Write to MySQL on mouseover - php

After months of testing, I'm not succeeding to create a script that writes a logtext to the MySQL when a div gets a mouseover.
I think I have to use $.ajax, the only problem is, is that ajax (still) is the language which I'm not very good at.
One of the 100 things i've tried:
<?
echo "<div id='div0' rel=".$someid.">Some dynamic text</div>";
?>
<script>
$('.div0').mouseover(function() {
$('#result').load('../../../system/molog.php?cid='+$(this).attr('rel');
});
</script>
Who can help?

Ok, there's a much better way to do this, but since I'm on a phone that's dying and you have been waiting a year...
var info = $("#div0").html();
// if Js in a php file you can do var info = <?php echo $logtext ?>; To bring it to JS
$.get("phpfilehere.php", {info:info}, function(data){
alert(data);
});
The mouseover function...
$("#div0").on("mouseover", function(){
// my JS code above goes here
});
PHP file:
if(isset($_GET['info'])){
$log = $_GET['info'];
// Put ur stuff here, make sure u only echo when u want ur php script to stop and be sent back to Ajax function as data var.
// insert $log
echo "test";
} else {
echo "no get info supplied":
}
And here is a tool I made to teach people how to write prepared statements for SQL queries :) if you need it...
http://wbr.bz/QueryPro/index.php?query_type=prepared_insert

Related

How do I reload a input after 3 seconds with javascript

How do I reload this input once after 3 seconds has passed after the webpage has loaded. using javascript
<input type="text" name="steamID" id="steamID" value="<?php echo $steamid; ?>">
Try looking at this answer on SO:
Reload random div content every x seconds
If that doesn't work for you, you will have to use ajax to get new content. Look at jQuery's API here:
http://api.jquery.com/jQuery.ajax/
Or if you're not using jQuery, look at this for a tutorial on AJAX:
http://www.w3schools.com/ajax/default.asp
Otherwise, for more help, please post more of your code -- but ajax will have to be used
If you want the PHP in your code to be run again, you need to make you code a little more complicated.
You will need the following components
a php file that will lookup and print $steamid only.
a javascript function that uses AJAX to get the information from the php file, sets the value of your input
call the javascript on page load, then set an interval for 3 seconds and call it again.
But based on this...
The problem i have that the PHP var $steamid are set after the input has been created so all i need todo is reload the input so the $steamid will show.
... I think you just need to re-order your PHP code.
By reset, I am assuming you mean set the value to null.
$(window).load(function(){
setTimeout( function() {
document.getElementById("steamID").value = "";
},3000);
});
EDIT: Based on your further description, wait until steamID is set, then put this on the page:
<script type="text/javascript">
document.getElementById("steamID").value = "<?php echo $steamid; ?>";
</script>
<?php
echo "<script type='text/javascript'>";
$steamid = "testing 1,2,3";
echo " var sID = '".$steamid."';";
?>
function setupRefresh() {
setInterval("refreshVal()", 3000);
}
function refreshVal() {
var e = document.getElementById('steamID');
e.value = sID;
}
</script>

Delete db row according to Javascript Result

How can I halt a php code block when JS confirm false result. My php code like this;
<?php
function func($msg){
echo '<script type="text/javascript">
var r = confirm('$msg');
if(r==false){
return false;
}else{
return true;
}
</script>';
}
.
.
case "update":
func("Do you want to delete?");
mysql_query("UPDATE.....");
break;
?>
When func() result is false, dont process mysql_query()
With this approach it can not be done.
Javascript and PhP are different things. Javascript executes on client side end but php is server end. You would have to take into Account the power of Ajax. have a look at something similar
How to Delete MySQL Rows with Ajax & jQuery
SIMPLE JQUERY AJAX DELETE WITH CONFIRMATION

Best way to refresh multiple PHP values every x seconds?

