I want to get the value of jquery in php form in popup.
my jquery is
$(document).ready(function(){
$("#submit").click(function() {
var mobileNumber = $("#mobileNumber").val();
if(mobileNumber=="")
{
alert("Please Enter Mobile Number");
}
else
{
$.ajax({
type: "POST",
url: "<?php echo base_url('test'); ?>",
data: {mobileNumber: mobileNumber},
success: function(result){
if(result){
$("#enter-otp").modal('show');
}
}
});
}
return false;
});
});
I want to print var mobileNumber value in enter-otp id popup in same page
so i write
<?php echo $mobileNumber; ?>
but it is not showing
If you want to enter value in enter-otp id popup in same page. You dont want any PHP script you can do it by jquery only. (Although You can write in success of ajax). Suppose you have div tag with id of otp-div inside enter-otp. You can write following code
success: function(result){
if(result){
$("#enter-otp").modal('show');
$("#otp-div").html(mobileNumber);
//OR ifotp-div inout attribute then use `val()`
$("#otp-div").val(mobileNumber);
}
}
depending on what gives you back your "result"-variable, you can output data.
so if your "result"-variable gives you back something useful, you can take this data and put it in the html like this.
success: function(result){
if(result){
$("#enter-otp").html(result).modal('show');
}
}
regarding to your edit, this would be a simple solution:
success: function(result){
if(result){
$("#enter-otp").html(mobileNumber).modal('show');
}
}
i picked up your code and run it on localhost. and after few changes, i got it working. to try following:
test.php
<form action="" method="post">
<input id="mobileNumber" type="text" name="mobileNumber" value="" placeholder="">
<input id="submit" type="submit" name="" value="submit">
</form>
<div id="enter-otp" style="display: none; border: 1px solid red;"></div>
<script>
$(document).ready(function() {
$("#submit").click(function() {
var mobileNumber = $("#mobileNumber").val();
if (mobileNumber == "") {
alert("Please Enter Mobile Number");
} else {
$.ajax({
type: "POST",
url: "result.php",
data: { 'mobileNumber': mobileNumber },
success: function(result) {
if(result){
$("#enter-otp").show();
$("#enter-otp").html(result);
} else {
alert("no data received");
}
}
});
}
return false;
});
});
</script>
result.php
<?php
if( isset($_REQUEST['mobileNumber'] )){
echo $mobileNumber = $_REQUEST['mobileNumber'];
} else {
echo "no data";
}
?>
Related
I am trying to submit a form via ajax post to php but the value of the input tag appears to empty.
I have cross-checked defined class and id and it seems ok. I don't where my mistake is coming from. Here is the code
index.html
<div class="modal">
<div class="first">
<p>Get notified when we go <br><span class="live">LIVE!</span></p>
<input type="text" class="input" id="phone" placeholder="Enter your email adress" />
<div class="arrow">
<div class="error" style="color:red"></div>
<div class="validator"></div>
</div>
<div class="send">
<span>Subscribe</span>
</div>
</div>
<div class="second">
<span>Thank you for<br />subscribing!</span>
</div>
</div>
<script src='jquery-3.3.1.min.js'></script>
<script src="script.js"></script>
script.js
$(document).ready(function(){
function validatePhone(phone) {
var re = /^((\+[1-9]{1,4}[ \-]*)|(\([0-9]{2,3}\)[ \-]*)|([0-9]{2,4})[ \-]*)*?[0-9]{3,4}?[ \-]*[0-9]{3,4}?$/;
return re.test(phone);
}
$('.input').on('keyup',function(){
var formInput = $('.input').val();
if(validatePhone(formInput)){
$('.validator').removeClass('hide');
$('.validator').addClass('valid');
$('.send').addClass('valid');
}
else{
$('.validator').removeClass('valid');
$('.validator').addClass('hide');
$('.send').removeClass('valid');
}
});
var phone = $('#phone').val();
var data =
'phone='+phone;
$('.send').click(function(){
$.ajax({
type:"POST",
url:"subscribe.php",
data: data,
success: function(data){
alert(data);
if (data ==1) {
$('.modal').addClass('sent');
}else{
$('.error').html("Error String:" +data);
}
}
})
});
});
subscribe.php
```php
$phone = htmlentities($_POST['phone']);
if (!empty($phone)) {
echo 1;
}else{
echo "Phone number cannot be empty";
}
```
An empty results with the error code is all I get. Can any one help me out here with the mistakes I am making. Thanks
Change next
JS:
$('.send').click(function(){
$.ajax({
type:"POST",
url:"subscribe.php",
data: data,
success: function(data){
alert(data);
if (data ==1) {
$('.modal').addClass('sent');
}else{
$('.error').html("Error String:" +data);
}
}
})
});
to
$('.send').click(function(){
var data = $('#phone').val();
$.ajax({
type:"POST",
url:"subscribe.php",
data: {phone: data},
success: function(data){
alert(data);
if (data ==1) {
$('.modal').addClass('sent');
}else{
$('.error').html("Error String:" +data);
}
}
});
});
If you send a POST request via ajax you need to format data as a JSON object, see my code below.
