Custom Month and Year inside php for-loop - php

Question

I saw this question:
how to get the previous 3 months in php
My question is.. How do i output from a custom month.
I want to start from Mar 2018 (or any M Y user inputs) and it should output the next 3 (or any number user inputs) months.
Ex: Mar, Apr, May
The code below is from current month and year.
// current month: Aug 2018
for ($i = 0; $i <= 2; $i++){
$x = strtotime("$i month");
echo $dte = date('M Y', $x);
echo '<br>';
}
And the output is
Aug 2018
Sep 2018
Oct 2018

Answer 1

You could use the DateTime class and increment using a DateInterval object:
// Assuming these are the user inputs
$month = 11;
$year = 2015;
// We create a new object with year and month format
$date = DateTime::createFromFormat('Y m', $year . ' ' . $month);
for ($i = 0; $i <= 2; $i++){
// Output the month and year
echo $date->format('m Y') . '<br>';
// Add 1 month to the date
$date->add(new DateInterval('P1M'));
}
Output:
11 2015
12 2015
01 2016
Documentation:
DateTime::createFromFormat
DateTime::format
DateTime::add

Answer 2

Change it to this as below it will give you as expected see the below code
// current month: Aug 2018
$effective_date = "MAR 2018";
for ($i = 0; $i <= 2; $i++){
$x = strtotime("$i month",strtotime($effective_date));
echo $dte = date('M Y', $x);
echo '<br>';
}

Answer 3

This may be also helpful:
<?php
$month = 11;
$year = 2017;
$count = 15;
for ($i = 1; $i <= $count; $i++) {
$month++;
if ($month > 12) {
$month = 1;
$year++;
}
$x = DateTime::createFromFormat('Y-m', $year.'-'.$month);
echo $x->format('m-Y');
echo '<br>';
}
?>
Output:
12-2017
01-2018
02-2018
03-2018
04-2018
05-2018
06-2018
07-2018
08-2018
09-2018
10-2018
11-2018
12-2018
01-2019
02-2019

Answer 4

Try this code for add nth Days, Months and Years
$n = 2;
for ($i = 0; $i <= $n; $i++){
$d = strtotime("$i days");
$x = strtotime("$i month");
$y = strtotime("$i year");
echo "Dates : ".$dates = date('d M Y', "+$d days");
echo "<br>";
echo "Months : ".$months = date('M Y', "+$x months");
echo '<br>';
echo "Years : ".$years = date('Y', "+$y years");
echo '<br>';
}

Answer 5

You can generate the date with strtotime() function
Check this phpfiddle
<?php
$currMonth = 11;
$currYear = 2017;
$count = 15;
$currentYear = date('M Y',strtotime($currYear.'-'.$currMonth));
echo $currentYear.'<br>';
for ($i = 1; $i < $count; $i++) {
$currMonth++;
if ($currMonth > 12) {
$currMonth = 1;
$currYear++;
}
$newMonthandYear = date('M Y',strtotime($currYear.'-'.$currMonth));
echo $newMonthandYear.'<br>';
}
?>

Answer 6

<?php
$year = date('Y');
//start at march
$startMonth = 7;
//go forwards 2 months
$stepForwards = 22;
for ($i = $startMonth; $i <= $stepForwards; $i++){
if($i > 12 ) {
$month = $i % 12 == 0 ? 12 : $i % 12;
}
else {
$month = $i;
}
echo date("M Y", strtotime(date($year.'-'.$month.'-1'))) . "<br/>";
if($month == 12) {
$year++;
echo "<br/>";
}
}