How to insert multiple inputs with same name in php through ajax - php

Question

I have html form that allowed to insert multiple input. I am able to insert only first input. How to insert multiple value in php passing through ajax, My HTML form is as below.
<tr>
<th>ID</th>
<td><input type="number" id="navid"></td>
</tr>
<tr>
<th>Menu IN</th>
<td><input type="text" name="menuin"></input></td>
</tr>
<tr>
<th>Menu ENG</th>
<td><input type="text" name="menueng"></input>
</td>
</tr>
User can add input field dynamically(dynamic add has be done by jquery)
It is not problem to pass if only one input group. But I want to pass multiple input if user add more than one.
And I've passed value as
$("#submit").click(function(){
var navid = $("#navid").val();
var menuin = $("input[name='menuin']").val();
var menueng = $("input[name='menueng']").val();
$.ajax({
url: 'insert_nav.php',
type: 'post',
data: {navid:navid,menuin:menuin,menueng:menueng},
success: function(data){
alert(data);
$('#nav')[0].reset();
}
});
});
I've inserted input values passed by ajax as below
if (isset($_POST["navid"]) && !empty($_POST["navid"])) {
$query1 =$con->prepare("INSERT INTO menu(cid, title, en_title) VALUES (:navid, :menuin, :menueng)");
$query1->bindParam(':menuin',$_POST["menuin"]);
$query1->bindParam(':menueng',$_POST["menueng"]);
$query1->bindParam(':navid', $_POST["navid"]);
$query1->execute();
$msg1 = 'Menu has inserted';
}
Now I want to insert multiple values. How to do ?

Answer 1

You have to apply array in input field for multiple input element. And pass array through ajax and insert to database using foreach loop.
HTML
<tr>
<th>ID</th>
<input type="number" name="navid[]" id="navid">
</tr>
<tr>
<th>Menu IN</th>
<td><input type="text" name="menuin[]"></input></td>
</tr>
<tr>
<th>Menu ENG</th>
<td><input type="text" name="menueng[]"></input>
</td>
</tr>
Ajax
$("#submit").click(function(){
var navid = [];
$('input[name="navid[]"]').each( function() {
navid.push(this.value);
});
var menuin = [];
$('input[name="menuin[]"]').each( function() {
menuin.push(this.value);
});
var menueng = [];
$('input[name="menueng[]"]').each( function() {
menueng.push(this.value);
});
$.ajax({
url: 'insert_nav.php',
type: 'post',
data: {navid:navid,menuin:menuin,menueng:menueng},
success: function(data){
alert(data);
$('#nav')[0].reset();
}
});
});
PHP
foreach ($_POST["navid"] AS $key => $item){
$query1 =$con->prepare("INSERT INTO menu(cid, title, en_title) VALUES (:navid, :menuin, :menueng)");
$query1->bindParam(':menuin',$_POST["menuin"][$key]);
$query1->bindParam(':menueng',$_POST["menueng"][$key]);
$query1->bindParam(':navid',$item);
$query1->execute();
$msg1 = 'Menu has inserted';
}

Answer 2

HTML:
<form id="the_form">
<tr>
<th>ID</th>
<td><input type="number" name="navid[]" id="navid"></td>
</tr>
<tr>
<th>Menu IN</th>
<td><input type="text" name="menuin[]"></input></td>
</tr>
<tr>
<th>Menu ENG</th>
<td><input type="text" name="menueng[]"></input>
</td>
</tr>
<input type="submit" value="Submit Form" id="submit"/>
</form>
I added a name for your ID so that it will be included when you submit the form, I just added a form tag since it was not present in your question.
JS:
Read about serialize
(https://stackoverflow.com/questions/15173965/serializing-and-submitting-a-form-with-jquery-post-and-php)
$("#submit").click(function(){
var form_data = $("#the_form").serialize();
$.ajax({
url: 'insert_nav.php',
type: 'post',
data: {form_data:form_data},
success: function(data){
alert(data);
$('#nav')[0].reset();
}
});
});
PHP
//Since the submitted data is now a collection of an array you'll have to loop through it to save them in the database as you cannot save an array directly in a DB.
if (!empty($_POST["navid"])) {
for($counter = 0; $counter < sizeof($_POST["navid"]); $counter++){
$query1 =$con->prepare("INSERT INTO menu(cid, title, en_title) VALUES (:navid, :menuin, :menueng)");
$query1->bindParam(':menuin',$_POST["menuin"][$counter]);
$query1->bindParam(':menueng',$_POST["menueng"][$counter]);
$query1->bindParam(':navid', $_POST["navid"][$counter]);
$query1->execute();
$msg1 = 'Menu has inserted';
}
}