$image = imagecreatetruecolor(538,616);
$black = imagecolorallocate($image,0,0,0);
imagefill($image,0,0,$black);
I have already draw a black image i want draw a file suppose 3.png on it ..
How to do that ?
You have to load an image you want to draw and then use imagecopy() to draw it:
// the part you already have; creates 538x616 px black image
$image = imagecreatetruecolor(538,616);
$black = imagecolorallocate($image,0,0,0);
imagefill($image,0,0,$black);
// load image from file and draw it onto black image;
// for loading PNG, use imagecreatefrompng()
$overlayImage = imagecreatefromjpeg('macro_photo_1.jpg');
imagecopy($image, $overlayImage, 10, 10, 0, 0, imagesx($overlayImage), imagesy($overlayImage));
// send image to the browser
header("Content-Type: image/png");
imagepng($image);
exit;
I would also advise to go through the list of GD and Image functions to see what (and how) can be done with images in PHP.
imagepng($image);
And if you haven't already you need:
header('Content-Type: image/png');
Before you call imagepng to let the browser know it's looking at an image not an HTML page.
Saroj, http://www.php.net/manual/en/function.imagecreate.php and from same page, here is the example snippet
<?php
header("Content-Type: image/png");
$im = #imagecreate(110, 20)
or die("Cannot Initialize new GD image stream");
$background_color = imagecolorallocate($im, 0, 0, 0);
$text_color = imagecolorallocate($im, 233, 14, 91);
imagestring($im, 1, 5, 5, "A Simple Text String", $text_color);
imagepng($im);
imagedestroy($im);
?>
HTH!
Related
I want to create/generate an image with PHP, adding text into it, but without saving it into the FTP, I'd like to load it on the site by changing the content type to image/png, the same way I did it with ASP.NET:
Response.ContentType = "image/png";
rImage.Save(Response.OutputStream, ImageFormat.Png);
I found a function called file_put_contents, but I'm not so sure this is what I'm looking for. If you know how to do something like this, please tell me.
I'm trying this code, but it fails to load the image, and shows the browser's default error image.
<?php
header("Content-Type: image/png");
$im = #imagecreate(110, 20)
or die("Cannot Initialize new GD image stream");
$background_color = imagecolorallocate($im, 0, 0, 0);
$text_color = imagecolorallocate($im, 233, 14, 91);
imagestring($im, 1, 5, 5, "A Simple Text String", $text_color);
imagepng($im);
imagedestroy($im);
?>
Below example will regenerate an image with text over it:
<?php
header("Content-type: image/png"); // Set the header so that browser can output the image
$string = 'Print this text on Image'; // Text to be added on the image
$im = imagecreatefrompng("images/button1.png"); // Take base image
$orange = imagecolorallocate($im, 220, 210, 60); // Allocate a color for an image
imagestring($im, 3, 0, 0, $string, $orange); // Write the string at the top left
imagepng($im); // Create new image
imagedestroy($im); // destroy object
?>
Reference: http://php.net/manual/en/image.examples-png.php
I am executing my following code for creating a transparent image but everytime it shows me black background.
kindly tell me my my fault in the code.
<?php
//set the content type
header('Content-type: image/jpeg');
//create the image
$im = imagecreatetruecolor(250, 200);
$black = imagecolorallocate($im, 255, 255, 255);
$blue = imagecolorallocate($im, 0, 0, 255);
// Make the background transparent
imagecolortransparent($im, $black);
//text to draw
$text=$_POST['text'];
//font path
$font = '/usr/share/fonts/truetype/droid/DroidSans.ttf';
// Add the text
imagettftext($im, 15, 0, 50, 50, -$blue, $font, $text);
//view the image
imagejpeg($im);
imagedestroy($im);
?>
You cannot make jpeg images transparent. Use png instead
Change below 2 lines:
header('Content-type: image/png');
imagepng($im);
Update
Reference Link: create transparent png image
Please take look the demo site at
http://jsfiddle.net/Alidad/fexGj/
That demo is called "Image title", my next step is to convert both text and images as one group to images so that way i can click right mouse to copy and paste over.
However, there is PHP code that allow me to convert into the image from text but I can't hardly figure out how can I convert from "image title" (demo) into the HTML!
Here is sample PHP code but I can't figure out how to combine it!
