curl Authentication error on Images Only - php

I am trying to get information from a XML Rest API.
I can get everything but not the images.
I can display all info, but when it comes on images I get 401 error
Failed to load resource: the server responded with a status of 401 ().
My username and password are correct. The only way to get the images display is if I login to this API in a different window. Then all images are displayed.
Am I doing something wrong ? Here is my php code:
function CallAPI($url){
$curl = curl_init();
curl_setopt($curl, CURLOPT_HTTPAUTH, CURLAUTH_BASIC);
curl_setopt($curl, CURLOPT_USERPWD, "usr:psw");
curl_setopt($curl, CURLOPT_URL, $url);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
$result = curl_exec($curl);
curl_close($curl);
return $result;
}
$a = "query SQL";
$asd = $database->query($a);
while($row = sqlsrv_fetch_array($asd)){
echo $url = $row['url']; // I can get this data display
$row['hotel_name'];
$a = CallAPI($url);
$axml = new SimpleXMLElement($a);
$img_link = $axml->item->images;
foreach ($img_link->image as $value) {
echo "<img src='".$value->sizes->size[1]->attributes('http://www.w3.org/1999/xlink')."' class='img-responsive' />";
}

So your problem must be that this link need authentication as well. So try make the call for $value->sizes->size[1]->attributes('http://www.w3.org/1999/xlink') to pass user and pass.
So you code should look like this
while($row = sqlsrv_fetch_array($asd)){
$url = $row['url'];
$row['hotel_name']; // No use of this one, maybe you use it on your end
$a = CallAPI($url);
$axml = new SimpleXMLElement($a);
$img_link = $axml->item->images;
foreach ($img_link->image as $value) {
/*I am adding the link to a variable*/
$imgLinkFromValue = $value->sizes->size[1]->attributes('http://www.w3.org/1999/xlink');
$img = CallAPI($imgLinkFromValue );
/* Now if you still get a link just pass the variable */
echo "<img src='$img->**link or href or anything you get**' class='img-responsive' />";
}
UPDATE
If you getting text or symbols maybe you have to use base64_encode().
Try this :
$img = base64_encode(CallAPI($imgLinkFromValue ));
echo '<img src="data:image/jpeg;base64,' . $img . '" class="img-responsive" />'
You can always change the data inside src to png or gif, depends on what you need.
For more Info about base64_encode function you can use this link.
http://php.net/manual/en/function.base64-encode.php

Related

Roblox API ( Avatar Equipment )

I am currently working on Roblox API. I am stuck on one question. Reason :
I have this link https://avatar.roblox.com/v1/users/2/currently-wearing.
This shows what specified users have equipped on them. this link right here shows this:
{"assetIds":[382537569,607702162,607785314]}
My goal is to get the assetIds to string.
I tried this:
<?php
$id = 2;
$ch = file_get_contents("https://avatar.roblox.com/v1/users/$id/currently-wearing");
$ch = curl_init($ch);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$data = curl_exec($ch);
$data = json_decode($data);
$id = "$data->assetIds";
echo $id;
But it Shows Array. I need some help.
The cURL is not necessary as the file_get_contents() get you the data you appear to require
$id = 2;
$ch = file_get_contents("https://avatar.roblox.com/v1/users/2/currently-wearing");
$data = json_decode($ch);
foreach ($data->assetIds as $id){
echo $id . PHP_EOL;
}
RESULT
382537569
607702162
607785314

Get Facebook Profile URL From Facebook Profile id Using PHP

I have a list of Facebook links in xls sheet with Facebook id something like this
and when i go through these links means if i access Facebook with id www.facebook.com/7500
i get urls something like this https://www.facebook.com/davesachs/
so my question is i want to do this with PHP, i have a PHP page which read data from xls sheet
my code here:
require_once 'src/SimpleXLSX.php';
if ( $xlsx = SimpleXLSX::parse('fburl.xlsx') ) {
$rows= $xlsx->rows();
foreach($rows as $data){
echo $data[0].'<br>';
}
} else {
echo SimpleXLSX::parseError();
}
its returning all Facebook link with id same that i am passing like www.facebook.com/7500 but i want it return URL / link of profile as https://www.facebook.com/davesachs/ ,if it is possible please help me to do that.
You can do something like that, Taken reference from here
<?php
require_once 'src/SimpleXLSX.php';
if ( $xlsx = SimpleXLSX::parse('fburl.xlsx') ) {
$rows= $xlsx->rows();
foreach($rows as $data){
getRedirectedUrl($data[0]);
}
} else {
echo SimpleXLSX::parseError();
}
function getRedirectedUrl($link){
$url=$link;
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_HEADER, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true); // Must be set to true so that PHP follows any "Location:" header
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$a = curl_exec($ch); // $a will contain all headers
$url = curl_getinfo($ch, CURLINFO_EFFECTIVE_URL); // This is what you need, it will return you the last effective URL
// Uncomment to see all headers
/*
echo "<pre>";
print_r($a);echo"<br>";
echo "</pre>";
*/
echo $url; // Voila
}
?>

