I have a query that is using a subquery, and I can't seem to figure out why it is telling me I have duplicate methodID's. The query is supposed to take the data and order by and group by for showing only the latest single result for a given studentID where there could be multiple results with different timestamps but same studentID
SELECT a.*
FROM
( SELECT *
, o.methodName oldName
, n.methodName newName
, s.firstName fName
, s.lastName lName
FROM changeReport r
LEFT
JOIN methodLookup o
ON o.methodID = r.oldMethod
LEFT
JOIN methodLookup n
ON n.methodID = r.newMethod
JOIN students s
ON s.studentID = r.studentID
LEFT
JOIN staffaccounts a
ON r.staffID = a.staffID
WHERE 31 IN (newSubMethod,oldSubMethod)
AND date(timestamp) = CURRENT_DATE
) a
JOIN
( SELECT students.studentID
, MAX(timestamp) timestamp
FROM changeReport r
LEFT
JOIN methodLookup o
ON o.methodID = r.oldMethod
LEFT
JOIN methodLookup n
ON n.methodID = r.newMethod
JOIN students s
ON s.studentID = r.studentID
LEFT
JOIN staffaccounts a
ON r.staffID = a.staffID
WHERE 31 IN (newSubMethod,oldSubMethod)
AND date(timestamp) = CURRENT_DATE
) b
ON b.studentID = a.studentID
AND b.timestamp = a.timestamp;
Any ideas on how this could be?
Related
This is my code i am trying to left join the latest team data, not every piece of data. i have tried just using limit 1 but doesnt return anything
ORDER BY updated DESC LIMIT 1
this doesnt work
Any ideas?
$sql = "SELECT
events.id, events.time,events.status, events.home_team,events.away_team,events.league,
ht.id as home_id,ht.name as home_name,at.name as away_name,
statistics.home_goals,statistics.away_goals,statistics.time as game_time,
leagues.id as league_id,leagues.name as league_name,leagues.type as league_type,
country.name as country_name,country.logo,
hts.home_scored, ats.away_scored,
hts.home_conceeded,ats.away_conceeded,
hts.home_win,ats.away_win,
hts.home_15,ats.away_15,
hts.home_25,ats.away_25,
hts.home_btts, ats.away_btts,
hts.home_fts, ats.away_fts,
hts.home_cs, ats.away_cs,
hts.home_corners_for, ats.away_corners_for,
hts.home_corners_against, ats.away_corners_against,
hts.home_cards, ats.away_cards
FROM events
LEFT JOIN teams ht
ON ht.id = events.home_team
LEFT JOIN teams at
ON at.id = events.away_team
LEFT JOIN leagues
ON leagues.id = events.league
LEFT JOIN country
ON country.id=leagues.country
LEFT JOIN ( SELECT team,home_scored,home_conceeded,home_win,home_15,home_25,home_btts,home_fts,home_cs,home_corners_for,home_corners_against,home_cards FROM team_quick_stats ORDER BY updated DESC) hts
ON ht.id=hts.team
LEFT JOIN ( SELECT team,away_scored,away_conceeded,away_win,away_15,away_25,away_btts,away_fts,away_cs,away_corners_for,away_corners_against,away_cards FROM team_quick_stats ORDER BY updated DESC) ats
ON at.id=ats.team
LEFT JOIN statistics
ON statistics.event_id=events.id
WHERE (events.time BETWEEN $start AND $end) ORDER BY country.list_order, leagues.country ASC , leagues.id ASC, events.time ASC, home_name ASC";
Here's one way. Replace LEFT JOIN (SELECT team... etc....) ats with...
LEFT
JOIN
( SELECT x.team
, x.etc...
FROM team_quick_stats x
JOIN
( SELECT team
, MAX(updated) updated
FROM team_quick_stats
GROUP
BY team
) y
ON y.team = x.team
AND y.updated = x.updated
) ats...
