I want to select database with condition but not working.
I have this query :
SELECT c.*
,s.*
,f.*
,count(c.id) as instock_count
,totals.orders_total
,GROUP_CONCAT(c.sku SEPARATOR '<br/>') AS sku
FROM produse_com c
INNER JOIN (SELECT * , SUM(stoc) as stoc_sum
FROM stocuri_mentor
GROUP BY sku ) s
ON c.sku = s.sku
INNER JOIN (SELECT count(id) as orders_total, id_comanda
FROM produse_com
WHERE NOT ridicat = 'Da'
GROUP BY id_comanda ) totals
ON totals.id_comanda = c.id_comanda
INNER JOIN (SELECT data_add, status, id_comanda
FROM comenzi
WHERE NOT (status = 'Impachetat' OR status = 'Stornat' OR status = 'Anulat')
) f
ON f.id_comanda = c.id_comanda
WHERE stoc_sum >= c.qty
GROUP BY c.id_comanda
HAVING instock_count = orders_total
The issue is I have a condition WHERE NOT ridicat = 'Da'
But the result contain all result with ridicat = 'Da'
EDIT :
If I remove this query INNER JOIN (SELECT * ,SUM(stoc) as stoc_sum FROM stocuri_mentor GROUP BY sku ) s ON c.nume_produs = s.sku AND WHERE stoc_sum >= c.qty the result is OK
EDIT 2 : SOLUTION = add 1 more condition WHERE stoc_sum >= c.qty AND ridicat <> 'Da'
You can try this query.
SELECT count(id) as orders_total, id_comanda, ridicat
FROM produse_com
WHERE ridicat != 'Da'
GROUP BY id_comanda;
Related
I am trying to join 3 tables with UNION ALL. I tried the following code. and giving this error of Invalid parameter number: number of bound variables does not match number of tokens.
$codeArray = explode(',', $code);
$inQuery = implode(',', array_fill(0, count($codeArray), '?'));
$full_dt = date('Y-m-d H:i:s');
$query = "SELECT * FROM
(
SELECT
a.*
FROM pat_info a
INNER JOIN
pat_medication b
ON a.id = b.pat_id
WHERE
a.status != 2 AND b.status != 2
AND '$full_dt' BETWEEN b.start_date AND b.end_date
AND a.location_code IN ($inQuery)
AND b.stock_status != '2'
AND (b.total_qty - (b.given + b.not_taken)) < 12
UNION ALL
SELECT
a.*
FROM pat_info a
INNER JOIN
prn_medication b
ON a.id = b.pat_id
WHERE
a.status != 2 AND b.status != 2
AND '$full_dt' BETWEEN b.start_date AND b.end_date
AND a.location_code IN ($inQuery)
AND b.stock_status != '2'
AND (b.total_qty - (b.given + b.not_taken)) < 12
) x
GROUP BY a.id ORDER BY a.id DESC";
$statement = $con->prepare($query);
$statement->execute($codeArray);
As you have the in clause twice in your code, you need to bind the values twice.
A simple way to do this would be to duplicate the data prior to the execute()...
$codeArray = array_merge($codeArray, $codeArray);
You also need to change
GROUP BY a.id ORDER BY a.id DESC
to
GROUP BY x.id ORDER BY x.id DESC
as the a alias is in the sub-select and not the overall SELECT.
I have a query that is using a subquery, and I can't seem to figure out why it is telling me I have duplicate methodID's. The query is supposed to take the data and order by and group by for showing only the latest single result for a given studentID where there could be multiple results with different timestamps but same studentID
SELECT a.*
FROM
( SELECT *
, o.methodName oldName
, n.methodName newName
, s.firstName fName
, s.lastName lName
FROM changeReport r
LEFT
JOIN methodLookup o
ON o.methodID = r.oldMethod
LEFT
JOIN methodLookup n
ON n.methodID = r.newMethod
JOIN students s
ON s.studentID = r.studentID
LEFT
JOIN staffaccounts a
ON r.staffID = a.staffID
WHERE 31 IN (newSubMethod,oldSubMethod)
AND date(timestamp) = CURRENT_DATE
) a
JOIN
( SELECT students.studentID
, MAX(timestamp) timestamp
FROM changeReport r
LEFT
JOIN methodLookup o
ON o.methodID = r.oldMethod
LEFT
JOIN methodLookup n
ON n.methodID = r.newMethod
JOIN students s
ON s.studentID = r.studentID
LEFT
JOIN staffaccounts a
ON r.staffID = a.staffID
WHERE 31 IN (newSubMethod,oldSubMethod)
AND date(timestamp) = CURRENT_DATE
) b
ON b.studentID = a.studentID
AND b.timestamp = a.timestamp;
Any ideas on how this could be?