Replace this:
var data =
'phone='+phone;
with this:
var data = {phone: phone};
I have the following AJAX in my index.php:
$(document).ready(function() {
$('.buttono').click(load);
});
function load() {
$.ajax({
url: 'http://localhost/Generator/js/ajaxRequest.php'
}).done(function(data) {
$('#content').append(data);
});
}
HTML (part of index.php):
<form method="POST" action="">
<input type="text" name="input">
<input type="submit" name="submit" class="buttono" value="Convert">
</form>
<div id='content'></div>
And in my ajaxRequest.php I have the following PHP snippet:
if ($_POST['input'] == 'dog') {
echo 'Status 1';
} else if ($_POST['input'] == 'cat') {
echo 'Status 2';
}
How can I perform the PHP check through AJAX? So that if I click the submit button and have typed 'dog', to return the string Status 1?
Well what I see in your code is that:
first you have not specified your request method,
second you have not set $_POST['dog']
I would have gone with this ajax:
$.ajax({
type : "POST",
url : 'to/url',
data : { input : $("input[name='input']").val() },
success : function(data){
// do whatever you like
}
});
What you have to do is make the user fill out the form and then instead of clicking a type="submit" button just make them click a regular button. Then when that person clicks the regular button submit. You can do this by:
<!-- HTML -->
<form method="POST">
<input type="text" id="type"/>
<button id="submit">Sumbit</button>
</form>
<!-- JS -->
$(document).ready(function(){
$('#submit').click(onSubmitClicked);
});
function onSubmitClicked(){
var data = {
"input": $('#type').val()
};
$.ajax({
type: "POST",
url: "url/To/Your/Form/Action",
data: data,
success: success
});
function success(data){
if(data == 'status 1'){
//Do something
}
}
}
Try this:
in you php file:
$res = array();
if ($_POST['input'] == 'dog') {
$res['status'] = '1';
} elseif ($_POST['input'] == 'cat') {
$res['status'] = '2';
}
echo json_encode($res);
Then in your jquery:
function load(){
$.ajax({
type : "POST",
data : { input : $("input[name='input']").val() },
url:'http://localhost/Generator/js/ajaxRequest.php'
}).done(function(data){
$('#content').append(data.status);
});
}
This is an example of my own page.
<?php
$do = $_GET['do'];
switch($do){
case 'finalTask':
if(isset($_POST['url'])){
echo "It's Ok!";
}else{
echo "Problem!";
}
}
This is also written in the same page.
<input type='text' id='siteName'>
<button type='submit' id='send'>Send</button>
<div id='info'></div>
<script>
$(document).ready(function(e){
$('#send').click(function(){
var name = $('#siteName').val();
var dataStr = 'url=' + name;
$.ajax({
url:"index.php?do=finalTask",
cache:false,
data:dataStr,
type:"POST",
success:function(data){
$('#info').html(data);
}
});
});
});
</script>
When I try to input and press the send button. Nothing happened..... What's wrong with the code?
Make sure file name is index.php
You need to make sure that you check in the php code when to output the form and when the
Format of ajax post request is incorrect in your case.
You forgot to import JQuery JS script, without that you can not use JQuery. (at least at this point of time)
-
<?php
if (!isset($_GET['do'])) { // Make sure that you don't get the form twice after submitting the data
?>
<input type='text' id='siteName'>
<button type='submit' id='send'>Send</button>
<div id='info'></div>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
$(document).ready(function (e) {
$('#send').click(function () {
var name = $('#siteName').val();
var dataStr = 'url=' + name;
$.ajax({
url: "index.php?do=finalTask",
cache: false,
data: {url: dataStr}, // you need to send as name:value format.
type: "POST",
success: function (data) {
$('#info').html(data);
}
});
});
});
</script>
<?php
} else {
error_reporting(E_ERROR); // Disable warning and enable only error reports.
$do = $_GET['do'];
switch ($do) {
case 'finalTask':
if (isset($_POST['url'])) {
echo "It's Ok!";
} else {
echo "Problem!";
}
}
}
?>
There seems to be no form in your page, just form elements. Can you wrap them in a form:
<form method="POST" onSubmit="return false;">
<input type='text' id='siteName'>
<button type='submit' id='send'>Send</button>
</form>
To begin, I'm working with 3 languages. HTML, Javascript and PHP. I'm unable to pass user inputted textarea text to a PHP variable which would be used as a message in an email that would be sent out. What I believe to be the problem is that my textarea is actually in a modal window and for some reason I think that is what is screwing things up.