Mulitple Instagram feeds on one page

I have successfully put an Instagram feed for a specific user on my website, but having very little experience with PHP I cannot figure out how to simply repeat the process. I'm looking to showcase two different users, side by side in one div.
<?php
// http://jelled.com/instagram/lookup-user-id/
$userid = "userid";
// http://instagram.com/developer/
$clientid = "clientid";
// http://jelled.com/instagram/access-token/
$accessToken = "token";
// number of photos to return
$count = "4";
// Gets our data
function fetchData($url){
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_TIMEOUT, 20);
$result = curl_exec($ch);
curl_close($ch);
return $result;
}
// Pulls and parses data.
$result = fetchData("https://api.instagram.com/v1/users/{$userid}/media/recent/?access_token={$accessToken}&count={$count}");
$result = json_decode($result);
// cycles through the json tree and uses the low res url in the img tag
echo "<ul>";
foreach ($result->data as $photo) {
$img = $photo->images->{$display_size="thumbnail"};
echo "<li><a href='{$photo->link}'><img src='{$img->url}' /></a></li>";
}
echo "</ul>";
?>
If I just paste the code in again, the whole page stops working. I'm guessing this is something simple, but I don't know exactly what I'm looking for! Should this code be in a separate file that is linked into my website- rather than throwing some PHP inside an HTML Bootstrap site?
Thanks in advance.
EDIT
I was able to get this working by using the answer below. I wanted each account to have it's own div, and the only way I know how to do that is in the html file- which would mean I still need to link to two different files. I created one file with the correct code, and another with this:
<?php
// Set User ID here for different profile
//$userid = "idHere";
$userid = "296517730";
$result = fetchData("https://api.instagram.com/v1/users/{$userid}/media/recent/?client_id={$clientid}&count={$count}");
$result = json_decode($result);
// cycles through the json tree and uses the low res url in the img tag
echo "<ul>";
foreach ($result->data as $photo) {
$img = $photo->images->{$display_size="thumbnail"};
echo "<li><a href='{$photo->link}'><img src='{$img->url}' /></a></li>";
}
echo "</ul>";
?>
It was working just fine on my domain, but when I moved it to my client's domain I'm getting this error: Warning: Invalid argument supplied for foreach() in /home/savenors/savenorsmarket.com/bostoninsta.php on line 53
What happened? I'm guessing whatever I did to get this to work wasn't really working.. but it looked fine to me. Any ideas? This is the website: http://www.savenorsmarket.com
Here's code that is working on my machine pulling in twice. It pulls the same user pictures twice, but to fix this just reset the user id variable before making a second call to fetchData();
<?php
$userid = "idHere";
// http://instagram.com/developer/
$clientid = "IDhere";
// number of photos to return
$count = "4";
// Gets our data
function fetchData($url){
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_TIMEOUT, 20);
$result = curl_exec($ch);
curl_close($ch);
return $result;
}
// Pulls and parses data.
$result = fetchData("https://api.instagram.com/v1/users/{$userid}/media/recent/?client_id={$clientid}&count={$count}");
$result = json_decode($result);
// cycles through the json tree and uses the low res url in the img tag
echo "<ul>";
foreach ($result->data as $photo) {
$img = $photo->images->{$display_size="thumbnail"};
echo "<li><a href='{$photo->link}'><img src='{$img->url}' /></a></li>";
}
echo "</ul>";
// Set User ID here for different profile
//$userid = "idHere";
$result = fetchData("https://api.instagram.com/v1/users/{$userid}/media/recent/?client_id={$clientid}&count={$count}");
$result = json_decode($result);
// cycles through the json tree and uses the low res url in the img tag
echo "<ul>";
foreach ($result->data as $photo) {
$img = $photo->images->{$display_size="thumbnail"};
echo "<li><a href='{$photo->link}'><img src='{$img->url}' /></a></li>";
}
echo "</ul>";
?>
Also note that I'm using the client_id over the access_token. It should work either way though.

How save Facebook user display picture to the disk Without using file_get_contents()`?