I have an index.php file that I would like to run getdata.php every 5 seconds.
getdata.php returns multiple variables that need to be displayed in various places in index.php.
I've been trying to use the jQuery .load() function with no luck.
It's refreshing the 12 <div> elements in various places on the index.php, but it's not re-running the getdata.php file that should get the newest data.
But If I hit the browser refresh button, the data is refreshed.
getdata.php returns about 15 variables.
Here is some sample code:
<script>
var refreshId = setInterval(function()
{
$('#Hidden_Data').load('GetData.php'); // Shouldn´t this return $variables
$('#Show_Data_001').fadeOut("slow").fadeIn("slow");
$('#Show_Data_002').fadeOut("slow").fadeIn("slow");
$('#Show_Data_003').fadeOut("slow").fadeIn("slow");
$('#...').fadeOut("slow").fadeIn("slow");
}, 5000); // Data refreshed every 5 seconds
*/
</script>
Here's an example of GetData.php:
$query = "SELECT column1, COUNT(column2) AS variable FROM table GROUP BY column";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){
$column1 = $row['column1 '];
$variable = $row['variable '];
if($column1 == "Text1") { $variable1 = $variable; }
elseif($column1 == "Text2") { $variable2 = $variable; }
... continues to variable 15 ...
}
Then further down the page the HTML elements display the data:
<div id="Hidden_Data"></div>
<div id="Show_Data_001"><?php echo $variable1; ?></div>
<div id="Show_Data_002"><?php echo $variable2; ?></div>
<div id="Show_Data_003"><?php echo $variable3; ?></div>
...
I tried using the data parameter as suggested here:
https://stackoverflow.com/a/8480059/498596
But I couldn't fully understand how to load all the variables every 5 seconds and call them on the index page.
Today the GetData.php page just returns $variable1 = X; $variable2 = Y and so on.
UPDATE
For some reason the jQuery is not loading the GatData.php file and refreshing the variables.
I tried adding to "Hidden_Data" to the include('GetData.php') and then the variables are readable on the page.
If I remove this part, the page displays "variable not set" warning that suggesting that the jQuery is not loading the GetData.php script into the Hidden_Data <div>.
Try
<script>
var refreshId = setInterval(function()
{
$('#Hidden_Data').load('GetData.php', function() { // Shouldn´t this return $variables
$('#Show_Data_001').fadeOut("slow").fadeIn("slow");
$('#Show_Data_002').fadeOut("slow").fadeIn("slow");
$('#Show_Data_003').fadeOut("slow").fadeIn("slow");
$('#...').fadeOut("slow").fadeIn("slow"); });
}, 5000); // Data refreshed every 5 seconds
*/
</script>
Above is assuming, that your code returns snippet of HTML elements (Show_Data_XXX), but now that you've clarified your question above wont help you alone...
What you need to do is either in your php send back new value elements or send back your results as data and update existing elements.
Put your elements into a php Array and then send it back
data.php after sql call
$results = Array();
while($row = mysql_fetch_array($result)){
$column1 = $row['column1 ']; // change Text1 in db to Show_Data_001 in html or vice versa
$variable = $row['variable '];
$results[$column1] = $variable;
}
echo json_encode($results);
in your javascript something like this...
$.getJSON('GetData.php',function(data) {
$.each(data, function(key, val) {
$('#'+key).text(val);
});
});
I didn't put the fadeOut and fadeIn into the example, because it complicates it a bit. You could do fadeOut to all those elements before calling getJSON and the fadeIn as the results pouring in. Hope this helps
First of all, make sure you have correct respond from server, just like this:
//We won't use load() to load content for now
window.setInterval(function(){
$.ajax({
url : "path_to_your_php_script.php",
type : "GET",
beforeSend: function(){
//here you can display, smth like "Please wait" in some div
},
error : function(msg){
//You would know if an error occurs
alert(msg);
},
success : function(respondFromPHP){
//Are you getting distinct results every 5 sec?
alert(respondFromPHP);
return;
//if respondFromPHP contains data you want
//ONLY THEN, add some effects
}
});
}, 5000);
The only difference between this approach and yours, is that, you can handle errors and make sure you are getting data you want.
Can you show me the code of GetData.php?
Rather than using Jquery.load you can actually get the page with $.post or $.get and format your results from GetData.php to Json or xml you can easily map it to your javascript.
Using $.post it will allow you to have a callback after getting the value from GetData.php and you can check it if it's working right or not. If it gets a data from your GetData.php then you can populate it to your DIV elements.
You can check more information regarding POST and GET here:
http://api.jquery.com/jQuery.post/

How to make the JS function get the data from the database everytime I call it?