I have this sql request :
SELECT pl.*, l.loyer, l.charges, l.locataire_id, laire.nom, laire.prenom,
l.chambre_id, c.numero, c.etage, c.maison_id, m.titre_crm
FROM
(
SELECT spl.id, spl.location_id, spl.mois, spl.annee, spl.loyer_paye
from locations sl
LEFT JOIN
(
SELECT * FROM paiement_loyer
union
SELECT 9999, usl.id, (MONTH(NOW())-1), YEAR(NOW()), 0
FROM locations usl
WHERE usl.id not in (SELECT location_id FROM paiement_loyer) ||
(select count(*) FROM paiement_loyer
WHERE location_id = usl.id AND annee = YEAR(NOW())
AND mois=(MONTH(NOW())-1) ) = 0
) spl ON sl.id = spl.location_id
where sl.date_debut <= CURDATE() && CURDATE() <= sl.date_fin
) pl
JOIN locations l ON pl.location_id = l.id
JOIN locataires laire ON l.locataire_id = laire.id
JOIN chambres c ON l.chambre_id = c.id
JOIN maisons m ON c.maison_id = m.id
ORDER BY trim(upper(m.titre_crm)), c.numero, annee, mois
I would like to simplify it, do you have any idea please ?
An attempt at cleaning it up. Note that I think the first LEFT OUTER JOIN could probably be swapped to an INNER JOIN.
I have swapped the 2nd UNIONed query to 2 queries, and for those I have changed them to use LEFT OUTER JOINs which then check that there isn't a match
SELECT pl.id, pl.location_id, pl.mois, pl.annee, pl.loyer_paye,
l.loyer, l.charges, l.locataire_id, laire.nom, laire.prenom,
l.chambre_id, c.numero, c.etage, c.maison_id, m.titre_crm
FROM
(
SELECT spl.id, spl.location_id, spl.mois, spl.annee, spl.loyer_paye
FROM locations sl
LEFT OUTER JOIN
(
SELECT id, location_id, mois, annee, loyer_paye
FROM paiement_loyer
UNION
SELECT 9999, usl.id, (MONTH(NOW())-1), YEAR(NOW()), 0
FROM locations usl
LEFT OUTER JOIN paiement_loyer pl1
ON usl.id = pl1.location_id
WHERE pl1.location_id IS NULL
SELECT 9999, usl.id, (MONTH(NOW())-1), YEAR(NOW()), 0
FROM locations usl
LEFT OUTER JOIN paiement_loyer pl2
ON usl.id = pl1.location_id
AND pl2.annee = YEAR(NOW())
AND pl2.mois=(MONTH(NOW())-1)
WHERE pl2.location_id IS NULL
) spl ON sl.id = spl.location_id
WHERE CURDATE() BETWEEN sl.date_debut AND sl.date_fin
) pl
JOIN locations l ON pl.location_id = l.id
JOIN locataires laire ON l.locataire_id = laire.id
JOIN chambres c ON l.chambre_id = c.id
JOIN maisons m ON c.maison_id = m.id
ORDER BY TRIM(UPPER(m.titre_crm)), c.numero, pl.annee, pl.mois
I have a table structure like this
Table Structure
Here I want to select all the data from bus_routines table with bus details and avaliable_seat which is calculated from buses.number_of_seat - reserved_seats.number_of_reserved_seat - booking.number_of_seat even if the data is not present in booking table and reserved_seats table too where the bus_routines.sector_from=Ktm ,bus_routines.sector_to=Pkr and bus_routines.date=2015-12-15
Relation between them are :
buses and bus_routines --> one to many bus_routines and booking -->
one to many bus_routines and reserved_seats --> one to many
I have tried the following query
SELECT r.* , b.* ,
(
SELECT b.number_of_seat - sum(booking.number_of_seat)-sum(reserved_seats.number_of_reserved_seat)
FROM bus_routines AS r
INNER JOIN buses AS b
ON b.id = r.bus_id
INNER JOIN
(SELECT number_of_seat , bus_routine_id FROM booking GROUP BY booking.bus_routine_id) AS booking
ON booking.bus_routine_id = r.id
INNER JOIN (SELECT number_of_reserved_seat , routine_id FROM reserved_seats GROUP BY reserved_seats.routine_id) AS reserved_seats
ON r.id = reserved_seats.routine_id
WHERE
r.sector_from = "KTM" AND
r.sector_to = "PKR" AND
r.departure_date = "2015-12-15"
) AS avaliable_seat
FROM bus_routines AS r
INNER JOIN buses AS b
ON b.id = r.bus_id
WHERE
r.sector_from = "KTM" AND
r.sector_to = "PKR" AND
r.departure_date = "2015-12-15"
HAVING avaliable_seat > 0
