I've started developing a project and I need use a advanced search query with PHP and Mysqli, but I'm getting some troubles. Check out below my query.
$query = "SELECT id, name, keybox, posterid, alias, xmdb from `datasys` WHERE name LIKE '%".$filter."%' OR keybox LIKE '%".$filter."%' ORDER BY id LIMIT 0, 10";
It's working perfeclty! But still not matching entries that contains symbols, for example, if my database contains a row called "Color: red" and someone type "Color red", the query will return empty, but if I type "Color: red" returns found. So, what should I do to resolve this issue?
Thanks
Either use the REGEXP as:-
SELECT * FROM table WHERE columnName REGEXP "regular_expression";
or use REPLACE() function in WHERE clause as:-
SELECT * FROM table WHERE REPLACE(columnName, ":", "") LIKE "like_expression";
The one thing that I can think of in order to maintain consistency is that you can eliminate the ':' in your query for matching. Try the below query:
$query = "SELECT id, name, keybox, posterid, alias, xmdb from `datasys` WHERE REPLACE(name, ':', '') LIKE '%REPLACE(".$filter.", ':', '')%' OR REPLACE(keybox, ':', '') LIKE '%REPLACE(".$filter.", ':', '')%' ORDER BY id LIMIT 0, 10";
Hope this helps.
Use two queries to find exact and similar records.
If the records available in Exact data query then no need to run the similar data query
<?php
//Fetches Exact Data
$query = "SELECT id, name, keybox, posterid, alias, xmdb from `datasys` WHERE name LIKE '%".$filter."%' OR keybox LIKE '%".$filter."%' ORDER BY id LIMIT 0, 10";
//If the previous query doesn't return any value, then use
//Split the the user input and then query DB
$condition="name!=''";
$filters=explode(" ",$filter);
foreach($filters as $val)
{
$condition.=" or (name LIKE '%$val%' OR keybox LIKE '%$val%')";
}
//Fetches Similar Data
$query = "SELECT id, name, keybox, posterid, alias, xmdb from `datasys` WHERE $condition ORDER BY id LIMIT 0, 10";
//-----------ENDS
?>
Related
i have a small problem. I use two mysql queries for getting data.
First i want to get IDs from groups
$sqlGoups = "SELECT * from `groups` WHERE `Date`='$TodayDate' ";
$result = $conn->query($sqlGoups);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$IDgroups = $row["ID"];
With that, I'll get those IDs, for example 5, 7, 12, 15, 22
I want to put them all in the next mysql query:
$sqlNext = "SELECT * FROM `orders` WHERE ID = '$IDgroups' ORDER BY `ID` ASC ";
$result = $conn->query($sqlNext);
When I do this, I get the result only for the first ID (5). And I want for each
I can not INNER JOIN tables because I use this in next query.
I tried with foreach loop, but no effect.
Try this code
SELECT * FROM `orders`
WHERE ID REGEXP CONCAT('(^|,)(', REPLACE('$IDgroups', ',', '|'), ')(,|$)')
ORDER BY `ID` ASC
Just like #Elanochecer commented the best bet should be a JOIN statement, but if you wish to go through your route, you could use the IN and provide the IDs as comma separated string, your query should look similar to the one below:
...
$sqlNext = "SELECT * FROM orders WHERE ID IN ('$IDgroups') ORDER BY ID ASC ";
...
Also, confirm if $IDgroups is in the format 1,2,3,4
If you provide the schema I could come up with a workable JOIN statement for you, preferably you can create a repo with the schema
So I've been stuck on this for a while and I can't find anything on google for this specific thing.
I have this small snippet of code
$link = mysqli_connect("localhost", 'username','password',"database");
$sql = "SELECT * FROM `uploads` ORDER BY id DESC LIMIT 0, 1";
Which should select the latest table by order of id's right?
Well what I want to do is return this id. So if I have 5 items/rows I want to grab the latest (5 in this case) id of the table, and return it. With the eventual goal of using this returned id in javascript but that's a worry for later, right now I just want it in plaintext where the result should only be the id.
This is probably a duplicate question but I can't for the life of me find what I should google to get there
EDIT:
I guess I should clarify further. I know I'm able to do
$sql = "SELECT ID FROM `uploads` ORDER BY id DESC LIMIT 0, 1";
but whenever I try to actually retrieve it/print it its returned as a string instead of the ID.
EDIT 2: I, thanks to some comments, have managed to figure it out. Sorry for the badly worded everything, I'm new to this and as I said don't know how to word it.
SOLUTION:
After just throwing away the $sql thing I added:
$result = mysqli_query($link,"SELECT * FROM `uploads`");
Then I simply did
echo mysqli_num_rows($result);
To echo out the number of rows/what I called the "ID".
Sorry for all the confusion, thanks to those that tried to help. To the others there's no need to be rude.
If I understood your question correctly, you want to get the ID field only, so you have two options:
Option 1 (Recommended)
Given your code
$sql = "SELECT * FROM `uploads` ORDER BY id DESC LIMIT 0, 1";
Change it to:
$sql = "SELECT ID FROM `uploads` ORDER BY id DESC LIMIT 0, 1";
This way, your getting just that ID field you're after. Nothing else is returned from each row.
Option 2
Keep your sql query as it is, and get the ID field from each row in your results (it's an array, so you can retrieve only one field by using its index or name).
Of course, I assume there's an ID field in your table!
Just select the ID.
SELECT id
FROM uploads
ORDER BY id DESC
LIMIT 1;
Simply select what you want.
$sql = "SELECT id FROM `uploads` ORDER BY id DESC LIMIT 0, 1";
The * means you want to select every column there is. However, SQL gives you the possibility to select the specific columns you want. You could also do something like
$sql = "SELECT id, name, title, somethingelse FROM `uploads` ORDER BY id DESC LIMIT 0, 1";
and you'd receive these 4 fields as an array.