Hello I am trying to get the user profile picture and then merge into an existing image as per my Facebook app requirement. For that I need to check its mime time etc. But I am having difficulty in retrieving and saving the picture.
$facebook = new Facebook($config);
$user = $facebook -> getUser();
if ($user) {
$user_profile = $facebook -> api('/me');
}
//User Info. Variables:
try {
$userPpicture = $user_profile[picture];
}
Now we I have retrieved this I want to save this image on disk so I could check its mime time etc. for further processing, how can I achieve this?
p.s. due to my hosting server restrictions I can’t use the function file_get_contents(). So I need a solution except this.
Kindly help.
thank-you.
cURL try:
//Create image instances
$url = "http://graph.facebook.com/{$userId}/picture?type=large";
$dpImage = 'temp/' . $userId . '_dpImage_' . rand().'.jpg';
echo $dpImage;
function get_data($url) {
$ch = curl_init();
$timeout = 5;
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);
$data = curl_exec($ch);
curl_close($ch);
return $data;
}
$returned_content = get_data($url);
file_put_contents($dpImage, $returned_content);
echo "Type: " . exif_imagetype($dpImage);
getting this error while checking the mime type of the image:
Notice: exif_imagetype(): Read error! in
Are you allowed to use CURL ?
If so, just follow http://phpsense.com/2007/php-curl-functions/

Get artist image from last.fm xml (api artist.getinfo)

I wanted to ask you help I have an xml source (http://livefmhits.6te.net/nowplay.xml) it gives me the source of the song and I wanted to remove the cover through the lastfm (artist.getinfo) in echo I tried as follows:
<?php
$xml = simplexml_load_file('http://livefmhits.6te.net/nowplay.xml');
$artist = urlencode($xml->TRACK["ARTIST"]);
$url = 'http://ws.audioscrobbler.com/2.0/?method=artist.getinfo&artist='.$artist.&api_key=b25b959554ed76058ac220b7b2e0a026;
$xml2 = #simplexml_load_file($url);
if ($xml2 === false)
{
echo("Url failed"); // do whatever you want to do
}
else
{
if($xml2->track->album->image[3])
{
echo '<img src="';
echo((string) $xml2->track->album->image[3]);
echo '">';
}
else
{
echo "<img src='http://3.bp.blogspot.com/-SEsYAbASI68/VZ7xNuKy-GI/AAAAAAAAA3M/IWcGRDoXXms/s1600/capaindisponivel.png'"; // do whatever you want to do
}
}
I'm not able to extract the source must be wrong echo, I like to remove the image that says "mega". I present to you the complete link
http://ws.audioscrobbler.com/2.0/?method=artist.getinfo&lang=ru&artist=COLDPLAY&api_key=ae9dc375e16f12528b329b25a3cca3ee and yet I was to do a post yours but I could not (Get large artist image from last.fm xml (api artist.getinfo))
I came to ask your help in this work from the outset thanks for availability
Here is how I'm doing it in json. It's pretty much the same in XML.
First, we define the API KEY:
define('YOUR_API_KEY', 'b25b959554ed76058ac220b7b2e0a026');
It's better to separate it from the code, it makes things easier if you need to reuse it somewhere else in your code. (for eg. in another function)
Then, we create the 2 functions we need to make the magic happen.
1) To query Lastfm's API and get its content, we will use CURL:
function _curl($url)
{
$ch = curl_init();
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 15);
if(strtolower(parse_url($url, PHP_URL_SCHEME)) == 'https')
{
curl_setopt($ch,CURLOPT_SSL_VERIFYPEER,1);
curl_setopt($ch,CURLOPT_SSL_VERIFYHOST,1);
}
curl_setopt($ch, CURLOPT_URL, $url);
$data = curl_exec($ch);
curl_close($ch);
return $data;
}
2) Lastfm offers many options. Personally, I find it's easier to separate main queries into functions. But as you simply target images, here is the function I'd use:
function lfm_img($artist)
{
$url = "http://ws.audioscrobbler.com/2.0/?method=artist.getinfo&artist=$artist&api_key=".YOUR_API_KEY."&format=json";
$json = _cul($url);
$data = str_ireplace("#text", "text", $json);
$list = json_decode($data);
//If an error occurs...
if($list->error)
return 'ERROR.'. $list->error;
//That's where we get the photo. We try to get the biggest size first, if not we try smaller sizes. Returns '0' if nothing is found.
if($list->artist->image[4])
$img = $list->artist->image[4]->text;
else if($list->artist->image[3])
$img = $list->artist->image[3];
else if($list->artist->image[2])
$img = $list->artist->image[2];
else if($list->artist->image[1])
$img = $list->artist->image[1];
else if($list->artist->image[0])
$img = $list->artist->image[0];
else
$img = 0;
return $img;
}
And finally, use them:
$artist_query = 'Nirvana';
$artist_image = lfm_img($artist);
//display image
echo '<img src="'. $artist_image .'" alt="'. $artist_query .'" />';
I think it's self explanatory here. ;)
Hope it helped!

Categories