Count number of Sunday's in given Month and year - php

Question

I want output to be count of sunday's present in given month and year.
This is my code:
$months=$_POST['month'];
$years=$_POST['year'];
$monthName = date("F", mktime(0, 0, 0, $months));
$fromdt=date('Y-m-01 ',strtotime("First Day Of $monthName $years")) . '<br/>';
$todt=date('Y-m-d ',strtotime("Last Day of $monthName $years")) . '<br/>';
$num_sundays='';
for ($i = 0; $i < ((strtotime($todt) - strtotime($fromdt)) / 86400); $i++)
{
if(date('l',strtotime($fromdt) + ($i * 86400)) == 'Sunday')
{
$num_sundays++;
}
}
I am not getting any output if i echo $num_sundays. Please help me . I am new to PHP

Answer 1

You just need to remove <br> from these two lines:
$fromdt=date('Y-m-01 ',strtotime("First Day Of $monthName $years")) . '<br/>';
$todt=date('Y-m-d ',strtotime("Last Day of $monthName $years")) . '<br/>';
Otherwise this will be the part of start and end date, and your strtotime() will return false.
Example:
<?php
$months = 12;
$years=2016;
$monthName = date("F", mktime(0, 0, 0, $months));
$fromdt=date('Y-m-01 ',strtotime("First Day Of $monthName $years")) . '<br/>';
$todt=date('Y-m-d ',strtotime("Last Day of $monthName $years")) . '<br/>';
var_dump(strtotime($todt));
var_dump(strtotime($fromdt));
?>
DEMO: This will return false for both.
Example 2:
<?php
$months = 12;
$years=2016;
$monthName = date("F", mktime(0, 0, 0, $months));
$fromdt=date('Y-m-01 ',strtotime("First Day Of $monthName $years")) ;
$todt=date('Y-m-d ',strtotime("Last Day of $monthName $years"));
var_dump(strtotime($todt));
var_dump(strtotime($fromdt));
?>
DEMO: This will return the values
Complete Example:
<?php
$months = 12;
$years=2016;
$monthName = date("F", mktime(0, 0, 0, $months));
$fromdt=date('Y-m-01 ',strtotime("First Day Of $monthName $years")) ;
$todt=date('Y-m-d ',strtotime("Last Day of $monthName $years"));
$num_sundays='';
for ($i = 0; $i < ((strtotime($todt) - strtotime($fromdt)) / 86400); $i++)
{
if(date('l',strtotime($fromdt) + ($i * 86400)) == 'Sunday')
{
$num_sundays++;
}
}
echo "Total Count is: ".$num_sundays;
?>
DEMO: This will return 4 sunday

Answer 2

Without loop. I hope this gives the correct results.
date_default_timezone_set('UTC');
// unix timestamp 0 = Thursday, 01-Jan-70 00:00:00 UTC
// unix timestamp 259200 = Sunday, 04-Jan-70 00:00:00 UTC
$sun_first = strtotime('1970-01-04');
$t1 = strtotime('2018-10-01') - $sun_first - 86400;
$t2 = strtotime('2018-10-31') - $sun_first;
$sun_count = floor($t2 / 604800) - floor($t1 / 604800); // total Sunday from 2018-10-01 to 2018-10-31
echo $sun_count; // 4

Answer 3

Get all sunday in month see below code:
function total_sun($month,$year)
{
$sundays=0;
$total_days=cal_days_in_month(CAL_GREGORIAN, $month, $year);
for($i=1;$i<=$total_days;$i++)
if(date('N',strtotime($year.'-'.$month.'-'.$i))==7)
$sundays++;
return $sundays;
}
echo total_sun(11,2016);
http://phpio.net/s/l9f

Answer 4

Check following Example. I work perfectly..
function dayCount($day,$month,$year){
$totalDay=cal_days_in_month(CAL_GREGORIAN,$month,$year);
$count=0;
for($i=1;$totalDay>=$i;$i++){
if( date('l', strtotime($year.'-'.$month.'-'.$i))==ucwords($day)){
$count++;
}
}
echo $count;
}
dayCount('saturday',3,2019);

