PHP Sorting results of a Loop and displaying onscreen - php

I was wondering if someone could point me in the right direction with a coding issue Im having.
I am running a while loop in PHP comparing a post code to another and each run of the loop generates distance data. What Id like to do is then sort this data and display it.
Usually I'd throw everything into a MySQL database then sort that way but I think thats over kill.
Here's an example of the loop :
while($row = mysql_fetch_array($result))
{
$info = get_driving_information($_POST['customerpostcode'], $row[instructor_postcode]);
echo $row['instructor_name'] . " - " . $info['distance'];
}
I know this is probably PHP 101 but Ive never had to do anything like this before and am not sure how.
Thanks in advance for reading,
Rik

I think this is what you mean:
$rows = array();
while($row = mysql_fetch_array($result))
{
$info = get_driving_information($_POST['customerpostcode'], $row[instructor_postcode]);
$row['distance'] = $info['distance']; // store it in the array
$rows[] = $row;
}
Then use usort to sort the $rows array by the distance key.

What I'd recommend here is storing each distance result in an array and then apply a sort to the array. For example:
$distances = array();
while($row = mysql_fetch_array($result))
{
$info = get_driving_information($_POST['customerpostcode'], $row[instructor_postcode]);
$distances[$info['distance']] = $row['instructor_name'] . " - " . $info['distance'];
}
if(ksort($distances)) {
foreach($distances as $key=>$value) {
echo $value;
}
}
Note that my solution will not work for you if an exact distance appears more than once in the array; If that seems likely then you might need a different array-based solution.
For more information on array sorting, see Sorting Arrays in the PHP manual.

$data = array();
while($row = mysql_fetch_assoc($result)) {
$info = get_driving_information($_POST['customerpostcode'], $row['instructor_postcode']);
$data[$row['instructor_name']] = $info['distance'];
}
asort($data);
foreach ($data as $instructor => $distance) echo "$instructor - $distance<br />\n";
This will sort by instructor name. If you need to sort by distance, just reverse the way data is stored in the temporary array, I.E. $data[$row['distance']] = $info['instructor_name'];.
This will not work if the value you use as the temporary array key appears more than once, for that you would have to use array_multisort().
$data = $instructors = $distances = array();
for ($i = 0; $row = mysql_fetch_assoc($result); $i++) {
$info = get_driving_information($_POST['customerpostcode'], $row['instructor_postcode']);
$instructors[$i] = $row['instructor_name'];
$distances[$i] = $row['distance'];
$data[$i] = array('instructor'=>$row['instructor_name'],'distance'=>$info['distance']);
}
array_multisort($instructors,SORT_DESC,$distances,SORT_ASC,$data);
foreach ($data as $entry) echo "{$entry['instructor']} - {$entry['distance']}<br />\n";

This will work even if you have same instructor_name or distances several time in the array. Additionally buy modifying cmp() function you can sort whole thing by any other criteria.
$drivers = array();//initialising an array
while($row = mysql_fetch_array($result))
{
$info = get_driving_information($_POST['customerpostcode'], $row[instructor_postcode]);
$drivers[]=row;//adding new item to array
}
$drivers = usort($drivers,'cmp'); // sorting array using custom comparison function "cmp()"
foreach ($drivers as $driver) //printing results
echo $driver['instructor_name'] . " - " . $driver['distance'];
//custom comparison function
function cmp($a, $b) //returns +1 if $a > $b, -1 if $a < $b, else returns 0
{
if ($a['distance']>$b['distance'])
return 1;
if ($a['distance']<$b['distance'])
return -1;
return 0;
//quicker solution is to "return $a['distance']-$b['distance'];"
}

Related

Returning values from an array

Is there any reason why this code would avoid the first value in an array?
$rappels = array();
$i = 0;
while($row = $result->fetch_assoc()) {
foreach($row as $key=>$val) {
$rappels[$i][$key] = $val;
}
$i++;
}
return $rappels;
When I return the rappels, it always seems to avoid returning the very first item, which should be [0] in the array.
You have a number of redundancies in your code. You don't need $i nor do you need the foreach loop.
$rappels = array();
while($row = $result->fetch_assoc()) {
$rappels[] = $row;
}
return $rappels;
Your code as you posted it shouldn't remove any rows. You may need to look at the code you haven't posted to see if there's something there that's skipping the first row.

How to index the result of a mySql query as an array of array?