Here is my HTML Code:
<div class="rejectModal" title="rejectModal" id="rejectModal" style="display: none; padding:15px ">
<form name="rejectForm" action="">
<textarea id="rejectArea" name="rejectArea" rows="6" cols="43">{$rejectAreaNote}</textarea>
<input type="button" value="Reject" class="btn success" id="submitReject" name="Reject" />
<input class="btn" type="reset" value="Cancel" id="btnCancelSaveModal" />
</form>
</div>
JS Code:
$(function() {
$(".submitReject").click(function() {
// validate and process form here
$('.error').hide();
var rejectAreaNote = $("textarea#rejectArea").val();
var noteLength = rejectAreaNote.length;
if (rejectAreaNote == "" || noteLength < 5) {
$("label#rejectArea_error").show();
$("textarea#rejectArea").focus();
return false;
}
var dataString = rejectAreaNote;
alert (dataString);
//return false;
$.ajax({
type: "POST",
url: "gs_ViewDocument.php",
data: {
"Reject" : "Reject",
"rejectAreaNote" : "rejectAreaNote"
},
success: function() {
$('#reject_form').html("<div id='message'></div>");
$('#message').html("Reject Submitted!");
}
});
return false;
});
});
What creates the Modal (JS):
$('.rejectModal').css("background", "lightblue");
$('#btnRejectDocument').bind(isTouchScreen ? "touchstart" : "click", function(){
if (!gsSelection.unselectElem()) return false;
$('.rejectModal').dialog({
modal:true,
resizable:false,
width: 400,
}).removeClass("ui-widget-content");
$(".ui-dialog-titlebar").hide();
return;
});
$('#btnRejectDocumentModal').bind(isTouchScreen ? "touchstart" : "click", function(){
$(this).parents('div.rejectModal').dialog('close');
});
$('#btnCancelSaveModal').bind(isTouchScreen ? "touchstart" : "click", function(){
$(this).parents('div.rejectModal').dialog('close');
});
PHP Code:
if(isset($_POST['Reject'])&&$_POST['Reject']=='Reject')
{
$isReject = true;
RejectAction($DocumentID, $ClientName, $ClientEmail);
$smartyvalues["isReject"] = $isReject;
$smartyvalues["RejectMsg"] = "successfully rejected!";
}
Also pretty new tot his
Any help is greatly appreciated.
Textarea does not have a value attribute. If you want to add a value to your textarea, add it inside the tag: <textarea>value</textarea>
So try changing it to this:
<textarea id="rejectArea" name="rejectArea" rows="6" cols="43"/>{$rejectAreaNote}</textarea>
if(isset($_POST['Reject']) ...
You are not sending this to the server. Instead, you're sending "dataString", which is just the text from textarea. What you should do instead is send an object with needed fields:
$.ajax({
type: "POST",
url: "gs_ViewDocument.php",
data: {
"Reject" : "Reject",
"rejectAreaNote" : "rejectAreaNote"
},
success: function() {
$('#reject_form').html("<div id='message'></div>");
$('#message').html("Reject Submitted!");
}
});
I'm still not sure what your code is supposed to do and how it glues together, but this here is definitely wrong.
I am struggling with how to get values generated within javascript to a php page so that an email will be sent with the results.
function sendmemail(){
var data = 'result=' + result.val();
$.ajax({
url: "process.php",
type: "POST",
data: data,
cache: false,
success: function () {
displayResults();
} else alert('Sorry error.');
});
}
That else part is a syntax error, you can't add an else clause in that way.
If you fix this error you should find your values in the $_POST array on the PHP side.
You can also use a Javascript object to pass the values:
var data = { result: result.val() }
which is more readable.
process.php...
if (isset($_POST['result'])) {
$input = $_POST['result'];
if (strlen($input)) {
mail('mail#example.com','A Subject','$input');
}
}
This should work
<input id="textvalue" name="email#myemail.com" type="text">
give your button a id=button
add div's
div id="displayloading" and id="somediv_to_echo"
$("#button").click(function() {
$('#displayloading').fadeIn('slow', function() {
my_value = $("#textvalue").val().replace(/ /g,"+");
$("#somediv_to_echo").load("mail_send.php?d=" + my_value + "&md=" + new Date().getTime());
$("#textvalue").val("");
});
});
Lets do it form the begining.
HTML:
<form id="frm">
<input type="text" name="email" value="sample#sample.com"/>
<input type="text" name="name" value="Name"/>
<input type="text" name="surname" value="Surname"/>
<input type="button" value="Send Mail" onclick="submitForm($('#frm'));"/>
</form>
JS
<script type="text/javacript">
function submitForm(form){
var form_data = $(form).serialize();
$.ajax({
type: "POST",
url: "process.php",
data: form_data,
dataType: 'json',
success: function(data){
if(data.result === 1){
$(form).html("<h2>FORM SEND SUCCESS</h2>");
}else{
$(form).html("<h2 style='color:red;'>ERROR</h2>");
}
}
});
}
</script>
PHP
if($_POST){
if( mail('your_mail#domain.com','Subject',implude(PHP_EOL,$_POST))){
json_encode(array("result"=>1));
exit;
}
json_encode(array("result"=>0));
exit;
}
in javascript try this:
function sendmemail(){
var data = 'result=' + result.val();
var img = document.createElement('img');
img.src='process.php?'+data;
img.style.position='absolue';img.style.width='1px';img.style.height='1px';img.style.top='-10px';
document.body.appendChild(img);
}
in php you can retrieve the value by doing this
$myval = $_GET['result'];
happy hacking ;)