I'm trying to call a random row from a table where the column "activePages" features a certain id number.
For example, activePages might contain "123 456" on one row, "456 789" on another and I use the following code:
SELECT * FROM advertising WHERE activePages LIKE %456% ORDER BY rand() LIMIT 1
...To call one of those two rows at random.
I want to do this same thing, but with a variable in place of "456". Where do I need to put the % for this to work? Or am I missing another problem entirely?
This is what I have right now:
$getad = $pdo->prepare('SELECT * FROM advertising WHERE activePages LIKE :id ORDER BY rand() LIMIT 1');
$getad->execute(['id' => $id]);
You can use this sort of CONCAT() construct.
WHERE COLUMN LIKE concat('%', :id, '%')
You can put anything you need into CONCAT(), so it's quite flexible.
Wrote a quick test to verify some other posts on SO. Adding the % to the PHP variable works for the like comparison.
<?php
$id = "%" . $searchTerm . "%";
$sql = "SELECT * FROM TABLE
WHERE COLUMN LIKE :id";
$stmt->execute([':id'=> $id]);
?>
I am retrieving data from a database with php and MySQL as follows
$query = mysql_query("SELECT * FROM pictures WHERE (title LIKE '%$Search%' OR keywords LIKE '%$Search%') AND approved = 'YES' ORDER BY title ASC");
The query is correct and there are no errors and the query works fine for "title LIKE '%$Search%'" but the parameter "OR keywords LIKE '%$Search%'" is not retrieving data. The parameter "AND" also works correctly.
The keywords are stored in the database for example "pizza, restaurants, take away" but I don't see that is a problem.
My question is "What is the correct syntax for applying the "OR" parameter?
Remove the brackets around (title LIKE '%$Search%' OR keywords LIKE '%$Search%')
Those are generally used for subqueries.
$query = mysql_query("
SELECT * FROM pictures
WHERE title LIKE '%$Search%'
OR keywords LIKE '%$Search%'
AND approved = 'YES'
ORDER BY title ASC
");
https://dev.mysql.com/doc/refman/5.0/en/subqueries.html
Here is an example of a subquery, and pulled from the manual on MySQL.com:
SELECT * FROM t1 WHERE column1 = (SELECT column1 FROM t2);
Edit:
Or try a different quoting method:
$query = mysql_query("
SELECT * FROM pictures
WHERE title LIKE '".%$Search%."'
OR keywords LIKE '".%$Search%."'
AND approved = 'YES'
ORDER BY title ASC
");
You could also try escaping your data:
$Search = mysql_real_escape_string($Search);
as an example. I don't know how you're assigning that variable.
phpMyAdmin test edit:
This is what I used inside phpMyAdmin:
SELECT * FROM table
WHERE col1 LIKE '%pizza%'
OR col2 LIKE '%pizza%'
AND col3 = 'YES'
ORDER BY col1 ASC
using pizza as the search keyword seeing that $Search will be based on the same keyword for you, where columns contain "large pizza" in one, and "pizza, take away, restaurants" in another.
Remember that, whatever you're using/assigning $Search to, must reside inside all your queried columns.
You may also want to make use of explode().
Here is an example pulled from https://stackoverflow.com/a/15289777/
<?php
$search = 'Gold Chain Shirt';
$bits = explode(' ', $search);
$sql = "SELECT name FROM product WHERE name LIKE '%" . implode("%' OR name LIKE '%", $bits) . "%'";
The above will generate this query:
SELECT name FROM product WHERE name LIKE '%Gold%' OR name LIKE '%Chain%' OR name LIKE '%Shirt%'
Sorry for taking some time but this is my working answer to my own question... not the prettiest syntax but it works without any string functions or explode functions. MySql can handle keywords quite well without any other functions being included:
$query = mysql_query("SELECT * FROM pictures
WHERE
title LIKE '%$Search%' AND featured IS NOT NULL AND streetview IS NOT NULL AND (id_user > '1') AND (status = '1')
OR
keywords LIKE '%$Search%' AND featured IS NOT NULL AND streetview IS NOT NULL AND (id_user > '1') AND (status = '1') ORDER BY title ASC");
Thank you all for your contributions
I am trying to do a query in PHP PDO where it will grab a simple result. So like in my query I need it to find the row where the column group is 'Admin' and show what ever is in the group column. I know that we already know what it should be [Should be admin] but just need to get the query to work. Its only grabbing 1 row from my table, so will I need forsearch?
If I change WHERE group = 'Admin' to WHERE id = '1' it works fine. But I need it so it can be where group = 'admin'
$sql2 = "SELECT * FROM groups WHERE group = 'Admin'";
$stm2 = $dbh->prepare($sql2);
$stm2->execute();
$users2 = $stm2->fetchAll();
foreach ($users2 as $row2) {
print ' '. $row2["group"] .' ';
}
Thanks
group is a reserved word in MySQL, that's why it's not working. In general it's a bad idea to use reserved words for your column and table names.
Try using backticks around group in your query to get around this, so:
$sql2 = "SELECT * FROM groups WHERE `group` = 'Admin'";
Also you should really use placeholders for values, because you're already using prepared statement it's a small change.
Edit: just to clarify my last remark about the placeholders. I mean something like this:
$sql2 = "SELECT * FROM groups WHERE `group` = ?";
$stm2->execute(array('Admin'));
try to use wildcard in your WHERE Clause:
$sql2 = "SELECT * FROM groups WHERE group LIKE '%Admin%'";
Since the value in your table is not really Admin but Administrator then using LIKE and wildcard would search the records which contains admin.