I have a database of events that are used to fill a PHP calender. I want to also have a page that lists three upcoming events in date order when ever the page loads. The records have a separate field for day, month and year. The issue i run in to is getting records that accrue after the current date.
Table structure will be good to have but I will guess the query that you need. Use that as a point to start from.
SELECT * FROM events WHERE CONCAT(year,'-',month,'-',date) > DATE_FORMAT(NOW(),'%Y-%m-%d')
ORDER BY year DESC, month DESC, date DESC LIMIT 3;
You are going to have to build a date from your three fields to test against current date, or split current date into year, month, day and test all three against data in your table.
Got to say, not a brill decision on someones part to split date like that.
Need table structure before we can properly help query wise.
Related
I want to do a query with thousands of tuples. I need to save the first ID, last ID and date saved in a historic table by day in a new table. I have data from 2020 to 2022. Every day could 600.000 rows or more. I have thought two solutions:
Doing a query every time with limit 600.000 and save the first id, last id and date, all of this order by dates or ids.
Doing a query day by day and get the first and the last id.
The problems are that these querys could delay so much because i am doing orderings.
I´m doing this with SQL and need execute this in PHP with a cron every day to save the data of the day. First, i´m building the new table with the data of past.
Someone would know one tip or antoher form to do this.
THANKS!
You can do this (result here)
select date, min(id) as min, max(id) as max
from logs
group by date
What I am trying to do here is render a report for each date in the current month from a MYSQL table.
I have a table with rows in, which a lot have the same date. As you can see here
What I would like to do is for every date in the current month is see how many rows have been found in the MYSQL table for that date and then return it into an array. The final product will be a multidimensional array for every date in the current month. Something like this
array("dates"=>
array(
"1 feb"=>2, //the number of rows for that date found in the MYSQL table
"2 feb"=>8,
"3 feb"=>0
)
)
But the issue is I wouldn't have a clue where to start with the coding, like what PHP functions would I use? So I was hoping someone could push me in the right direction :)
Probably not working code but should point you in the right direction:
SELECT
SUM(money) AS sum,
`date`
FROM
money_table
WHERE
MONTH(`date`) = 2
GROUP BY
DAY(`date`)
Reference
GROUP BY
MONTH
DAY
You said you didn't have a table with all the dates. If you did, this would be trivial. Let's say you had such a table called calendar.
select calendardate
, ifnull(sum(money), 0) sum_of_money
from calendar left join money on calendardate = money.date
where calendardate >= {d '2013-02-01'}
and calendardate < {d '2013-03-01'}
group by calendardate
Other things that could be stored in the calendar table are fiscal information and holidays. It might be worth your while to create and maintain one.
I'm looking for an efficient way to collate all blog posts into a menu of the following format:
2012
August(6)
September(4)
October(2)
Month representing the month(obviously), and the value inside the brackets representing the number of posts in that month. Once clicked, a search will then be made for all posts in that month, in that year.
I need it to be dynamic, picking up November automatically when a post is created in that month, and carrying on into December, into 2013 etc etc...
All I have is a UNIX timestamp for each post. I would really like to avoid using seperate functions to gather endless comlex arrays etc.
Any help much appreciated.
From your question, I understand you're trying to come up with a query to group a number of elements by month and year. The following should do the trick:
SELECT
YEAR(dateField) AS YEAR,
MONTH(dateField) AS MONTH,
COUNT(*) AS TOTAL
FROM table
GROUP BY YEAR, MONTH
Obviously, "dateField" being the name of your datetime/timestamp column and "table" being the name of your table.
More information on the GROUP BY clause and aggregate functions (such as the COUNT(*) function used above) here.
How do you sort data which was stored in a mysql database depending on the days of the week in which the data was submited ??
I basically want to create a diary which outputs information in each day of the week depending on what day it was posted by dates so,
Mon - Data in order of date
Tue -
Wed - e.t.c
Any code examples and information will be great, thanks.
You can do a
SELECT DAYOFWEEK(datehere) as dayofweek, datehere FROM something ORDER BY dayofweek, datehere;
You can use the DAYOFWEEK function to extract the day, and then sort on it just like any other data.
What kinf of data type is the column where you store the date submission?
It seems like you're asking for a basic SELECT statement?
SELECT some_column, another_colum FROM your_table ORDER BY your_date_column DESC
This assumes you actually have a column that logs the insertion timestamp.
If this answer is obnoxiously simplistic, please forgive me...and give us more details :)
Regards.
If your data is stored as a DATE or DATETIME field, use the DAYOFWEEK or DATE_FORMAT functions to turn it into day name for output, but continue to order by the DATE field
SELECT DATE_FORMAT(my_date_column, '%W') AS dayofweek
FROM my_table
ORDER BY my_date_column
Well, the sorting bit is easy, just sort on the column that represents the post's date. The grouping in days is something you can do in your code, since you need to check the date there anyway (for post-processing the actual output).
To put it this way, you can do a subselect to get the specific day of the week, but in your code you would have to check the day again to group posts per day. In that case it's better (and cleaner, since you're separating business logic from data) to do this in your code, something like this:
select all posts (within date range)
make an associative array, with the
days as keys, and posts (in new
arrays) as values
loop through the
days and then posts to output the
posts per day
SELECT *
FROM diary_entries
ORDER BY FIELD(DAYOFWEEK(created), '2, 3, 4, 5, 6, 7, 1'), created
DAYOFWEEK grabs day of the week number (1 = Sunday).
FIELD makes Monday first day of the week.
After sorting by day of week, then sorted by date created.
I have a list of dates in a table in a MySQL database (the dates when a charity bookstall is to be held), which I want to display on a page. On one page I'm displaying the date of the next stall, and on another the dates of the stall in the next month. (Currently I'm using an unordered HTML list and selecting the dates with PHP, but it's a bit messy, and I also want to tie in the dates with the fundraising totals that are stored in the database).
I want to put the dates in a database though so that I can tie in the dates with the fundraising totals for each week. I'm thinking that once I can identify the date with the nearest up-coming date that I can use 'LIMIT 1' to select the next week's date for display, and 'LIMIT 4' say for where I need to display the dates for the next month, but what I can't figure out is how to identify the record with the nearest up-coming date - identifying the current date and then selecting the nearest date...I have a feeling there's probably one of the MySQL date functions that can be persuaded to help out in this, but can't figure out exactly how.
Any ideas on how I can do this?
If I understand correctly, you can just pick up next four dates that are after today.
In MySQL you could use the CURDATE() function for the 'today' bit, then apply an order and limit to your select statement. For example,
SELECT stall_date
FROM stall_dates
WHERE stall_date >= CURDATE() -- >= assumes you want today's to show too
ORDER BY
stall_date
LIMIT 4
Use ORDER BY stall_date DESC to reverse the ordering if needed.
If your column is a DATETIME field, you can identify the next by using SELECT...WHERE event_date > "2009-11-06" and ORDER BY event_date.
SELECT * FROM so_events
WHERE event_date > "2009-11-06 15:36:00"
ORDER BY event_date ASC
LIMIT 4
MySQL will internally do the work for you and select rows where whose timestamp is greater than the one you specify in the WHERE clause.