Set input value upon select option in php - php

Question

I have a form where I am selecting a product. On the basis of the selected product, I want to update the rest of the fields in the form.
The Form display with select option
On selecting the product name, I want rest of the details of the form to fill up from the database using php.
Here is the code for the table created.
<table id="productTable" class="table-c">
<tr>
<th class="text-center" style="width: 5%;">SR No.</th>
<th class="text-center" style="width: 45%">DESCRIPTION</th>
<th class="text-center" style="width: 10%">HSN/SAC</th>
<th class="text-center" style="width: 10%">QTY IN-HAND</th>
<th class="text-center" style="width: 10%">ENTER OUTWARD QTY</th>
<th class="text-center" style="width: 5%">Delete</th>
</tr>
<tr style="text-align: center;" id="products">
<?php $j=0; $j++; ?>
<td><?php echo $j; ?></td>
<td><select class="form-control" name="code" id="productID" style="width: 429px;">
<?php
$sql = "SELECT * FROM `product`";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<option id='".$row['code']."' value='".$row['pname']."'>".$row['pname']."</option>";
}
} else {
echo "0 results";
}
?>
</select>
</td>
<td><input type="number" name="hsnNo" id="hsnNo" readonly></td>
<td><input type="number" name="qty" id="qty" readonly></td>
<td class="coljoin"><input type="number" format="2" name="amount"></td>
<td>
<span class="fa fa-trash"></span>
</td>
</tr>
</table>
How should I do this?

Answer 1

This is PHP Code:-
<form>
<select name="customer" id="customer_id">
<option value="">-- Select customer Name -- </option>
<option value="1">John</option>
<option value="2">Smith</option>
</select>
Address: <input name="add" type="text" value="">
Mobile: <input name="mobile" type="text" value="">
EMail-Id:<input name="email" type="text" value="">
</form>
This is JS Code:-
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<script>
$(document).ready(function() {
$("#customer_id").change(function() {
var id = $(this).val();
var dataString = 'cid='+id;
//alert(dataString);
$.ajax({
url: 'dataAjax.php',
type: 'post',
data: dataString,
success: function(response) {
// Parse the jSON that is returned
var Vals = JSON.stringify(response);
// These are the inputs that will populate
$("input[name='add']").val(Vals.add);
$("input[name='mobile']").val(Vals.mobile);
$("input[name='email']").val(Vals.email);
}
});
});
});
</script>
This is other PHP File Code:-
<?php
// This is where you would do any database call
if(!empty($_POST)) {
// Send back a jSON array via echo
echo json_encode(array("add"=>'India',"mobile"=>'1234567890','email'=>'demo#demo.com'));
}
?>

Answer 2

using product id use ajax & call the get_product_details(id) & in get product convert response array in json & echo it .in ajax, response data you have to parse in json... then set you required field.. (add require js)
**Ajax Call :**
$(document).on('change','your_dropdown_filed_id',function()
{
var product_id = $(this).val();
//Ajax call
$.ajax({
method: "POST",
url: "/get_product_details", //your php file function path
data: { product_id: product_id}
}).done(function( response ) {
alert( "Data Saved: " + response );
var obj = JSON.parse(response);
//obj hold all values
alert(obj.qty);
alert(obj.hsn);
$('#hsn_id').val(obj.hsn);
$('#qty_id').val(obj.qty);
});
});
**product.php**
function get_product_details(product_id)
{
//Get product details in associative array format
echo json_encode($product_details);
}

Answer 3

Once the product is selected execute ajax request and get data from the database with respective of the selected product.
JAVASCRIPT CODE :
$('#products').change(function(){
$.ajax({
url: 'your php code page name which returns product details.php?product_id'+$('#products').val(),
type: 'post',
success: function(response) {
var obj = JSON.parse(response);
$("#hsn_sac").val(obj.hsn_sac); // hsn or sac values
$("#qty_in_hand").val(obj.qty_in_hand); // qty_in_hand values
}
}});
});
PHP CODE :
<?php
// first connect database and then fire the query to get product details
$connection = mysql_connect("your database host name","database username","database password","database name");
$result = mysql_query("your query");
while ($row = mysql_fetch_array($result)) {
// get data and store in array
}
mysql_close($connection); // close connection
echo json_encode(database result); // encode database result so that it will available to ajax request and assign back to view
exit;
?>