Answer 5

working example dorcode calculation
$startd="31-7-2006 15:30:00";
$endd="31-7-2007 15:30:00";
$startDate=$startd;
$endDate=$endd;
$startDate1 = strtotime($startDate);
$endDate1 = strtotime($endDate);
if($startDate1>$endDate1)
{
$startDate1 = strtotime($endDate);
$endDate1 = strtotime($startDate);
} else {
$startDate1 = strtotime($startDate);
$endDate1 = strtotime($endDate);
}
$p=0;
for($i = strtotime("Sunday", $startDate1); $i <= $endDate1;
$i =strtotime('+1 week', $i))
{
$p++;
echo $p.": ".date('F d, Y', $i)."<br>";
}

Answer 6

To get a count of any given day in a given month in a year:
$year = '2019';
$month = '2';
$day = 'Tuesday';
$count = 0;
$days = cal_days_in_month(CAL_GREGORIAN, $month, $year);
$date = new Datetime($year.'-'.$month.'-01');
for($i=1; $i<$days; $i++){
if($date->format('l') == $day){
$count++;
}
$date->modify('+1 day');
}
echo "Count: $count";

Answer 7

Use this code if it helps you
public function countWeekendDays($month, $year){
$daytime = strtotime(date($year."/".$month."/01 00:00:01"));
$daysOfMonth = date("t", $daytime);
$weekdays = 0;
for ($day=1; $day <= $daysOfMonth; $day++) {
$time = strtotime(date($year.'/'.$month.'/'.$day.' 00:00:01'));
$dayStr = date('l', $time);
if ($dayStr == 'Saturday' || $dayStr == 'Sunday') {
$weekdays++;
}
}
return $weekdays;
}

Answer 8

Simple code for day count:
function dayCount($day,$month,$year){
$totaldays = date('t',strtotime($year.'-'.$month.'-01'));
$countday = 4;
if(($totaldays - $day) >= 28 ){
$countday = 5;
}
return $countday;
}
echo dayCount(1,9,2019);

Answer 9

$day =Carbon\Carbon::now("Asia/Kolkata")->daysInMonth;
echo $day.'</br>';
if($day = 28) {
$weekend = 8;
}elseif($day = 29) {
$first_day_saturday = Carbon\Carbon::now("Asia/Kolkata")->firstOfMonth()->isSaturday();
$first_day_sunday = Carbon\Carbon::now("Asia/Kolkata")->firstOfMonth()->isSunday();
if($first_day_saturday || $first_day_sunday) {
$weekend = 9;
}else {
$weekend = 8;
}
}elseif($day = 30) {
$first_day_saturday = Carbon\Carbon::now("Asia/Kolkata")->firstOfMonth()->isSaturday();
$first_day_sunday = Carbon\Carbon::now("Asia/Kolkata")->firstOfMonth()->isSunday();
if ($first_day_saturday) {
$weekend = 10;
}elseif ($first_day_sunday) {
$weekend = 9;
}else {
$weekend = 8;
}
}else {
$first_day_thrusday = Carbon\Carbon::now("Asia/Kolkata")->firstOfMonth()->isThursday();
$first_day_friday = Carbon\Carbon::now("Asia/Kolkata")->firstOfMonth()->isFriday();
$first_day_saturday = Carbon\Carbon::now("Asia/Kolkata")->firstOfMonth()->isSaturday();
$first_day_sunday = Carbon\Carbon::now("Asia/Kolkata")->firstOfMonth()->isSunday();
if ($first_day_friday || $first_day_saturday) {
$weekend = 10;
}elseif ($first_day_sunday || $first_day_thrusday) {
$weekend = 9;
}else {
$weekend = 8;
}
}
echo $weekend.'</br>';