I get the result what I want but the avaliable_seat is same for all the row
I have tried another query too but it give me the single result
SELECT r.* , b.* , b.number_of_seat - sum(booking.number_of_seat)-sum(reserved_seats.number_of_reserved_seat) AS available_seat
FROM bus_routines AS r
INNER JOIN buses AS b
ON b.id = r.bus_id
INNER JOIN
(SELECT number_of_seat , bus_routine_id FROM booking GROUP BY booking.bus_routine_id) AS booking
ON booking.bus_routine_id = r.id
INNER JOIN
(SELECT number_of_reserved_seat , routine_id FROM reserved_seats GROUP BY reserved_seats.routine_id) AS reserved_seats
ON r.id = reserved_seats.routine_id
WHERE
r.sector_from = "KTM" AND
r.sector_to = "PKR" AND
r.departure_date = "2015-12-15"
HAVING available_seat > 0
I also tried another query and it give me Subquery returns more than 1 row . The query is
SELECT r.* , b.* ,
b.number_of_seat - (SELECT sum(number_of_seat) FROM booking GROUP BY booking.bus_routine_id)
- (SELECT sum(number_of_reserved_seat) FROM reserved_seats GROUP BY reserved_seats.routine_id) AS available_seat
FROM bus_routines AS r
INNER JOIN buses AS b
ON b.id = r.bus_id
WHERE
r.sector_from = "KTM" AND
r.sector_to = "PKR" AND
r.departure_date = "2015-12-15"
HAVING available_seat > 0
One approach is to use correlated subqueries to get the reserved_seats and booked_seats for each bus_routine.
Let's assume that this query returns the rows you are wanting to return, it's just missing the available_seat column you want calculated:
SELECT r.*
, b.*
FROM bus_routines r
JOIN buses b
ON b.id = r.bus_id
WHERE r.sector_from = 'KTM'
AND r.sector_to = 'PKR'
AND r.departure_date = '2015-12-15'
To number of "reserved seats" for a given bus_routine, you can query the reserved_seats table, like this:
SELECT IFNULL(SUM(s.number_of_reserved_seat),0)
FROM reserved_seats s
WHERE s.routine_id = '649'
And the number of "booked seats" for a given bus_routine can be returned from the booking table, like this:
SELECT IFNULL(SUM(k.number_of_seat),0)
FROM booking k
WHERE k.bus_routine_id = '649'
We can incorporate the queries to get "reserved seats" and "booked seats" into the first query, as correlated subqueries. In place of the literal '649', with a reference the id from the bus_routine table.
SELECT r.*
, b.*
-- number of booked seats
, ( SELECT IFNULL(SUM(k.number_of_seat),0)
FROM booking k
WHERE k.bus_routine_id = r.id
) AS booked_seats
-- number of reserved seats
, ( SELECT IFNULL(SUM(s.number_of_reserved_seat),0)
FROM reserved_seats s
WHERE s.routine_id = r.id
) AS reserved_seats
-- calculate available seats as
-- (bus number_of_seat) - (booked_seats) - (reserved_seats)
, ( b.number_of_seat
- ( SELECT IFNULL(SUM(k.number_of_seat),0)
FROM booking k
WHERE k.bus_routine_id = r.id
)
- ( SELECT IFNULL(SUM(s.number_of_reserved_seat),0)
FROM reserved_seats s
WHERE s.routine_id = r.id
)
) AS avaliable_seat
FROM bus_routines r
JOIN buses b
ON b.id = r.bus_id
WHERE r.sector_from = 'KTM'
AND r.sector_to = 'PKR'
AND r.departure_date = '2015-12-15'
If there's no requirement to return the booked_seats and reserved_seats columns, those can be omitted from the query. The subqueries to get those values can just appear in the calculation of the available_seat column.
SQL Fiddle demonstration here: http://sqlfiddle.com/#!9/64eaa/7
Please try GROUP_CONCAT for return one column from multiple in subquery.
refer the links.
How to use GROUP_CONCAT in a CONCAT in MySQL
http://www.w3resource.com/mysql/aggregate-functions-and-grouping/aggregate-functions-and-grouping-group_concat.php
i have the following query which gives desired output in mysql , now i want to implement it in zend query language,
which has different approach to implement the query..