If I need to select and use information of every element of a table in a database the procedure would be this:
$query = "...mySql query...";
$query_result = mysql_query($query) or die (mysql_error());
Then if I wished to access the fields of the result I would use the function mysql_fetch_array() and access them like this:
$query_result_array = mysql_fetch_array($query_result);
echo $query_result_array['field_1'];
....
echo $query_result_array['field_i'];
....
But since more elements could be returned by the query I would like to access every single of them with an array indexed from 0 to mysql_num_rows($query_result).
As an example:
echo $query_result_array['field_i'][0];
....
echo $query_result_array['field_i'][mysql_num_rows($query_result)];
should print for every selected element of the table the value of field i.
Is there a function that will do the job for me?
If not, any suggestions on how to do it?
Thanks in advance for help.
This may be an alternative
$res = mysql_query("..SQL...");
$arr = array();
while ($row = mysql_fetch_assoc($res)) {
$arr[] = $row;
}
var_dump($arr);
Or
$res = mysql_query("..SQL...");
for
(
$arr = array();
$row = mysql_fetch_assoc($res);
$arr[] = $row
);
var_dump($arr);
I don't think there is such a method; you have to do it yourself.
try with something like:
$res = mysql_query("..mySql query...");
$arr = array();
while ($row = mysql_fetch_assoc($res)) {
$query_result_array[] = $row;
}
then you access your data like:
echo $query_result_array[0]['field_i'];
based on 2 previous answers, those authors assuming that usual SO author is familiar with such a thing as creating a function
function sqlArr($sql) { return an array consists of
$ret = array();
$res = mysql_query($sql) or trigger_error(mysql_error()." in ".$sql);
if ($res) {
while ($row = mysql_fetch_assoc($res)) {
$ret[] = $row;
}
}
return $ret;
}
$array = sqlArr("SELECT * FROM table");
foreach ($array as $row) {
echo $row['name'],$row['sex'];
}
this resulting array have different structure from what you asked, but it is way more convenient too.
if you still need yours unusual one, you have to tell how you gonna use it

Create and array index and value from the two array elements in a while loop

while($info5 = mysql_fetch_array($result)){
$namelist[] = $info5["name"];
$idlist[] = $info5["id"]
}
I want an array which has the entries of the array idlist as it's index and entries of the array namelist as it's values.
Is there a short way to do this?
Like this, if I understand your request. Use $info['id'] as the array key to the accumulating array $namelist (or whatever you decide to call it)
while($info5 = mysql_fetch_array($result)){
$namelist[$info['id']] = $info5["name"];
}
i'm not sure i understand your question but probably something like this should be fine.
while($info5 = mysql_fetch_array($result)){
$values[$info5['id']] = $info5;
}
$result = array();
while($info5 = mysql_fetch_array($result))
{
$id = $info5['id'];
$name = $info5['name'];
$result[$id] = $name;
}
This should give the output array $result you want, if I understood correctly.
You can use array_combine as long as the arrays have the same number of values:
$result = false;
if (count($idlist) == count($namelist))
$result = array_combine($idlist, $namelist);
Check out the docs: http://www.php.net/manual/en/function.array-combine.php
But, I also wonder why you don't just do it in the while loop:
$values = array();
$namelist = array();
$idlist = array();
while($info5 = mysql_fetch_array($result)){
$namelist[] = $info5["name"];
$idlist[] = $info5["id"]
// this is the combined array you want?
$values[$info5["id"]] = $info5["name"];
}

