I have tons of records that are in my database table leadactivity basically I need to display all the records that were created in the first week of the current month, then also another query to display records in the second week, same for third week and then finally the fourth week of the current month.
I have a column called created_date which onupdate puts in the current timestamp
What is the best way to achieve this?
You can use date functions for this:
select la.*
from leadactivity la
where day(la.created_date) between 1 and 7 and
created_date >= curdate() + (1 - day(curdate())) day;
The above assumes MySQL syntax. Most databases have similar functionality, although the specific functions may differ.
Related
I have a query that counts the "Xp" difference per day from my database, this all works as it should however it groups from midnight-midnight, what I would like to do is group 3am to 3am.
However another issue I think I may have is that my query may not always have the rows being the exact second at 3am due to the fact that it has to run a huge query and retrieve data from another website per user profile, so it should get all data after 3am, but before maybe 4am or something, so it has enough time to get all of the rows.
my current mysql is:
SELECT FROM_UNIXTIME(date, '%Y%m%d') AS YYYYMMDD, MAX(xp)-MIN(xp) AS xp_gain
FROM skills
WHERE userID = '$checkID'
AND skill = '$skill'
AND date >= '$date'
GROUP BY YYYYMMDD
ORDER BY date ASC
The best way to handle this is to add (if you can) another column that is just a DATE (not a DATETIME) and have this field rollover from one day to the next at 3am, (you can to this by subtracting 3 hours from the current time when doing the INSERT).
This gives you a couple of benefits, especially with a large number of rows:
It is much faster to query or group by a DATE than a range of
DATETIME
It will always query the rows at the exact second of 3am,
regardless of how long the query takes.
I have a database of events that are used to fill a PHP calender. I want to also have a page that lists three upcoming events in date order when ever the page loads. The records have a separate field for day, month and year. The issue i run in to is getting records that accrue after the current date.
Table structure will be good to have but I will guess the query that you need. Use that as a point to start from.
SELECT * FROM events WHERE CONCAT(year,'-',month,'-',date) > DATE_FORMAT(NOW(),'%Y-%m-%d')
ORDER BY year DESC, month DESC, date DESC LIMIT 3;
You are going to have to build a date from your three fields to test against current date, or split current date into year, month, day and test all three against data in your table.
Got to say, not a brill decision on someones part to split date like that.
Need table structure before we can properly help query wise.
How do you sort data which was stored in a mysql database depending on the days of the week in which the data was submited ??
I basically want to create a diary which outputs information in each day of the week depending on what day it was posted by dates so,
Mon - Data in order of date
Tue -
Wed - e.t.c
Any code examples and information will be great, thanks.
You can do a
SELECT DAYOFWEEK(datehere) as dayofweek, datehere FROM something ORDER BY dayofweek, datehere;
You can use the DAYOFWEEK function to extract the day, and then sort on it just like any other data.
What kinf of data type is the column where you store the date submission?
It seems like you're asking for a basic SELECT statement?
SELECT some_column, another_colum FROM your_table ORDER BY your_date_column DESC
This assumes you actually have a column that logs the insertion timestamp.
If this answer is obnoxiously simplistic, please forgive me...and give us more details :)
Regards.
If your data is stored as a DATE or DATETIME field, use the DAYOFWEEK or DATE_FORMAT functions to turn it into day name for output, but continue to order by the DATE field
SELECT DATE_FORMAT(my_date_column, '%W') AS dayofweek
FROM my_table
ORDER BY my_date_column
Well, the sorting bit is easy, just sort on the column that represents the post's date. The grouping in days is something you can do in your code, since you need to check the date there anyway (for post-processing the actual output).
To put it this way, you can do a subselect to get the specific day of the week, but in your code you would have to check the day again to group posts per day. In that case it's better (and cleaner, since you're separating business logic from data) to do this in your code, something like this:
select all posts (within date range)
make an associative array, with the
days as keys, and posts (in new
arrays) as values
loop through the
days and then posts to output the
posts per day
SELECT *
FROM diary_entries
ORDER BY FIELD(DAYOFWEEK(created), '2, 3, 4, 5, 6, 7, 1'), created
DAYOFWEEK grabs day of the week number (1 = Sunday).
FIELD makes Monday first day of the week.
After sorting by day of week, then sorted by date created.
how can i query my mysql database and fetch rows which are posted in earlier 3 days
i know how to fetch todays's rows but not 3 days ago
time will save in my table like this :
2010-01-20 19:17:49
and this is what i know :
SELECT id FROM pages WHERE date=now()
but i need to show posts in 3days
and im looking for a simple and straight solution ,because i know how to do so in long php codes
To get records three days in the past up to current time:
SELECT t.id
FROM PAGES t
WHERE t.date BETWEEN DATE_SUB(NOW(), INTERVAL 3 DAY) AND NOW()
This should select all entries with a date value after and including 3 days ago:
Select id From pages Where NOW() >= Interval date day + 3
Note that if there are dates in the future this will select them too.
Would be helpful to know what version of MySQL you're using and what column type we're talking about but here's the reference of Date and Time Functions for 5.1. You're going to probably want DATE_SUB().
I have a list of dates in a table in a MySQL database (the dates when a charity bookstall is to be held), which I want to display on a page. On one page I'm displaying the date of the next stall, and on another the dates of the stall in the next month. (Currently I'm using an unordered HTML list and selecting the dates with PHP, but it's a bit messy, and I also want to tie in the dates with the fundraising totals that are stored in the database).
I want to put the dates in a database though so that I can tie in the dates with the fundraising totals for each week. I'm thinking that once I can identify the date with the nearest up-coming date that I can use 'LIMIT 1' to select the next week's date for display, and 'LIMIT 4' say for where I need to display the dates for the next month, but what I can't figure out is how to identify the record with the nearest up-coming date - identifying the current date and then selecting the nearest date...I have a feeling there's probably one of the MySQL date functions that can be persuaded to help out in this, but can't figure out exactly how.
Any ideas on how I can do this?
If I understand correctly, you can just pick up next four dates that are after today.
In MySQL you could use the CURDATE() function for the 'today' bit, then apply an order and limit to your select statement. For example,
SELECT stall_date
FROM stall_dates
WHERE stall_date >= CURDATE() -- >= assumes you want today's to show too
ORDER BY
stall_date
LIMIT 4
Use ORDER BY stall_date DESC to reverse the ordering if needed.
If your column is a DATETIME field, you can identify the next by using SELECT...WHERE event_date > "2009-11-06" and ORDER BY event_date.
SELECT * FROM so_events
WHERE event_date > "2009-11-06 15:36:00"
ORDER BY event_date ASC
LIMIT 4
MySQL will internally do the work for you and select rows where whose timestamp is greater than the one you specify in the WHERE clause.