SELECT A.NAME , B.PAYMENT , C.TOTALPROJ , D.TOTALTASK , T.ACTIVETASK , H.HOUR
FROM USERMASTER AS A
LEFT OUTER JOIN
(
SELECT A.U_ID , SUM(A.TOTALTIME * B.RATE) AS PAYMENT
FROM
(
SELECT U_ID , PROJECT_ID ,
SUM(TIME_TO_SEC(CASE WHEN endtime is null then timediff (starttime,starttime)
ELSE timediff (endtime,starttime) END )) / 3600 AS TOTALTIME
FROM LOGMASTER AS A
WHERE PROJECT_ID IS NOT NULL
GROUP BY U_ID , PROJECT_ID
) AS A
INNER JOIN PROJECTTOUSER AS B ON A.PROJECT_ID = B.PROJECT_ID AND A.U_ID = B.U_ID
GROUP BY B.U_ID
) AS B ON A.ID = B.U_ID
LEFT OUTER JOIN
(
SELECT U_ID , COUNT(*) AS TOTALPROJ FROM PROJECTTOUSER GROUP BY U_ID
) AS C ON A.ID = C.U_ID
LEFT OUTER JOIN
(
SELECT ASSIGNED_TO , COUNT(*) AS TOTALTASK FROM TASKTOTARGET GROUP BY ASSIGNED_TO
) AS D ON A.ID = D.ASSIGNED_TO
LEFT OUTER JOIN
(
SELECT ASSIGNED_TO,COUNT(*) AS ACTIVETASK FROM TASKTOTARGET WHERE
IS_ACTIVE = 0 GROUP BY ASSIGNED_TO
) AS T ON A.ID = T.ASSIGNED_TO
LEFT OUTER JOIN
(
SELECT U_ID, SEC_TO_TIME(SUM(TIME_TO_SEC(CASE WHEN endtime is null then
timediff (starttime,starttime) ELSE timediff (endtime,starttime) END ))) AS HOUR
FROM LOGMASTER WHERE INSERT_DATE >= '2013-08-20' AND INSERT_DATE <='2013-08-31'
GROUP BY U_ID
) AS H ON A.ID = H.U_ID
so if any one can guide me in how to create this query in zend then it will be very helpful, and appreciated
Each of your subqueries becomes an new Zend_Query that you can then use just like a table and pass in to the main query.
For example:
$h = new Zend_Db_Select()
->from('LOGMASTER', array('U_ID', 'HOUR' => new Zend_Db_Expr('SEC_TO_TIME(SUM(TIME_TO_SEC(CASE WHEN endtime is null then
timediff (starttime,starttime) ELSE timediff (endtime,starttime) END ))))')
->where("INSERT_DATE >= '2013-08-20'")
->where("INSERT_DATE <= '2013-08-31'")
->group('U_ID');
$mainQuery = new Zend_Db_Select()
->from('a' => 'USERMASTER', array('NAME'))
->joinLeft($h, 'A.ID = H.U_IS', array('HOUR'));
You would create each of your subqueries as its own object and then you can join them into your main query. The last argument of the join function is which columns from the subquery should be added to the main query.
With ZF's fluid interface you can keep joining tables/queries until you have built your entire query.
http://framework.zend.com/manual/1.12/en/zend.db.select.html
With a Left Join i have this result.
Here the screen
http://f.cl.ly/items/373Y141r1K131d0n3f1q/Schermata%202013-04-01%20alle%2016.51.18.png
i want to show only record once time, without repeat it, but with a left join all my records are different.
what i have to do for show once all my records?
the query.
SELECT * FROM login_users
LEFT JOIN login_users_seguaci
ON login_users.user_id = login_users_seguaci.following
WHERE name LIKE ""
AND user_id != '1'
ORDER BY data DESC
SELECT x.*, y.*
FROM login_users x
LEFT JOIN
(
SELECT a.*
FROM login_users_seguaci a
INNER JOIN
(
SELECT following, MAX(DATA) max_data
FROM login_users_seguaci
GROUP BY following
) b ON a.following = b.following AND
a.DATA = b.max_date
) y ON x.user_id = y.following
// WHERE ... your condition here ...
ORDER BY t.data DESC