PHP Parse error: syntax error, unexpected '$_GET' (T_VARIABLE) [duplicate] - php

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PHP parse/syntax errors; and how to solve them
(20 answers)
Closed 5 years ago.
First off, yes I have done research and have seen tons of posts like this one. I see the post this is supposed to be a duplicate of but it was not helpful. I am very new with this and do not know how to apply their results to mine.
I'm getting this result when running:
Parse error: syntax error, unexpected '$_GET' (T_VARIABLE) in /storage/ssd4/269/2113269/public_html/updateuser.php on line 12
Here is my script:
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "database";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "UPDATE Users ". "SET Status = '"$_GET["status"]"' ".
"WHERE Username = '"$_GET["username"]"'";
if ($conn->query($sql) === TRUE) {
echo "Record updated successfully";
} else {
echo "Error updating record: " . $conn->error;
}
$conn->close();
?>
Thank you a bunch for taking a look. I might be missing a semi-colon somewhere but I've looked over the code for a while. Please let me know!

Answer 1

You have to concatenate string using .
$sql = "UPDATE Users ". "SET Status = '".$_GET["status"]."' ".
"WHERE Username = '".$_GET["username"]."'";

Answer 2

You need to concatenate string and variable using dot(.) properly like this
$sql = "UPDATE Users
SET Status = '".$_GET["status"]."'
WHERE Username = '".$_GET["username"]."'";

Answer 3

This is because you end and start the statement with " before and after the the GET statement declaration; but haven't put the concatenation . in between the " and GET.
"SELETCT tb FROM db WHERE field = '".GET ['something']."'";
It's also a good habit to wrap the two GET in a IF statement and run the full code if bot Get has some value. Reduce the unnecessar SQL and PHP execution.