr><td>";
echo $row['taskName'];
echo "</td><td>";
echo $row['taskType'];
echo "</td><td>";
echo $row['dueDate'];
echo "</td></tr>";
//Make the below its own loop where I output in order of decreasing UI value
}
//now we have an array of key => value pairs with rows tied to a priority.
//We need to organize the rows by the priority
arsort($results);
echo "</table>"
$mysqli->close(); //close connection
?>

Answer 1

This is a syntax error with your subarray declaration.
Change
$results[] = ($row => $priority);
To
$results[] = array($row => $priority);
Correction: $row is an array, that cannot be used as a key.
I think you might mean:
$results[]=array($row['taskName']=>$priority);
Or maybe:
$results[]=array($priority=>$row);
Depending on your preferred structure.
As an aside, I would replace your taskType conditional block with a lookup array as a matter of clean / more compact code which I believe is easier to maintain and read.