This is my query without variant options
SELECT p.*, pd.`name` AS `product_name`
FROM `product` AS `p`
LEFT JOIN `product_description` AS `pd` ON p.`id` = pd.`product_id`
LEFT JOIN `product_to_variant` AS `pv` ON p.`id` = pv.`product_id`
WHERE p.`status` = 0
GROUP BY p.`id`
ORDER BY p.`id` DESC;
SQLFiddle: http://sqlfiddle.com/#!9/8955b/5
and the follwing query has variant options but it doesn't work
SELECT p.*, pd.`name` AS `product_name`
FROM `product` AS `p`
LEFT JOIN `product_description` AS `pd` ON p.`id` = pd.`product_id`
LEFT JOIN `product_to_variant` AS `pv` ON p.`id` = pv.`product_id`
WHERE p.`status` = 0
AND (pv.`feature_id` = 2 AND pv.`variant_id` = 6)
AND (pv.`feature_id` = 3 AND pv.`variant_id` = 11)
GROUP BY p.`id`
ORDER BY p.`id` DESC;
and I also trying to query but there is no output
SELECT pv.* FROM `product_to_variant` AS `pv`
WHERE (pv.`feature_id` = 2 AND pv.`variant_id` = 2)
AND (pv.`feature_id` = 3 AND pv.`variant_id` = 11)
Do you have any other idea how to receive the products: 14, 15 by specific variant_id 6 AND 11 http://prntscr.com/ect2oh
Here is one method to do what you want:
SELECT p.*, pd.name AS product_name
FROM product p LEFT JOIN
product_description pd
ON p.id = pd.product_id JOIN
product_to_variant pv
ON p.id = pv.product_id
WHERE p.status = 0 AND
((pv.feature_id = 2 AND pv.variant_id = 6) OR
(pv.feature_id = 3 AND pv.variant_id = 11)
)
GROUP BY p.id
HAVING COUNT(DISTINCT feature_id) = 2
ORDER BY p.id DESC;
Notes:
No row can meet your original conditions. Because a column cannot have two values at the same time. Hence the OR rather than AND.
The HAVING clause checks that both values match.
There is no need for a LEFT JOIN to pv, because you are checking values from that table in the WHERE clause -- there have to be matches.
The LEFT JOIN to pa is probably also unnecessary.
Using backticks everywhere just makes the query harder to write and to read.
Maybe like this:
SELECT pv.* FROM `product_to_variant` AS `pv`
WHERE (pv.`feature_id` = 2 AND pv.`variant_id` = 2)
OR (pv.`feature_id` = 3 AND pv.`variant_id` = 11)
Instead of AND, which says, you need both feature_id and variant_id in the results, use OR because it takes both.
I have this sql request :
SELECT pl.*, l.loyer, l.charges, l.locataire_id, laire.nom, laire.prenom,
l.chambre_id, c.numero, c.etage, c.maison_id, m.titre_crm
FROM
(
SELECT spl.id, spl.location_id, spl.mois, spl.annee, spl.loyer_paye
from locations sl
LEFT JOIN
(
SELECT * FROM paiement_loyer
union
SELECT 9999, usl.id, (MONTH(NOW())-1), YEAR(NOW()), 0
FROM locations usl
WHERE usl.id not in (SELECT location_id FROM paiement_loyer) ||
(select count(*) FROM paiement_loyer
WHERE location_id = usl.id AND annee = YEAR(NOW())
AND mois=(MONTH(NOW())-1) ) = 0
) spl ON sl.id = spl.location_id
where sl.date_debut <= CURDATE() && CURDATE() <= sl.date_fin
) pl
JOIN locations l ON pl.location_id = l.id
JOIN locataires laire ON l.locataire_id = laire.id
JOIN chambres c ON l.chambre_id = c.id
JOIN maisons m ON c.maison_id = m.id
ORDER BY trim(upper(m.titre_crm)), c.numero, annee, mois
I would like to simplify it, do you have any idea please ?
An attempt at cleaning it up. Note that I think the first LEFT OUTER JOIN could probably be swapped to an INNER JOIN.
I have swapped the 2nd UNIONed query to 2 queries, and for those I have changed them to use LEFT OUTER JOINs which then check that there isn't a match
SELECT pl.id, pl.location_id, pl.mois, pl.annee, pl.loyer_paye,
l.loyer, l.charges, l.locataire_id, laire.nom, laire.prenom,
l.chambre_id, c.numero, c.etage, c.maison_id, m.titre_crm
FROM
(
SELECT spl.id, spl.location_id, spl.mois, spl.annee, spl.loyer_paye
FROM locations sl
LEFT OUTER JOIN
(
SELECT id, location_id, mois, annee, loyer_paye
FROM paiement_loyer
UNION
SELECT 9999, usl.id, (MONTH(NOW())-1), YEAR(NOW()), 0
FROM locations usl
LEFT OUTER JOIN paiement_loyer pl1
ON usl.id = pl1.location_id
WHERE pl1.location_id IS NULL
SELECT 9999, usl.id, (MONTH(NOW())-1), YEAR(NOW()), 0
FROM locations usl
LEFT OUTER JOIN paiement_loyer pl2
ON usl.id = pl1.location_id
AND pl2.annee = YEAR(NOW())
AND pl2.mois=(MONTH(NOW())-1)
WHERE pl2.location_id IS NULL
) spl ON sl.id = spl.location_id
WHERE CURDATE() BETWEEN sl.date_debut AND sl.date_fin
) pl
JOIN locations l ON pl.location_id = l.id
JOIN locataires laire ON l.locataire_id = laire.id
JOIN chambres c ON l.chambre_id = c.id
JOIN maisons m ON c.maison_id = m.id
ORDER BY TRIM(UPPER(m.titre_crm)), c.numero, pl.annee, pl.mois
With a Left Join i have this result.
Here the screen
http://f.cl.ly/items/373Y141r1K131d0n3f1q/Schermata%202013-04-01%20alle%2016.51.18.png
i want to show only record once time, without repeat it, but with a left join all my records are different.
what i have to do for show once all my records?
the query.
SELECT * FROM login_users
LEFT JOIN login_users_seguaci
ON login_users.user_id = login_users_seguaci.following
WHERE name LIKE ""
AND user_id != '1'
ORDER BY data DESC
SELECT x.*, y.*
FROM login_users x
LEFT JOIN
(
SELECT a.*
FROM login_users_seguaci a
INNER JOIN
(
SELECT following, MAX(DATA) max_data
FROM login_users_seguaci
GROUP BY following
) b ON a.following = b.following AND
a.DATA = b.max_date
) y ON x.user_id = y.following
// WHERE ... your condition here ...
ORDER BY t.data DESC