Get Instagram media using php? - php

Question

I am trying to get images from an Instagram user (it's our own account). Below is the code I am using, but it does not seem to work. I do have the correct userID and accessToken being fed into the code.
function fetchData($url){
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_TIMEOUT, 20);
$result = curl_exec($ch);
curl_close($ch);
return $result;
}
$result = fetchData("https://api.instagram.com/v1/users/".$userID."/media/recent/?access_token=".$accessToken);
$theinfo = json_decode($result, true);
foreach ($theinfo->data as $post){
echo $post->images->standard_resolution->url;}
Any suggestion would be greatly appreciated.

Answer 1

I have another way to get user images if you know username
here is link of my github repo to get user images
here is link of repo
following php code is used to get user images
i am using curl & scraping images
not using instagram api
function scrape_insta_user_images($username) {
$insta_source = file_get_contents('https://www.instagram.com/'.$username.'/'); // instagram user url
$shards = explode('window._sharedData = ', $insta_source);
$insta_json = explode(';</script>', $shards[1]);
$insta_array = json_decode($insta_json[0], TRUE);
return $insta_array; // this return a lot things print it and see what else you need
}
$username = 'pakistan'; // user for which you want images
$results_array = scrape_insta_user_images($username);
//echo '<pre>';
//print_r($results_array);
//echo '<pre>';
$limit = 56; // provide the limit thats important because one page only give some images.
$image_array= array(); // array to store images.
for ($i=0; $i < $limit; $i++) {
//new code to get images from json
if(isset($results_array['entry_data']['ProfilePage'][0]['graphql']['user']['edge_owner_to_timeline_media']['edges'][$i])){
$latest_array = $results_array['entry_data']['ProfilePage'][0]['graphql']['user']['edge_owner_to_timeline_media']['edges'][$i]['node'];
$image_data = '<img src="'.$latest_array['thumbnail_src'].'">'; // thumbnail and same sizes
//$image_data = '<img src="'.$latest_array['display_src'].'">'; actual image and different sizes
array_push($image_array, $image_data);
}
}
foreach ($image_array as $image) {
echo $image;// this will echo the images wrap it in div or ul li what ever html structure
}
// for getting all images have to loop function for more pages
// for confirmation you are getting correct images view
//https://www.instagram.com/username

Answer 2

<?
function getPosts($username)
{
if (function_exists('curl_init')) {
$url = "https://www.instagram.com/" . $username . "/?__a=1";
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_TIMEOUT, 20);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
$response = curl_exec($ch);
curl_close($ch);
return json_decode($response);
} else {
return false;
}
}
$arResult["POSTS"] = getPosts("instagram");
?>
<? foreach ($arResult["POSTS"]->graphql->user->edge_owner_to_timeline_media->edges as $key => $post): ?>
<div class="col-md-2 col-sm-3 col-xs-4">
<a href="https://www.instagram.com/p/<?=$post->code?>" target="_blank">
<img src="<?=$post->node->thumbnail_resources[3]->src?>">
<div class="instagram-info">
<div class="instagram-icon instagram-icon--likes">
<span><? echo number_format($post->node->edge_liked_by->count, 0, '.', ' '); ?></span>
</div>
<div class="instagram-icon instagram-icon--comments">
<span><? echo number_format($post->node->edge_media_to_comment->count, 0, '.', ' '); ?> <span class="horizontal-line"></span></span>
</div>
</div>
</a>
</div><? endforeach; ?>