<?php
// Create a 100*30 image
$im = imagecreate(100, 30);
// White background and blue text
$bg = imagecolorallocate($im, 255, 255, 255);
$textcolor = imagecolorallocate($im, 0, 0, 255);
// Write the string at the top left
imagestring($im, 5, 0, 0, 'Hello world!', $textcolor);
// Output the image
header('Content-type: image/png');
imagepng($im);
imagedestroy($im);
?>
Have any help me please how to convert this to images from jQuery code!
AM
Easiest way would probably be to just do:
// index.html
<img src="render_image.php?text=Hello World" />
and then:
// render_image.php
<?php
// Create a 100*30 image
$im = imagecreate(100, 30);
// White background and blue text
$bg = imagecolorallocate($im, 255, 255, 255);
$textcolor = imagecolorallocate($im, 0, 0, 255);
// Write the string at the top left
imagestring($im, 5, 0, 0, $_GET['text'], $textcolor);
// Output the image
header('Content-type: image/png');
imagepng($im);
imagedestroy($im);
?>
Using this with slight modifications to your javascript code should work.
More info on using the $_GET variable: http://php.net/manual/en/reserved.variables.get.php
Folks,I've some 288 points with their X,Y co-ordinates and a value assigned to them. I need to show this figuratively. I tried gd and imagettftext but simple code to draw a blank image isn't working even when I've installed and configured gd.
header('Content-Type: image/png');
$image = imagecreatetruecolor(400, 300);
// Allocate a color for the polygon
$col_poly = imagecolorallocate($image, 255, 255, 255);
// Draw the polygon
imagepolygon($image, array(
0, 0,
100, 200,
300, 200
),
3,
$col_poly);
// Output the picture to the browser
header('Content-type: image/png');
imagepng($image);
imagedestroy($image);
The output in the browser is
Try to set encoding of php file with your code to UTF-8 without BOM (e.g. in Notepad++).
Your code works right and image shows. Most probably your GD library is not working as expected. Try this
$image = imagecreatetruecolor(400, 300) or die('Cannot Initialize new GD image stream');
I'm using Creating image function to create an image with exact text message using the following code
<?PHP
header ("Content-type: image/gif");
$image=imagecreatefromgif("myimage.gif"); // will be background img
$black = imagecolorallocate($image, 0,0,0);
$message = "Hello Egypt";
imagestring($image, 4, 25, 10, $message, $black);
imagegif($image);
imagedestroy($image);
?>
The output should be like this
Now my question is there any way i can write image over it not only text
so that if i've flag image at same path (flag.gif ) and i would like to write it just after my $message to be like this
so is this possible and how could be ! ~ thanks a lot
Update
based on #MarcB idea of using imagecopy function
<?PHP
header ("Content-type: image/gif");
$image=imagecreatefromgif("myimage.gif"); // will be background img
$src = imagecreatefromjpeg('flag.jpg');// new image will add
imagecopy($image, $src, 120, 10, 0, 0, 32, 20);
$black = imagecolorallocate($image, 0,0,0);
$message = "Hello Egypt";
imagestring($image, 4, 25, 10, $message, $black);
imagegif($image);
imagedestroy($image);
?>
the output is not true color WHY :(
ANY help about this new problem ~ thanks
With the help of Surreal Dreams and Marc B
This one works fine
<?PHP
header ("Content-type: image/gif");
$image=imagecreatefromjpeg("myimage.jpg"); // will be background img
$src = imagecreatefromjpeg('flag.jpg');// new image will add
imagecopy($image, $src, 120, 10, 0, 0, 32, 20);
$black = imagecolorallocate($image, 0,0,0);
$message = "Hello Egypt";
imagestring($image, 4, 25, 10, $message, $black);
imagegif($image);
imagedestroy($image);
?>
Output
I've should have learned the following functions
imagecopy
imagecreatefromjpeg
imagecreatefromgif
imagecopy() should properly deal with differences between images' palettes; however, the GIF format does not support more than 256 colors, and neither does GD when it works with palette-based images. If 256 palette entries already exist when GD tries to use a new color, GD will pick the closest match, which can produce the results you see.
To avoid this problem, you should use imagecreatetruecolor() to create a 24-bit true-color image in memory. You can then use imagecopy() to insert each GIF image (including the background) and imagepng() to generate PNG output, which is better for line art than JPEG, offers better compression than GIF, and can support more than 256 colors.