PHP Calendar to show years - php

Question

I have some code for a calendar. it works and displays as it should. However, I was wondering is there a way to display years?
At the moment it just shows current year (2018) but i would like for it to have buttons on side to go to next year, 2019 etc..
See code below. Can anyone help?

Answer 1

How about this:
You will need to pass an additional param to the query, in my example: y
With this, you will be able to create links to years like:
/page.php?y=1999&m=4
$monthArg = !empty($_GET['m']) ? intval($_GET['m']) : date('m');
$yearArg = !empty($_GET['y']) ? intval($_GET['y']) : date('Y'); // you will need to add an other query parameter for this
$currYear = $yearArg;
$startDate = strtotime($currYear . "-" . $monthArg . "-01 00:00:01");
$startDay = date("N", $startDate);
$monthName = date("M",$startDate );
$daysInMonth = cal_days_in_month(CAL_GREGORIAN, date("m", $startDate), date( "Y", $startDate));
$endDate = strtotime($currYear . "-" . $monthArg . "-" . $daysInMonth ." 00:00:01");
$endDay = date("N", $endDate);
if ($startDay> 6)
$startDay = 7 - $startDay;
$currElem = 0;
$dayCounter = 0;
$firstDayHasCome = false;
$arrCal = [];
for($i = 0; $i <= 5; $i ++) {
for($j= 0; $j <= 6; $j++) {
// decide what to show in the cell
if($currElem < $startDay && !$firstDayHasCome)
$arrCal[$i][$j] = "";
else if ($currElem == $startDay && !$firstDayHasCome) {
$firstDayHasCome= true;
$arrCal[$i][$j] = ++$dayCounter;
}
else if ($firstDayHasCome) {
if ($dayCounter < $daysInMonth)
$arrCal[$i][$j] = ++ $dayCounter;
else
$arrCal[$i][$j] = "";
}
$currElem ++;
}
}