PHP and SQL uploading error [duplicate] - php

Question

This question already has answers here:
When to use single quotes, double quotes, and backticks in MySQL
(13 answers)
Closed 4 years ago.
I have a problem, I can't upload anything to database. In my database in the jelenlet table there is a jelen which is integer and a gyerekneve which is text.
Here is my php code:
<?php
$servername = "...";
$username = "...";
$password = "...";
$dbname = "...";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "INSERT INTO 'jelenlet' ('gyerekneve', 'jelen') VALUES ('barmi', 0)";
if ($conn->query($sql) === TRUE) {
echo "Hozzaadtad ezt a nevet: ";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
And don't know what is the problem with the code. The page says:
Error: INSERT INTO 'jelenlet' ('gyerekneve', 'jelen') VALUES ('barmi',
0) You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near ''jelenlet' ('gyerekneve', 'jelen') VALUES ('barmi', 0)' at line
1

Answer 1

$sql = "INSERT INTO jelenlet (gyerekneve, jelen) VALUES ('barmi', 0)";
This will work. BUT make sure to use prepared statements when you will try to pass variables to this one and not static values. The problem was that you were using single-quotes when you didn't have to. If you want to escape fields in a query you can use this : `
This query would also work :
$sql = "INSERT INTO `jelenlet` (`gyerekneve`, `jelen`) VALUES ('barmi', 0)";