format mysql data in array

I am pulling data from my database and trying to encode into JSON data using json_encode. But to make it easier to read in my android app. I was hopping to format it differently then I am currently doing. Please see bottom encode string example. Any help would be great. Thanks in Advance.
$result = $db->query($query);
while($info = mysql_fetch_array($result))
{
$content[] = $info;
}
$count = count($content);
$result=array();
for($i=0;$i<$count;$i++)
{
$result[id][] = $content[$i]['imageID'];
$result[name][] = $content[$i]['Name'];
$result[thumb][] = $content[$i]['Thumb'];
$result[path][] = $content[$i]['Path'];
}
echo json_encode($result);
{"id":["1","2","3"],"name":["Dragon","fly","bug"],"thumb":["thm_polaroid.jpg","thm_default.jpg","thm_enhanced-buzz-9667-1270841394-4.jpg"],"path":["polaroid.jpg","default.jpg","enhanced-buzz-9667-1270841394-4.jpg"]}
But I am trying to format my array like so when it is encoded by json_encode.
[{"id":"1","name":"Dragon","thumb":"thm_polaroid.jpg","path":"polaroid.jpg"},{"id":"2","name":"Fly","thumb":"thm_default.jpg","path":"default.jpg"},{"id":"3","name":"Bug","thumb":"thm_enhanced-buzz-9667-1270841394-4.jpg","path":"enhanced-buzz-9667-1270841394-4.jpg"}]
Well, there is a problem. This is not valid JSON:
{"image":["1","Dragon","thm_polaroid.jpg","polaroid.jpg"],
"image":["2","fly","thm_default.jpg","default.jpg"]}
A JSON object can only have one value per unique key. This means that your latter image key would clobber the value of the former.
If you are content with this, however:
[["1","Dragon","thm_polaroid.jpg","polaroid.jpg"],
["2","fly","thm_default.jpg","default.jpg"]]
Then you can simply use mysql_fetch_row:
$result = $db->query($query);
while($info = mysql_fetch_row($result))
{
$content[] = $info;
}
echo json_encode($content);
Side Note:
Generally, in PHP, it is best to use foreach( $arr as $val ) (or $arr as $key => $val). for loops should be limited to when they are strictly necessary.
You need to add the iterator $i to the setting array
for($i=0;$i<$count;$i++)
{
$result[$i][id] = $content[$i]['imageID'];
$result[$i][name] = $content[$i]['Name'];
$result[$i][thumb] = $content[$i]['Thumb'];
$result[$i][path] = $content[$i]['Path'];
}
<?
$result = $db->query($query);
while($info = mysql_fetch_array($result))
$content[] = $info;
$result=array();
$count = count($content);
for ($x=0;$x<$count;++$x)
{
$result[$x][] = $content[$x]['imageID'];
$result[$x][] = $content[$x]['Name'];
$result[$x][] = $content[$x]['Thumb'];
$result[$x][] = $content[$x]['Path'];
}
echo json_encode($result);
?>

php string name as variable in array

how take string from array define as new array,
how to code in php
$column = array("id","name","value");
let say found 3 row from mysql
want result to be like this
$id[0] = "1";
$id[1] = "6";
$id[2] = "10";
$name[0] = "a";
$name[1] = "b";
$name[2] = "c";
$value[0] = "bat";
$value[1] = "rat";
$value[2] = "cat";
I want to take string from $column array define as new array.
how to code it?
or if my question is stupid , my please to have suggestion.
thank you.
Answer I made on your previous question:
$result = mysql_query($sql);
$num = mysql_num_rows($result);
$i = 0;
if ($num > 0) {
while ($row = mysql_fetch_assoc($result)) {
foreach($row as $column_name => $column_value) {
$temp_array[$column_name][$i] = $column_value;
}
$i++;
}
foreach ($temp_array as $name => $answer) {
$$name = $answer;
}
}
I can't see why you'd want to model your data like this, you're asking for a world of hurt in terms of debugging. There are "variable variables" you could use to define this, or build global variables dynamically using $GLOBALS:
$somevar = "hello"
$$somevar[0] = "first index"; // creates $hello[0]
$GLOBALS[$somevar][0] = "first index"; // creates $hello[0] in global scope
try
$array = array();
foreach ($results as $r){
foreach ($column as $col ){
$array[$col][] = $r[$col];
}
}
extract ($array);
or you can simply do this
$id = array();
$name = array();
$value = array();
foreach ( $results as $r ){
$id[] = $r['id']; // or $r[0];
$name[] = $r['name'];
$value[] = $r['value'];
}
Hope this is what you asked
This is pretty dangerous, as it may overwrite variables you consider safe in your code. What you're looking for is extract:
$result = array();
while ($row = mysql_fetch_array($result))
foreach ($column as $i => $c)
$result[$c][] = $row[$i];
extract($result);
So, if $result was array( 'a' => array(1,2), 'b' => array(3,4)), the last line defines variables $a = array(1,2) and $b = array(3,4).
You cannot use variable variables right on for this, and you shouldn't anyway. But this is how you could do it:
foreach (mysql_fetch_something() as $row) {
foreach ($row as $key=>$value) {
$results[$key][] = $value;
}
}
extract($results);
Ideally you would skip the extract, and use $results['id'][1] etc. But if you only extract() the nested array in subfunctions, then the local variable scope pollution is acceptable.
There is no need for arrays or using $_GLOBALS, i believe the best way to create variables named based on another variable value is using curly brackets:
$variable_name="value";
${$variable_name}="3";
echo $value;
//Outputs 3
If you are more specific on what is the array you receive i can give a more complete solution, although i must warn you that i have never had to use such method and it's probably a sign of a bad idea.
If you want to learn more about this, here is a useful link:
http://www.reddit.com/r/programming/comments/dst56/today_i_learned_about_php_variable_variables/

Categories