I am using a code look like this:
<script>
function getdata()
{
var employee =
<?php
//connect to database and get employee name
echo "'" . $row['empnm'] "'";
?>;
}
</script>
print them
It works, but the function is running the PHP code only on the page loading and not every time I call the function. So, if the target employee name is changed the JS function will show the old name untill the page is reloaded. How to make the JS function get the data from the database everytime I call it?
look into a library like jQuery
Then using the following code
function getdata(){
$.post("path/to/file.php", function(data) {
var employee = data;
// do whatever with the data.
});
}
and you can still use your same html
print them
and file.php
<?php
// connect to your db, get your results, echo them back
echo $row['empnm'];
?>
When you first request the page, PHP renders out a whole string of html, then your browser executes that generated HTML, not the original PHP. i.e. your server is going to send something like
<script>
function getdata()
{
var employee =
"hello world";
}
</script>
print them
So, as far as the web browser knows, "hello world" is just hardcoded there.
You'll need to look into AJAX for how to make it work. Check out this beginners' tutorial on using jQuery for ajax: http://www.devirtuoso.com/2009/07/beginners-guide-to-using-ajax-with-jquery/
Define a global variable
<script>
var employee = <?php echo "'" . $row['empnm'] "'";?>;
function getdata(){
return employee;
}
</script>
Now keep on changing variable employee whenever it is changed
print them
If you're in a PHP loop -- it does looks like you are, since -- you can use PHP to define the parameter to be passed into getdata() in your loop; e.g.
<script type="text/javascript">
function getdata(employee) {
// connect to database and get employee name
}
</script>
<?php
foreach ($loopData as $row) {
print 'print them';
}
?>

How do I run a function only when a div gets loaded?

