I am generating a simple text in an image like this...
// Create a blank image and add some text
$im = imagecreatetruecolor(120, 20);
$text_color = imagecolorallocate($im, 233, 14, 91);
imagestring($im, 1, 5, 5, 'A Simple Text String', $text_color);
// Set the content type header - in this case image/jpeg
header('Content-Type: image/jpeg');
// Output the image
imagejpeg($im);
// Free up memory
imagedestroy($im);
I need the output as a base64 string, I have tried base64_encode($im) but it is not working correctly for me.
Does anybody have an example I can see?
Try using the ob_get_clean function to get the image from the output buffer and then encode it to base64:
// Create a blank image and add some text
$im = imagecreatetruecolor(120, 20);
$text_color = imagecolorallocate($im, 233, 14, 91);
imagestring($im, 1, 5, 5, 'A Simple Text String', $text_color);
ob_start();
// Output the image
imagejpeg($im);
$img = ob_get_clean();
ob_end_clean();
// Free up memory
imagedestroy($im);
echo base64_encode($img);
Related
I want to create/generate an image with PHP, adding text into it, but without saving it into the FTP, I'd like to load it on the site by changing the content type to image/png, the same way I did it with ASP.NET:
Response.ContentType = "image/png";
rImage.Save(Response.OutputStream, ImageFormat.Png);
I found a function called file_put_contents, but I'm not so sure this is what I'm looking for. If you know how to do something like this, please tell me.
I'm trying this code, but it fails to load the image, and shows the browser's default error image.
<?php
header("Content-Type: image/png");
$im = #imagecreate(110, 20)
or die("Cannot Initialize new GD image stream");
$background_color = imagecolorallocate($im, 0, 0, 0);
$text_color = imagecolorallocate($im, 233, 14, 91);
imagestring($im, 1, 5, 5, "A Simple Text String", $text_color);
imagepng($im);
imagedestroy($im);
?>
Below example will regenerate an image with text over it:
<?php
header("Content-type: image/png"); // Set the header so that browser can output the image
$string = 'Print this text on Image'; // Text to be added on the image
$im = imagecreatefrompng("images/button1.png"); // Take base image
$orange = imagecolorallocate($im, 220, 210, 60); // Allocate a color for an image
imagestring($im, 3, 0, 0, $string, $orange); // Write the string at the top left
imagepng($im); // Create new image
imagedestroy($im); // destroy object
?>
Reference: http://php.net/manual/en/image.examples-png.php
okay, so im using this piece of code:
<?php
//Set the Content Type
header('Content-type: image/jpeg');
// Create Image From Existing File
$jpg_image = imagecreatefromjpeg('sunset.jpg');
// Allocate A Color For The Text
$white = imagecolorallocate($jpg_image, 255, 255, 255);
// Set Path to Font File
$font_path = 'font.TTF';
// Set Text to Be Printed On Image
$text = "This is a sunset!";
// Print Text On Image
imagettftext($jpg_image, 25, 0, 75, 300, $white, $font_path, $text);
// Send Image to Browser
imagejpeg($jpg_image);
// Clear Memory
imagedestroy($jpg_image);
?>
and i have GD installed.
but the results show me this:
any idea why?
Please take look the demo site at
http://jsfiddle.net/Alidad/fexGj/
That demo is called "Image title", my next step is to convert both text and images as one group to images so that way i can click right mouse to copy and paste over.
However, there is PHP code that allow me to convert into the image from text but I can't hardly figure out how can I convert from "image title" (demo) into the HTML!
Here is sample PHP code but I can't figure out how to combine it!
<?php
// Create a 100*30 image
$im = imagecreate(100, 30);
// White background and blue text
$bg = imagecolorallocate($im, 255, 255, 255);
$textcolor = imagecolorallocate($im, 0, 0, 255);
// Write the string at the top left
imagestring($im, 5, 0, 0, 'Hello world!', $textcolor);
// Output the image
header('Content-type: image/png');
imagepng($im);
imagedestroy($im);
?>
Have any help me please how to convert this to images from jQuery code!
AM
Easiest way would probably be to just do:
// index.html
<img src="render_image.php?text=Hello World" />
and then:
// render_image.php
<?php
// Create a 100*30 image
$im = imagecreate(100, 30);
// White background and blue text
$bg = imagecolorallocate($im, 255, 255, 255);
$textcolor = imagecolorallocate($im, 0, 0, 255);
// Write the string at the top left
imagestring($im, 5, 0, 0, $_GET['text'], $textcolor);
// Output the image
header('Content-type: image/png');
imagepng($im);
imagedestroy($im);
?>
Using this with slight modifications to your javascript code should work.
More info on using the $_GET variable: http://php.net/manual/en/reserved.variables.get.php
$image = imagecreatetruecolor(538,616);
$black = imagecolorallocate($image,0,0,0);
imagefill($image,0,0,$black);
I have already draw a black image i want draw a file suppose 3.png on it ..
How to do that ?
You have to load an image you want to draw and then use imagecopy() to draw it:
// the part you already have; creates 538x616 px black image
$image = imagecreatetruecolor(538,616);
$black = imagecolorallocate($image,0,0,0);
imagefill($image,0,0,$black);
// load image from file and draw it onto black image;
// for loading PNG, use imagecreatefrompng()
$overlayImage = imagecreatefromjpeg('macro_photo_1.jpg');
imagecopy($image, $overlayImage, 10, 10, 0, 0, imagesx($overlayImage), imagesy($overlayImage));
// send image to the browser
header("Content-Type: image/png");
imagepng($image);
exit;
I would also advise to go through the list of GD and Image functions to see what (and how) can be done with images in PHP.
imagepng($image);
And if you haven't already you need:
header('Content-Type: image/png');
Before you call imagepng to let the browser know it's looking at an image not an HTML page.
Saroj, http://www.php.net/manual/en/function.imagecreate.php and from same page, here is the example snippet
<?php
header("Content-Type: image/png");
$im = #imagecreate(110, 20)
or die("Cannot Initialize new GD image stream");
$background_color = imagecolorallocate($im, 0, 0, 0);
$text_color = imagecolorallocate($im, 233, 14, 91);
imagestring($im, 1, 5, 5, "A Simple Text String", $text_color);
imagepng($im);
imagedestroy($im);
?>
HTH!
I am using PHP imagejpeg to create a simple image like this..
// Create a blank image and add some text
$im = imagecreatetruecolor(120, 20);
$text_color = imagecolorallocate($im, 233, 14, 91);
imagestring($im, 1, 5, 5, 'A Simple Text String', $text_color);
// Set the content type header - in this case image/jpeg
header('Content-Type: image/jpeg');
// Output the image
imagejpeg($im);
// Free up memory
imagedestroy($im);
This is working, but i would like it to automatically trigger a download inside the browser instead of display the image.
How can I do this, do I need to set a header?
All you have to do is set an extra header:
// Create a blank image and add some text
$im = imagecreatetruecolor(120, 20);
$text_color = imagecolorallocate($im, 233, 14, 91);
imagestring($im, 1, 5, 5, 'A Simple Text String', $text_color);
// Set the content type header - in this case image/jpeg
header('Content-Type: image/jpeg');
header('Content-Disposition: attachment; filename=file-name.jpg'); // This will tell the browser to download it
// Output the image
imagejpeg($im);
// Free up memory
imagedestroy($im);
Here is the documentation
I believe you need at least 3 headers:
header("Content-Type: image/jpeg"); // Content type
header("Content-Disposition: attachment; filename=file-name.jpg"); // Content deposition
header("Content-Length: $fileSize"); // YOUR FILE SIZE
otherwise, the download will not work in firefox.