php loop, func_get_arg(0) - php

Question

can somone explain me how this code works
<?php
function append($initial)
{
$result=func_get_arg(0);
foreach(func_get_arg()as $key=>value){
if($key>=1)
{
$result .=' '.$value;
}
}
return $result;
echo append('Alex,'James','Garrett');
?>
why do we have a 0 at the func_get_arg(0), and this is a loop there are 0,1,2 shouldn't it only post Alex, James?
and what is the (as) does the func_get_arg() as $key => value. give the array the names to the value ?
this is basic but a bit messy!

Answer 1

That's how it works:
<?php
function append($initial)
{
// Get the first argument - func_get_arg gets any argument of the function
$result=func_get_arg(0);
// Get the remaining arguments and concat them in a string
foreach(func_get_args() as $key=>value) {
// Ignore the first (0) argument, that is already in the string
if($key>=1)
{
$result .=' '.$value;
}
}
// Return it
return $result;
}
// Call the function
echo append('Alex,'James','Garrett');
?>
This function will do the same that:
echo implode(' ', array('Alex', 'James', 'Garrett'));

Answer 2

before you used the foreach{} loop. You have returned 'Alex' which is at position 0.
$result=func_get_arg(0);
foreach(){
}
return $result; //It returns Alex
//foreach() loop
foreach(func_get_arg()as $key=>value){
/*Its looping and only printing after
the key gets to 1 and then the loop goes to 2.Eg: $result[$key]=> $value; */
if($key>=1)
{
$result .=' '.$value;
}
}