I want to run a function only when a div gets loaded.
When I load the page, a number of files are loaded. At the end of the list, PHP echoes a div. When this one is displayed, jQuery should run a function.
I can do this with a click-event, but I want it to work automatically, without pushing a button.
This is how it works with a click:
$("#PP_end_show").live("click",function(){
$("#PP_head_bar").slideToggle("slow");
$("#PP_info_file_wrap").slideUp("slow");
});
This is the div echoed by PHP:
<?php echo "<div id=\"PP_end_show\"></div>"; ?>
The output is generated after an AJAX call:
<form id="PP_search_input" method="post" name="search_ID" ONSubmit="xmlhttpPost('PP_search_stream_client.php', 'PP_search_input', 'PP_thumb_output', '<img src=\'images/wait.gif\'>');return false; ">
<input name="search_string" type="text" class="PP_input" id="search_string" value="<?php echo $_POST['search_string']; ?>"/>
<button type="submit" class="PP_submit" id="search_submit"> search </button>
at the end of the generated output the specific div will be printed and should trigger the new jQuery function.
This is how I would tackle this issue, assuming I've understood it correctly in which the submission of the form PP_search_input, returns the html needed, in which then a the javascript code should be executed.
$('#PP_search_input').submit(function() {
$.ajax({
url: 'PP_search_stream_client.php',
type: 'post',
data: $(this).serialize(),
success: function(html) {
$(html).insertAfter('#whereToInsert') //change to however you want to insert the html
.find("#PP_head_bar").slideToggle("slow").end()
.find("#PP_info_file_wrap").slideUp("slow");
}
});
});
Try putting your javascript code inside the generated ajax code.
For example if your ajax is generated from the php code
<?php echo "<div id=\"PP_end_show\"></div>"; ?>
then try smth like this
<?php
echo "<div id=\"PP_end_show\"></div>";
echo '$(function(){$("#PP_head_bar").slideToggle("slow");';
echo '$("#PP_info_file_wrap").slideUp("slow");});';
?>
You could use the livequery plugin
You would then use it as follows :
$('#PP_end_show').livequery(function(){
$("#PP_head_bar").slideToggle("slow");
$("#PP_info_file_wrap").slideUp("slow");
});
The code in the function would execute when the element in the selector (#PP_end_show) was added to the DOM
Why not echo your javascript along with the DIV code?
You can use PHP to echo Javascript like this:
After your code:
<?php echo "<div id=\"PP_end_show\"></div>"; ?>
Write this:
echo "<script type='text/javascript'>
$('#PP_head_bar').slideToggle('slow');
$('#PP_info_file_wrap').slideUp('slow');
";
echo "</script>";
This should work.
In your JS, wrap the code you want to execute in a function. i.e.
function showInfoBlock() {
$("#PP_head_bar").slideToggle("slow");
$("#PP_info_file_wrap").slideUp("slow");
}
In your PHP, write out the JS needed to call that function after writing out the PP_end_show div. i.e.
<?php echo "<div id=\"PP_end_show\"></div><script>$(function() { showInfoBlock(); })();</script>"; ?>
This does what you are asking:
(function($){
var checkForEndInterval = window.setInterval(function(){
if ($('#PP_end_show').length) {
// stop interval
window.clearInterval(checkForEndInvertal);
// call your code now
$("#PP_head_bar").slideToggle("slow");
$("#PP_info_file_wrap").slideUp("slow");
}
},200);
})(jQuery);
However this is not a good idea because its silly and what you are asking for hints you not understanding but that is why you are here. Since you already know when your AJAX is called, call it explicitly and attach a success handler to it.
$.ajax({
/* your other setup code here */
success : function(data) {
// run your code
}
});
If you were not doing AJAX as you say, I would put a script tag at the end of your output and have it call your code as the simplest approach. Even still, you could use the jQuery.load method (not event) which by default executes JavaScript from your response.
Happy coding.
keep that jquery live-click-function as it is
& run the below code in php
<?php
echo "<div id=\"PP_end_show\"></div>";
echo "$(function(){ $(\"#PP_end_show\").click(); });";
?>
$.ready(function(){
$("#wrapper").add("div").attr('id','PP_end_show');
$("#PP_head_bar").slideToggle("slow");
$("#PP_info_file_wrap").slideUp("slow");
});
<div id='wrapper'>
</div>
Bind the live event to a custom event that is triggered by the document:
$(document).trigger('echo');
$("#PP_end_show").live("echo", function(){
$("#PP_head_bar").slideToggle("slow");
$("#PP_info_file_wrap").slideUp("slow");
});
References
jQuery API: .trigger()
JQuery API: .live()
Jason Brumwell enter right answer, also you can use the $.when function of JQuery.
http://api.jquery.com/jQuery.when/
If the action you want to perform once the desired div loads is bound to a click event, simply trigger click at the end of the ajax request something like:
$.ajax({
url:'whatever.php',
type:'post', //guessing obviously
success: function(data){
$('#PP_end_show').click(); //etc
}
});
These guys are right though, you are doing this all backwards mate
Does it have to be that exact div? It seems to me that you should just execute the function on load of the document. That way you know all your elements are loaded.
$(function()
{
// This function is executed when the DOM is ready, including that last div.
// Could be that images are still loading, but your code usually won't depend on that.
}
Try this,
if(window.isBodyLoaded){
try{
$("#PP_head_bar").slideToggle("slow");
$("#PP_info_file_wrap").slideUp("slow");
}catch(d){
alert(d)
}
}
Use a callback function.
Its a function that will be triggered as soon as your event is handled.
so for Jquery:
$("#PP_end_show").live("click",function(){
$("#PP_head_bar").slideToggle("slow");
$("#PP_info_file_wrap").slideUp("slow");
}, myCallback());
function myCallback(){
//Do what ever you want to happen after
//the div creationin this function
}
And I think that should do the trick

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