echo statement for false php function - php

Question

I have created a function as follows:
//function for first name field
function name ($fname) {
//validate to see if field is empty
if (empty($fname)) {
return (false);
}
$welcome_string = '<p> Welcome ' . $fname . '. We\'re glad you\'re here! Take a look around!</p>';
return $welcome_string;
}//end fname function
When the function passes the check I echo the function and get the welcome_string. However, I need to display an error outside of the function when it returns false. I cannot figure out how to do this. Below is the code where I call the function:
echo name($fname);

Answer 1

What you want to do is add a check for that:
$result = name($fname);
if ($result) {
echo $result;
} else {
echo "There was an error.";
}
Using a ternary if, you can do this in shorthand:
$result = name($fname);
echo $result ? $result : "There was an error.";
Or even shorter without introducing a new variable:
echo name($fname) ?: "There was an error.";

Answer 2

You could simply do:
$result = name($fname);
echo $result?$result:"error message";

Answer 3

<?php
function greeting($name)
{
if (empty($name))
return false;
$welcome_string = 'Welcome ' . $name . ". We're glad you're here! Take a look around!\n";
return $welcome_string;
}
foreach(['Rita', 'Sue', '', null, 0, '0'] as $name)
echo ($message = greeting($name))
? $message
: "Who are you?\n";
Output:
Welcome Rita. We're glad you're here! Take a look around!
Welcome Sue. We're glad you're here! Take a look around!
Who are you?
Who are you?
Who are you?
Who are you?